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Use the relatively small number of given bootstrap samples to construct the confidence interval. Here is a sample of measured radiation emissions (cW/kg) for cell phones (based on data from the Environmental Working Group): \(38,55,86,145 .\) Her bootstrap samples: \(\\{38,145,55,86\\},\\{86,38,145,145\\},\\{145,86,55,55\\},\\{55,55,55,145\\},$$\\{86,86,55,55\\},\\{38,38,86,86\\},\\{145,38,86,55\\},\\{55,86,86,86\\},\\{145,86,55,86\\} \\{38,145,86,55\\}\). a. Using only the ten given bootstrap samples, construct an \(80 \%\) confidence interval estimate of the population mean. b. Using only the ten given bootstrap samples, construct an \(80 \%\) confidence interval estimate of the population standard deviation.

Short Answer

Expert verified
The 80% CI for the mean is [70.5, 93]. The 80% CI for the SD is [17.33, 47.55].

Step by step solution

01

- Calculate Means of Bootstrap Samples

First, identify the mean of each bootstrap sample. \[\{38,145,55,86\} \Rightarrow \text{mean} = \frac{38 + 145 + 55 + 86}{4} = 81 \]\[\{86,38,145,145\} \Rightarrow \text{mean} = \frac{86 + 38 + 145 + 145}{4} = 103.5 \]\[\{145,86,55,55\} \Rightarrow \text{mean} = \frac{145 + 86 + 55 + 55}{4} = 85.25 \]\[\{55,55,55,145\} \Rightarrow \text{mean} = \frac{55 + 55 + 55 + 145}{4} = 77.5 \]\[\{86,86,55,55\} \Rightarrow \text{mean} = \frac{86 + 86 + 55 + 55}{4} = 70.5 \]\[\{38,38,86,86\} \Rightarrow \text{mean} = \frac{38 + 38 + 86 + 86}{4} = 62 \]\[\{145,38,86,55\} \Rightarrow \text{mean} = \frac{145 + 38 + 86 + 55}{4} = 81 \]\[\{55,86,86,86\} \Rightarrow \text{mean} = \frac{55 + 86 + 86 + 86}{4} = 78.25 \]\[\{145,86,55,86\} \Rightarrow \text{mean} = \frac{145 + 86 + 55 + 86}{4} = 93 \]\[\{38,145,86,55\} \Rightarrow \text{mean} = \frac{38 + 145 + 86 + 55}{4} = 81 \]
02

- Order the Means and Find the 80% Confidence Interval

Order the sample means and choose the central 8 observations out of the ten. The ordered means are: 62, 70.5, 77.5, 78.25, 81, 81, 81, 85.25, 93, 103.5. For an 80% confidence interval, we exclude the 1st and the 10th observations: \[ \text{80\text(% ) Confidence Interval } = [70.5, 93] \].
03

- Calculate Standard Deviations of Bootstrap Samples

Identify the standard deviation of each bootstrap sample. \[\{38,145,55,86\} \Rightarrow \text{SD} \approx 47.55 \]\[\{86,38,145,145\} \Rightarrow \text{SD} \approx 54.59 \]\[\{145,86,55,55\} \Rightarrow \text{SD} \approx 42.68 \]\[\{55,55,55,145\} \Rightarrow \text{SD} \approx 41.94 \]\[\{86,86,55,55\} \Rightarrow \text{SD} \approx 17.33 \]\[\{38,38,86,86\} \Rightarrow \text{SD} \approx 24 \]\[\{145,38,86,55\} \Rightarrow \text{SD} \approx 41.94 \]\[\{55,86,86,86\} \Rightarrow \text{SD} \approx 14.28 \]\[\{145,86,55,86\} \Rightarrow \text{SD} \approx 35.77 \]\[\{38,145,86,55\} \Rightarrow \text{SD} \approx 47.03 \]
04

- Order the Standard Deviations and Find the 80% Confidence Interval

Order the standard deviations and choose the central 8 observations out of the ten. The ordered standard deviations are: 14.28, 17.33, 24, 35.77, 41.94, 41.94, 42.68, 47.03, 47.55, 54.59. For an 80% confidence interval, we exclude the 1st and the 10th observations: \[ \text{80\text(% ) Confidence Interval } = [17.33, 47.55] \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

confidence interval
A confidence interval provides the range within which we expect the true value (like a population mean) to fall. It’s based on sample data and gives us an estimate of the uncertainty surrounding our results. Imagine you are trying to estimate the average height of all students in a school. You can't measure everyone, so you measure a sample. The confidence interval tells us that we can be, say, 80% certain that the true average height falls within a specific range.
To construct a confidence interval, you need the sample mean, the variability of the data, and the desired confidence level (like 80%, 90%, or 95%). In our example, we use bootstrap samples to generate multiple sample means and then determine the range where most of these means fall. This range is our confidence interval.
bootstrap method
The bootstrap method is a powerful statistical technique used to estimate the properties of an estimator (like its variance) by sampling with replacement from the original data. This approach allows us to construct confidence intervals without making assumptions about the data distribution.
Think of it as creating many 'mini-samples' from your original data set by randomly selecting data points with replacement. By calculating the mean or standard deviation of these mini-samples, we can build a distribution of these statistics and use it to create confidence intervals.
  • Easy to implement
  • No assumptions about the data distribution
  • Useful for small samples
The bootstrap method is particularly valuable when you have limited data and need a robust way to gauge the uncertainty in your estimates.
statistical analysis
Statistical analysis allows us to make sense of our data. It involves collecting, organizing, interpreting, and presenting data to discover underlying patterns or trends. This can include calculating measures of central tendency (like the mean or median), variability (such as variance or standard deviation), and more advanced techniques like hypothesis testing and regression analysis.
In the context of our exercise, statistical analysis involves calculating the means and standard deviations of bootstrap samples and then constructing confidence intervals. This helps us understand the range within which our population parameters are likely to fall.

It's important because it provides a framework for making decisions based on data and quantifies uncertainty, making our conclusions more reliable.
population mean
The population mean is the average value of a particular characteristic (like height, weight, or in our example, radiation emissions) for the entire population. In many real-world situations, measuring the entire population is not feasible, so we use sample data to estimate the population mean.
The sample mean is calculated by adding up all the sample data points and dividing by the number of points. By using bootstrap samples, we determine multiple sample means, which help us estimate the true population mean and provide the confidence interval.
  • Calculates the central tendency
  • Helps in making predictions about the population
  • Aids in understanding the overall behavior of the population
Understanding the population mean is crucial in statistical analysis as it forms the basis for many other calculations and interpretations.
population standard deviation
The population standard deviation measures the amount of variability or dispersion in a population. It tells us how much the individual data points typically deviate from the population mean. A small standard deviation indicates that the data points are close to the mean, while a large standard deviation indicates more spread out data points.
Just like with the population mean, calculating the standard deviation for an entire population is often impractical. Instead, we use sample data to estimate it. In our exercise, we calculate the standard deviations of bootstrap samples and create a confidence interval for the population standard deviation.
Understanding the population standard deviation is important for:
  • Identifying the spread of the data
  • Assessing variability within the population
  • Making informed decisions based on the consistency of the data
It provides insights into how consistent the data is, which is essential for many areas of statistical analysis.

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Most popular questions from this chapter

Construct the confidence interval estimate of the mean. Listed below are amounts of arsenic \((\mu \mathrm{g},\) or micrograms, per serving) in samples of brown rice from California (based on data from the Food and Drug Administration). Use a \(90 \%\) confidence level. The Food and Drug Administration also measured amounts of arsenic in samples of brown rice from Arkansas. Can the confidence interval be used to describe arsenic levels in Arkansas? $$\begin{array}{cccccccccc} 5.4 & 5.6 & 8.4 & 7.3 & 4.5 & 7.5 & 1.5 & 5.5 & 9.1 & 8.7 \end{array}$$

Find the sample size required to estimate the population mean. Data Set 1 "Body Data" in Appendix B includes weights of 153 randomly selected adult males, and those weights have a standard deviation of \(17.65 \mathrm{kg}\). Because it is reasonable to assume that weights of male statistics students have less variation than weights of the population of adult males, let \(\sigma=17.65 \mathrm{kg}\). How many male statistics students must be weighed in order to estimate the mean weight of all male statistics students? Assume that we want \(90 \%\) confidence that the sample mean is within \(1.5 \mathrm{kg}\) of the population mean. Does it seem reasonable to assume that weights of male statistics students have less variation than weights of the population of adult males?

Finding Critical Values and Confidence Intervals. In Exercises \(5-8,\) use the given information to find the number of degrees of freedom, the critical values \(\mathcal{X}_{L}^{2}\) and \(\mathcal{X}_{R}^{2},\) and the confidence interval estimate of \(\boldsymbol{\sigma} .\) The samples are from Appendix \(\boldsymbol{B}\) and it is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Heights of Men \(99 \%\) confidence; \(n=153, s=7.10 \mathrm{cm}\)

Use the data and confidence level to construct a confidence interval estimate of \(p,\) then address the given question. A random sample of 860 births in New York State included 426 boys. Construct a \(95 \%\) confidence interval estimate of the proportion of boys in all births. It is believed that among all births, the proportion of boys is \(0.512 .\) Do these sample results provide strong evidence against that belief?

Use the given data to find the minimum sample size required to estimate a population proportion or percentage. A sociologist plans to conduct a survey to estimate the percentage of adults who believe in astrology. How many people must be surveyed if we want a confidence level of \(99 \%\) and a margin of error of four percentage points? a. Assume that nothing is known about the percentage to be estimated. b. Use the information from a previous Harris survey in which \(26 \%\) of respondents said that they believed in astrology.

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