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A set of eight multiple-choice questions are answered in the SAT. The probability of a correct answer is given to be equal to 0.20.

Let X denote the number of correct answers.

Thus, the number of trials (n) is given to be equal to eight.

The probability of success (getting a correct answer) is p= 0.20.

The probability of failure (getting a wrong answer) is calculated below:

$$\begin{gathered} q=1-p \\ =1-0.20 \\ =0.80 \end{gathered}$$

The number of successes required in eight trials should be x=0.

The binomial probability formula is as follows:

$P\left(X=x\right)={}^n{C}_x{\left(p\right)}^x{\left(q\right)}^{n-x}$

By using the binomial probability formula, the probability of getting no correct answer is computed below:

$$\begin{gathered} P\left(X=0\right)={}^8{C}_0{\left(0.20\right)}^0{\left(0.80\right)}^{8-0} \\ =\frac{8!}{0!\left(8-0\right)!}脳\left(0.20\right)脳{\left(0.80\right)}^8 \\ =0.167772 \\ 鈮�0.168 \end{gathered}$$

Therefore, the probability of getting no correct answers is equal to 0.168.