91影视

The claim states that the mean of data speeds is $渭=14.00\text{mbps}$

The sample size is $n=13$with the test statistic $t=-1.625$.

As per the claim, the hypotheses are stated as follows.

$$\begin{gathered} H_0:渭=14(\text{null}\text{hypothesis}) \\ {H}_1:渭鈮�14(\text{alternative}\text{hypothesis}\text{and}\text{original}\text{claim}) \end{gathered}$$

Hence, it is a two-tailed test.

The degrees of freedom for the given set of data are as follows.

$$\begin{gathered} df=n-1 \\ =13-1 \\ =12 \end{gathered}$$

The test is a two-tailed with 12 degrees of freedom and test statistic value of

-1.625.

In Table A-3, check for the value 1.625 in the row with 12 degrees of freedom to see test statistic. The value 1.625 lies between 1.356 and 1.782.

The corresponding two-tailed area indicates the P-value between 0.10 and 0.20.

Hence, this can be written as $0.10<P-value<0.20$

Thus, the range ofp-value is 0.10 and 0.20.