91影视

The 11 observations for jersey numbers are 89, 91, 55, 7, 20, 99, 25, 81, 19, 82, and 60.

(a).

The formula for mean is stated as follows:

$\stackrel{炉}{x}=\frac{鈭�x}{n}$, where xrepresents the observations and nis the count of the observations.

The number of observations (n) is11.

Substitute the values in the formula.

$$\begin{gathered} \stackrel{炉}{x}=\frac{89+91+...+60}{11} \\ =\frac{628}{11} \\ =57.0909 \\ 鈮�57.1 \end{gathered}$$

Thus, the mean value is approximately 57.1.

(b).

The formula for the median is stated as follows:

• If n is odd, the middlemost observation is the median.
• If n is even, the average of the two middle observations is the median.

Arrange the observations in ascending order.

7,19,20,25,55,60,81,82,89,91,99

The middlemost observation is 60.

The median is given as:

$M=60$

Thus, the median is 60.0.

(c).

Mode is the observation with the highest frequency.

Since all observations are repeated once, there is no mode.

(d).

The formula for midrange is stated as:

$\text{Midrange}=\frac{\text{Minimum}\text{value}+\text{Maximum}\text{value}}{2}$

Substitute the values in the formula.

$$\begin{gathered} \text{Midrange}=\frac{\text{7}+\text{99}}{2} \\ =\frac{106}{2} \\ =53 \end{gathered}$$

Thus, the midrange is 53.0.

The data records jersey numbers of 11 players, which can be categorized as nominal scaled data. Measures like mean, median, and midrange do not make any sense.

On the other hand, mode reveals the categorical value that repeats the maximum number of times. In this case, there is no modal value. Thus, there is no such jersey number that repeats itself.