/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13BSC Exercises 13鈥28 use the same d... [FREE SOLUTION] | 91影视

91影视

Exercises 13鈥28 use the same data sets as Exercises 13鈥28 in Section 10-1. In each case, find the regression equation, letting the first variable be the predictor (x) variable. Find the indicated predicted value by following the prediction procedure summarized in Figure 10-5 on page 493.

Internet and Nobel Laureates Find the best predicted Nobel Laureate rate for Japan, which has 79.1 Internet users per 100 people. How does it compare to Japan鈥檚 Nobel Laureate rate of 1.5 per 10 million people?

Short Answer

Expert verified

The regression equation is\(\hat y = - \;8.44 + 0.203x\).

Thebest predicted Nobel laureate rate for Japan, which has 79.1 internet users per 100 people, will be approximately 5.1 per 10 million people.

The predicted value is not very close to the given value of 1.5 per 10 million people.

Step by step solution

01

Given information

The given data depicts the number of internet users and Nobel laurates (per 10 million people).

02

State the equation for the estimated regression line

The formula for the estimated regression line is

\(\hat y = {b_0} + {b_1}x\),

where

\({b_0}\)is the y-intercept,

\({b_1}\)is the slope estimate,

\(x\)is the explanatory variable, and

\(\hat y\)is the response variable (predicted value).

Let X denote the number of internet users and Y denote the number of Nobel laureates.

03

Compute the slope and intercept estimates

The calculations required to compute the slope and intercept are as follows.

The number of observations in the sample are \(\left( n \right) = 6\).

The slope is computed as

\(\begin{array}{c}{b_1} = \frac{{n\left( {\sum {xy} } \right) - \left( {\sum x } \right)\left( {\sum y } \right)}}{{n\left( {\sum {{x^2}} } \right) - {{\left( {\sum x } \right)}^2}}}\\ = \frac{{6 \times 2301.16 - 399.7 \times 30.4}}{{6 \times 27987.71 - {{399.7}^2}}}\\ = 0.2028\end{array}\).

The intercept is computed as

\(\begin{array}{c}{b_0} = \frac{{\left( {\sum y } \right)\left( {\sum {{x^2}} } \right) - \left( {\sum x } \right)\left( {\sum {xy} } \right)}}{{n\left( {\sum {{x^2}} } \right) - {{\left( {\sum x } \right)}^2}}}\\ = \frac{{30.4 \times 27987.71 - 399.7 \times 2301.16}}{{6 \times 27987.71 - {{399.7}^2}}}\\ = - 8.4430\end{array}\).

Thus, the estimated regression equation is

\(\begin{array}{c}\hat y = {b_0} + {b_1}x\\ = - 8.44 + 0.203x\end{array}\).

04

Checking the model

Refer to exercise 21 of section 10-1 for the following result.

1) The scatter plot does not show an approximate linear relationship between the variables.

2) The P-value is 0.056.

As the P-value is greater than the level of significance (0.05), the null hypothesis is failed to be rejected.

Therefore, the correlation is not significant.

Referring to figure 10-5, the criteria for a good regression model is not satisfied.

Therefore, the regression equation cannot be used to predict the value of y.

For bad models, the best-predicted value of a variable is simply its sample mean of response variables.

05

Compute the prediction

The best-predicted number of Nobel laureate rate for Japan, which has 79.1 internet users per 100 people, is the sample mean of the response variable.

The sample meanis computed as

\(\begin{array}{c}\bar y = \frac{{\sum y }}{n}\\ = \frac{{\left( {5.5 + 9 + ... + 0.1} \right)}}{6}\\ = 5.1\end{array}\).

Therefore, the best predicted Nobel laureate rate for Japan, which has 79.1 internet users per 100 people, will be approximately 5.1per 10 million people.

The Nobel laureate rate of 1.5 per 10 million people is not close enough to the predicted value of 5.1 per 10 million people.

Thus, the two values are not comparable.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following exercises are based on the following sample data consisting of numbers of enrolled students (in thousands) and numbers of burglaries for randomly selected large colleges in a recent year (based on data from the New York Times).

Repeat the preceding exercise, assuming that the linear correlation coefficient is r= 0.997.

In Exercises 5鈥8, we want to consider the correlation between heights of fathers and mothers and the heights of their sons. Refer to the

StatCrunch display and answer the given questions or identify the indicated items.

The display is based on Data Set 5 鈥淔amily Heights鈥 in Appendix B.

A son will be born to a father who is 70 in. tall and a mother who is 60 in. tall. Use the multiple regression equation to predict the height of the son. Is the result likely to be a good predicted value? Why or why not?

Interpreting the Coefficient of Determination. In Exercises 5鈥8, use the value of the linear correlation coefficient r to find the coefficient of determination and the percentage of the total variation that can be explained by the linear relationship between the two variables.

Bears r = 0.783 (x = head width of a bear, y = weight of a bear)

In Exercises 5鈥8, we want to consider the correlation between heights of fathers and mothers and the heights of their sons. Refer to the

StatCrunch display and answer the given questions or identify the indicated items.

The display is based on Data Set 5 鈥淔amily Heights鈥 in Appendix B.

Identify the following:

a. The P-value corresponding to the overall significance of the multiple regression equation

b. The value of the multiple coefficient of determination\({R^2}\).

c. The adjusted value of \({R^2}\)

In Exercises 5鈥8, use a significance level 0.05 and refer to theaccompanying displays.Cereal Killers The amounts of sugar (grams of sugar per gram of cereal) and calories (per gram of cereal) were recorded for a sample of 16 different cereals. TI-83>84 Plus calculator results are shown here. Is there sufficient evidence to support the claim that there is a linear correlation between sugar and calories in a gram of cereal? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.