/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q18BSC Testing for a Linear Correlation... [FREE SOLUTION] | 91影视

91影视

Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

CSI Statistics Use the paired foot length and height data from the preceding exercise. Is there sufficient evidence to conclude that there is a linear correlation between foot lengths and heights of males? Based on these results, does it appear that police can use foot length to estimate the height of a male?

Shoe print(cm)

29.7

29.7

31.4

31.8

27.6

Foot length(cm)

25.7

25.4

27.9

26.7

25.1

Height (cm)

175.3

177.8

185.4

175.3

172.7

Short Answer

Expert verified

The scatter plot is shown below:

The value of the correlation coefficient is 0.826.

The p-value is 0.085.

There is not enough evidence to support the claim of alinear correlation between foot length and height of males.

As two variables are not linearly associated and the scatter plot does not indicate a clear non-linear trend, the foot length cannot be used to predict the height of males.

Step by step solution

01

Given information

Refer to Exercise 17 for the data onshoe print, foot length, and height of males.

Shoe print(cm)

29.7

29.7

31.4

31.8

27.6

Foot length(cm)

25.7

25.4

27.9

26.7

25.1

Height (cm)

175.3

177.8

185.4

175.3

172.7

02

Sketch a scatterplot

Paired values are obtainedon a graph with two axes scaled according to the variables.

Steps to sketch a scatterplot:

  1. Mark horizontal axis for footlengthand vertical axis for the height of males.
  2. Mark each of the points on the graph.
  3. The resultant graph is the scatterplot.

03

Compute the measure of the correlation coefficient

The formula for correlation coefficient is

\(r = \frac{{n\sum {xy} - \left( {\sum x } \right)\left( {\sum y } \right)}}{{\sqrt {n\left( {\sum {{x^2}} } \right) - {{\left( {\sum x } \right)}^2}} \sqrt {n\left( {\sum {{y^2}} } \right) - {{\left( {\sum y } \right)}^2}} }}\).

Let foot lengthbe defined by variable x and heights of males be defined by variable y.

The valuesare listed in the table below:

x

y

\({x^2}\)

\({y^2}\)

\(xy\)

25.7

175.3

660.49

30730.09

4505.21

25.4

177.8

645.16

31612.84

4516.12

27.9

185.4

778.41

34373.16

5172.66

26.7

175.3

712.89

30730.09

4680.51

25.1

172.7

630.01

29825.29

4334.77

\(\sum x = 130.8\)

\(\sum y = 886.5\)

\(\sum {{x^2}} = 3426.96\)

\(\sum {{y^2} = } \;157271.5\)

\(\sum {xy\; = \;} 23209.27\)

Substitute the values in the formula:

\(\begin{aligned} r &= \frac{{5\left( {23209.27} \right) - \left( {130.8} \right)\left( {886.5} \right)}}{{\sqrt {5\left( {3426.96} \right) - {{\left( {130.8} \right)}^2}} \sqrt {5\left( {157271.5} \right) - {{\left( {886.5} \right)}^2}} }}\\ &= 0.826\end{aligned}\)

Thus, the correlation coefficient is 0.826.

04

Step 4:Conduct a hypothesis test for correlation

Define\(\rho \)as the correlation coefficient for the population of two variables, foot lengths and height of males.

For testing the claim, form the hypotheses:

\(\begin{array}{l}{H_o}:\rho = 0\\{H_a}:\rho \ne 0\end{array}\)

The samplesize is 5 (n).

The test statistic is computed as follows:

\(\begin{aligned} t &= \frac{r}{{\sqrt {\frac{{1 - {r^2}}}{{n - 2}}} }}\\ &= \frac{{0.826}}{{\sqrt {\frac{{1 - {{0.826}^2}}}{{5 - 2}}} }}\\ &= 2.538\end{aligned}\)

Thus, the test statistic is 2.538.

The degree of freedom is

\(\begin{aligned} df &= n - 2\\ &= 5 - 2\\ &= 3.\end{aligned}\)

The p-value is computed from the t-distribution table.

\(\begin{aligned} p{\rm{ - value}} &= 2P\left( {T > t} \right)\\ &= 2P\left( {T > 2.538} \right)\\ &= 2\left( {1 - P\left( {T < 2.538} \right)} \right)\\ &= 0.085\end{aligned}\)

Thus, the p-value is 0.085.

Since the p-value is greater than 0.05, the null hypothesis fails to berejected.

Therefore, there is not enough evidence to conclude that foot length and height have a linear correlation between them.

05

Analyze if the foot length can help predict the height of males

From the above result, the variables foot lengths and height of males are not linearly correlated. On the other hand, the scatterplot shows an upward trend but no specific pattern (linear or non-linear).

Thus, the foot lengths cannot be used to predict heights.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Interpreting\({R^2}\)For the multiple regression equation given in Exercise 1, we get \({R^2}\)= 0.928. What does that value tell us?

Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Sports Diameters (cm), circumferences (cm), and volumes (cm3) from balls used in different sports are listed in the table below. Is there sufficient evidence to conclude that there is a linear correlation between diameters and circumferences? Does the scatterplot confirm a linear association?


Diameter

Circumference

Volume

Baseball

7.4

23.2

212.2

Basketball

23.9

75.1

7148.1

Golf

4.3

13.5

41.6

Soccer

21.8

68.5

5424.6

Tennis

7

22

179.6

Ping-Pong

4

12.6

33.5

Volleyball

20.9

65.7

4780.1

Softball

9.7

30.5

477.9

Finding a Prediction Interval. In Exercises 13鈥16, use the paired data consisting of registered Florida boats (tens of thousands) and manatee fatalities from boat encounters listed in Data Set 10 鈥淢anatee Deaths鈥 in Appendix B. Let x represent number of registered boats and let y represent the corresponding number of manatee deaths. Use the given number of registered boats and the given confidence level to construct a prediction interval estimate of manatee deaths.

Boats Use x = 85 (for 850,000 registered boats) with a 99% confidence level.

Stocks and Sunspots. Listed below are annual high values of the Dow Jones Industrial Average (DJIA) and annual mean sunspot numbers for eight recent years. Use the data for Exercises 1鈥5. A sunspot number is a measure of sunspots or groups of sunspots on the surface of the sun. The DJIA is a commonly used index that is a weighted mean calculated from different stock values.

DJIA

14,198

13,338

10,606

11,625

12,929

13,589

16,577

18,054

Sunspot

Number

7.5

2.9

3.1

16.5

55.7

57.6

64.7

79.3

Hypothesis Test The mean sunspot number for the past three centuries is 49.7. Use a 0.05 significance level to test the claim that the eight listed sunspot numbers are from a population with a mean equal to 49.7.

Cigarette Nicotine and Carbon Monoxide Refer to the table of data given in Exercise 1 and use the amounts of nicotine and carbon monoxide (CO).

a. Construct a scatterplot using nicotine for the xscale, or horizontal axis. What does the scatterplot suggest about a linear correlation between amounts of nicotine and carbon monoxide?

b. Find the value of the linear correlation coefficient and determine whether there is sufficient evidence to support a claim of a linear correlation between amounts of nicotine and carbon monoxide.

c. Letting yrepresent the amount of carbon monoxide and letting xrepresent the amount of nicotine, find the regression equation.

d. The Raleigh brand king size cigarette is not included in the table, and it has 1.3 mg of nicotine. What is the best predicted amount of carbon monoxide?

Tar

25

27

20

24

20

20

21

24

CO

18

16

16

16

16

16

14

17

Nicotine

1.5

1.7

1.1

1.6

1.1

1.0

1.2

1.4

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.