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Chapter 12: Q1RE (page 566)

Speed Dating Data Set 18 鈥淪peed Dating鈥� in Appendix B lists attribute ratings of females by males who participated in speed dating events, and some of those values are included in the table on the top of the next page. Analysis of variance is used with the values in that table, and the StatCrunch results are shown on the next page following the data. Use a 0.05 significance level to test the claim that males in the different age brackets give attribute ratings with the same mean. Does age appear to be a factor in the male attribute ratings?


Age 20-22

32

34

37

40.5

33

28

31

50

39

41

Age 23-26

40

21

14

32

26

34

31

34

34

34

Age 27-29

31

39

27

34

43

31

30

38

37

34

Short Answer

Expert verified

At a 0.05 level of significance, it can be concluded that the age of males does not have any significant effect on the ratings.

Thus, no, age does not appear to be a factor that affects the male attribute ratings.

Step by step solution

01

Given information

An analysis of variance test is conducted to test the significance of the factor of age on the male attribute ratings.

The significance level is 0.05.

02

Describe the one-way analysis of variance

The null hypothesis to test the effect of age is as follows.


There is no significant effect of age on the male attribute ratings.

From the results, the value of the F-statistic is equal to 2.7346.

The corresponding p-value is equal to 0.0829.

As the p-value is greater than 0.05, the null hypothesis is failed to be rejected.

Thus, it can be concluded that there is not enough evidence that age has a significant effect on male attribute ratings.

Therefore, age is not a factor that affects the ratings.

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Most popular questions from this chapter

Bonferroni Test Shown below are weights (kg) of poplar trees obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the table below. The data are from a study conducted by researchers at Pennsylvania State University and were provided by Minitab, Inc. Also shown are partial results from using the Bonferroni test with the sample data.

No Treatment

Fertilizer

Irrigation

Fertilizer and Irrigation

1.21

0.94

0.07

0.85

0.57

0.87

0.66

1.78

0.56

0.46

0.10

1.47

0.13

0.58

0.82

2.25

1.30

1.03

0.94

1.64

  1. Use a 0.05 significance level to test the claim that the different treatments result in the same mean weight.
  1. What do the displayed Bonferroni SPSS results tell us?
  1. Use the Bonferroni test procedure with a 0.05 significance level to test for a significant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and either the P-value or critical values. What do the results indicate?

In Exercises 1鈥�4, use the following listed arrival delay times (minutes) for American Airline flights from New York to Los Angeles. Negative values correspond to flights that arrived early. Also shown are the SPSS results for analysis of variance. Assume that we plan to use a 0.05 significance level to test the claim that the different flights have the same mean arrival delay time.

Flight 1

-32

-25

-26

-6

5

-15

-17

-36

Flight 19

-5

-32

-13

-9

-19

49

-30

-23

Flight 21

-23

28

103

-19

-5

-46

13

-3

Why Not Test Two at a Time? Refer to the sample data given in Exercise 1. If we want to test for equality of the three means, why don鈥檛 we use three separate hypothesis tests for\({\mu _1} = {\mu _2},{\mu _1} = {\mu _3}\;and\;{\mu _2} = {\mu _3}\)?

Speed Dating

Listed below are attribute ratings of males by females who participated in speed dating events (from Data Set 18 鈥淪peed Dating鈥� in Appendix B). Use a 0.05 significance level to test the claim that females in the different age brackets give attribute ratings with the same mean. Does age appear to be a factor in the female attribute ratings?

Age 20-22

38

42

30.0

39

47

43

33

31

32

28

Age 23-26

39

31

36.0

35

41

45

36

23

36

20

Age 27-29

36

42

35.5

27

37

34

22

47

36

32

Weights The weights (kg) in the following table are from Data Set 1 鈥淏ody Data鈥� in Appendix B. Results from two-way analysis of variance are also shown. Use the displayed results and use a 0.05 significance level. What do you conclude?


Female

Male

18-29

63.4

57.8

52.6

46.9

61.7

61.5

77.2

50.4

97

76.1

71.6

64.9

144.9

96.4

80.7

84.4

63.9

79

99.4

64.1

30-49

110.5

84.6

133.3

90.2

125.7

105.3

115.5

75.3

92.8

57.7

96.2

56.4

107.4

99.5

64.8

94.7

74.2

112.8

72.6

91.4

50-80

103.2

48.3

87.8

101.3

67.8

45.2

79.8

60.1

68.5

43.3

84.8

127.5

89.9

75.3

110.2

72.3

77.2

86.5

71.3

73.1

Tukey Test

A display of the Bonferroni test results from Table 12-1 (which is part ofthe Chapter Problem) is provided on page 577. Shown on the top of the next page is the SPSS-generated display of results from the Tukey test using the same data. Compare the Tukey test results to those from the Bonferroni test.
See all solutions

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