/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Find the (a) explained variation... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. In each case, there is sufficient evidence to support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions. The table below lists overhead widths (cm) of seals measured from photographs and the weights (kg) of the seals (based on "Mass Estimation of Weddell Seals Using Techniques of Photogrammetry," by R. Garrott of Montana State University). For the prediction interval, use a \(99 \%\) confidence level with an overhead width of \(9.0 \mathrm{cm} .\) $$\begin{array}{l|l|l|l|l|l|l}\hline \text { Overhead Width } & 7.2 & 7.4 & 9.8 & 9.4 & 8.8 & 8.4 \\ \hline \text { Weight } & 116 & 154 & 245 & 202 & 200 & 191 \\\\\hline\end{array}$$

Short Answer

Expert verified
Calculate the regression equation to find predicted weights. Use the predicted weights to compute explained and unexplained variations. Use the prediction interval formula to find the indicated interval for \( x = 9.0 \mathrm{cm} \).

Step by step solution

01

Calculate the Regression Equation

First, find the regression equation of the form \(\text{Weight} = a + b \times \text{Overhead Width}\). Using the least squares method, calculate the slope \(b\) and intercept \(a\) by using the given data points.
02

Compute the Slope (b) and Intercept (a)

Compute the slope \(b\) and intercept \(a\) using the formulas: \( b = \frac{N \sum{xy} - \sum{x} \sum{y}}{N \sum{x^2} - (\sum{x})^2} \) \( a = \frac{\sum{y} - b \sum{x}}{N} \) where \emph{x} represents Overhead Width and \emph{y} represents Weight.
03

Calculate the Predicted Weights

Using the regression equation obtained, calculate the predicted weights for the given overhead widths.
04

Calculate Explained Variation

To find the explained variation, use the formula \[SS_{regression} = \sum{(\hat{y_i} - \bar{y})^2} \] where \( \hat{y_i} \) is the predicted weight, and \( \bar{y} \) is the mean of the observed weights.
05

Calculate Unexplained Variation

The unexplained variation can be found using the formula \[SS_{residuals} = \sum{(y_i - \hat{y_i})^2} \] where \( y_i \) is the observed weight and \( \hat{y_i} \) is the predicted weight.
06

Determine Prediction Interval

Use the formula for the prediction interval at a certain confidence level, \[ \hat{y} \pm t_{\alpha/2,n-2} \sqrt{MS_{residual} (1 + \frac{1}{n} + \frac{(x_i - \bar{x})^2}{\sum{(x_i - \bar{x})^2}})} \] where \( \hat{y} \) is the predicted value for \(x = 9.0 \mathrm{cm} \), \( t_{\alpha/2,n-2} \) is the t-score for the confidence level and \emph{df}, and \( MS_{residual} \) is the mean square error.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Explained Variation
Explained variation refers to the portion of the total variation in the dependent variable (Weight, in this case) that can be explained by the independent variable (Overhead Width). It tells us how well our regression model performs in explaining the variations in the data.
To find the explained variation, we use the formula:
\[SS_{regression} = \sum{(\hat{y_i} - \bar{y})^2} \]
where:
\( \hat{y_i} \) = predicted value using the regression equation
\( \bar{y} \) = mean of the observed weights
In simpler terms, explained variation measures the differences between the predicted values of the regression model and the average of the observed values. The higher the explained variation, the better your model fits the data.
Unexplained Variation
Unexplained variation, also known as residual variation, measures the discrepancy between the observed values and the predicted values from the regression model. It shows the amount of variation that the model fails to explain.
The formula to compute unexplained variation is:
\[SS_{residuals} = \sum{(y_i - \hat{y_i})^2} \]
where:
\( y_i \) = actual observed value
\( \hat{y_i} \) = predicted value from the regression equation
In other words, unexplained variation evaluates the scatter of data points around the regression line. A smaller unexplained variation indicates a more accurate model.
Prediction Interval
A prediction interval gives us a range within which we expect a new observation to fall, with a certain level of confidence. For example, a 99% prediction interval means that we are 99% confident that the actual value will lie within this range.
To calculate it, use the formula:
\[ \hat{y} \pm t_{\alpha/2,n-2} \sqrt{MS_{residual} (1 + \frac{1}{n} + \frac{(x_i - \bar{x})^2}{\sum{(x_i - \bar{x})^2}})} \]
where:
\( \hat{y} \) = predicted value
\( t_{\alpha/2,n-2} \) = t-score for the given confidence level and degrees of freedom
\( MS_{residual} \) = mean square error
The prediction interval considers both the variability in the data and the sample size to provide a more realistic range for future predictions. It's especially useful in practice, as it accounts for the natural uncertainty in predictions.
Least Squares Method
The least squares method is a standard approach for deriving the regression line in linear regression. It minimizes the sum of the squares of the residuals (the differences between observed and predicted values).
The regression equation is of the form:
\( Weight = a + b \times Overhead \ Width\)
To find the coefficients, you calculate the slope \( b \) and intercept \( a \) using the formulas:
\[ b = \frac{N \sum{xy} - \sum{x} \sum{y}}{N \sum{x^2} - (\sum{x})^2} \]
\[ a = \frac{\sum{y} - b \sum{x}}{N} \]
where:
\( N \) = number of data points
\( x \) = Overhead Width
\( y \) = Weight
By fitting the line through the data points such that the sum of the squared differences between observed and predicted values is minimized, we obtain the best-fit line for making predictions. This technique is fundamental in regression analysis and provides a basis for understanding the relationship between variables.

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Most popular questions from this chapter

Let \(x\) represent years coded as \(1,2,3, \ldots\). for years starting in 1980 and let \(y\) represent the numbers of points scored in each Super Bowl from \(1980 .\) Using the data from 1980 to the last Super Bowl at the time of this writing, we obtain the following values of \(R^{2}\) for the different models: linear: 0.147; quadratic: 0.255; logarithmic: 0.176; exponential: 0.175; power: \(0.203 .\) Based on these results, which model is best? Is the best model a good model? What do the results suggest about predicting the number of points scored in a future Super Bowl game?

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Construct a scatterplot, and find the value of the linear correlation coefficient \(r\) Also find the \(P\) -value or the critical values of \(r\) from Table \(A\) -6. Use a significance level of \(\alpha=0.05 .\) Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section \(10-2\) exercises.)Diameters (cm), circumferences (cm), and volumes (cm \(^{3}\) ) from balls used in different sports are listed in the table below. Is there sufficient evidence to conclude that there is a linear correlation between diameters and circumferences? Does the scatterplot confirm a linear association?$$\begin{array}{l|c|c|c|c|c|c|c|c} \hline & \text { Baseball } & \text { Basketball } & \text { Golf } & \text { Soccer } & \text { Tennis } & \text { Ping-Pong } & \text { Volleyball } & \text { Softball } \\\\\hline \text { Diameter } & 7.4 & 23.9 & 4.3 & 21.8 & 7.0 & 4.0 & 20.9 & 9.7 \\\\\hline \text { Circumference } & 23.2 & 75.1 & 13.5 & 68.5 & 22.0 & 12.6 & 65.7 & 30.5 \\\\\hline \text { Volume } & 212.2 & 7148.1 & 41.6 & 5424.6 & 179.6 & 33.5 & 4780.1 & 477.9 \\ \hline\end{array}$$

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