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Using the Central Limit Theorem assume that females have pulse rates that are normally distributed with a mean of 74.0 beats per minute and a standard deviation of 12.5 beats per minute (based on Data Set 1 "Body Data" in Appendix \(B\) ). a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 80 beats per minute. b. If 16 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 80 beats per minute. c. Why can the normal distribution be used in part (b), even though the sample size does not exceed \(30 ?\)

Short Answer

Expert verified
a. 0.6844. b. 0.9726. c. Central Limit Theorem allows us to assume normality for reasonable sample sizes.

Step by step solution

01

Understanding Problem a

Identify the elements given: the mean \( \mu = 74.0 \) beats per minute, the standard deviation \( \sigma = 12.5 \) beats per minute, and we need to find the probability for a single female to have a pulse rate less than 80 beats per minute.
02

Calculate the Z-score for Problem a

Use the Z-score formula \( Z = \frac{X - \mu}{\sigma} \). Here, \( X = 80 \). Hence, \[ Z = \frac{80 - 74.0}{12.5} = 0.48 \]
03

Find the Probability for Problem a

Use the Z-table to find the probability corresponding to \( Z = 0.48 \). The table gives a value of approximately \( 0.6844 \). Thus, the probability that her pulse rate is less than 80 beats per minute is \( 0.6844 \).
04

Understanding Problem b

Identify the new problem elements: the sample size \( n = 16 \). We need to find the probability that the mean pulse rate of these 16 females is less than 80 beats per minute.
05

Calculate the Mean and Standard Error for Problem b

The mean remains \( \mu = 74.0 \). The standard error of the mean, \( \sigma_{\bar{X}} = \frac{\sigma}{\sqrt{n}} = \frac{12.5}{\sqrt{16}} = 3.125 \).
06

Calculate the Z-score for Problem b

Use the Z-score formula for the sample mean: \[ Z = \frac{\bar{X} - \mu}{\sigma_{\bar{X}}} = \frac{80 - 74.0}{3.125} = 1.92 \]
07

Find the Probability for Problem b

Use the Z-table to find the probability corresponding to \( Z = 1.92 \). The table gives a value of approximately \( 0.9726 \). Thus, the probability that the mean pulse rate of 16 females is less than 80 beats per minute is \( 0.9726 \).
08

Explanation for Problem c

The Central Limit Theorem states that the sampling distribution of the sample mean approaches a normal distribution as the sample size \( n \) increases, regardless of the original distribution, providing \( n \) is sufficiently large. For sample sizes of \( n \) greater than 30 or even smaller but reasonable to assume normality when the process is nearly normal, it is safe to use the normal distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

normal distribution
The normal distribution is a foundational concept in statistics that describes how data points are distributed around a mean. This distribution is symmetrical and bell-shaped, indicating that most data points cluster around the central mean, often represented as \( \mu \). The farther from the mean you go, the less frequent those data points become. For example, in our problem, the pulse rates are said to be normally distributed with a mean of 74 beats per minute and a standard deviation of 12.5 beats per minute. This means that most pulse rates will be around 74, and as you move further from this value, the frequency of pulse rates decreases.
Z-score calculation
To determine how far a particular data point is from the mean in terms of standard deviations, we use the Z-score. The formula for the Z-score is \( Z = \frac{X - \mu}{\sigma} \), where \( X \) is the data point, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. By converting a value to a Z-score, we can determine its position relative to the mean and find probabilities using a Z-table. For instance, in part a of our problem, we calculated the Z-score for a pulse rate of 80 beats per minute as \( Z = 0.48 \). This tells us that 80 beats per minute is 0.48 standard deviations above the mean of 74.
standard error
The standard error measures the variability of the sample mean from the population mean. It is calculated as \( SE = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the standard deviation and \( n \) is the sample size. In part b of our problem, we need to find the standard error for a sample of 16 females. Starting with a standard deviation of 12.5 and a sample size of 16, we calculate \( SE = \frac{12.5}{4} = 3.125 \). This tells us how much the sample mean is expected to vary from the population mean.
sampling distribution
The sampling distribution of the sample mean is the distribution of all possible sample means from all possible samples of a given size from a population. This concept is crucial in the Central Limit Theorem (CLT). The CLT states that, regardless of the population's distribution, the sampling distribution of the sample mean approaches a normal distribution as the sample size gets larger, usually larger than 30. In our exercise, even though the sample size of 16 is less than 30, the normal distribution can still be used. This is because the original pulse rate data are normally distributed, allowing the sample mean to also be normally distributed. This ensures the validity of using the normal distribution to find probabilities.

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Most popular questions from this chapter

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