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One of the objectives of a large medical study was to estimate the mean physician fee for cataract removal. For 25 randomly selected cases, the mean fee was found to be \(3550\)dollar with a standard deviation of \(275\)dollar. Set a \(99 \%\) confidence interval on \(\mu,\) the mean fee for all physicians. Assume fees are normally distributed.

Short Answer

Expert verified
The mean fee for all physicians with a 99% confidence interval is approximately between $3408.32 and $3691.68.

Step by step solution

01

Identify given values

Here the sample mean (\( \bar{X} \)) is $3550, the standard deviation (\( \sigma \)) is $275, the sample size (\( n \)) is 25, and the confidence interval required is 99%.
02

Determine the z-score for the desired confidence level

Refer to a standard z-table or use statistical software to find the z-score that corresponds to the middle 99% of the data. This would be \( \pm 2.576 \) as each tail is 0.5%.
03

Calculate the standard error

The standard error (SE) is the standard deviation divided by the square root of the sample size. It can be calculated as \( SE = \frac{\sigma}{\sqrt{n}} = \frac{275}{\sqrt{25}} = 55 \).
04

Determine the margin of error

The margin of error (ME) for a confidence interval is the product of the z-score and the standard error. It can be calculated as \( ME = z \times SE = 2.576 \times 55 = 141.68 \).
05

Compute the confidence intervals

Adding and subtracting the margin of error from the sample mean gives the confidence intervals. Thus the 99% confidence interval for the mean fee is \( \bar{X} \pm ME = 3550 \pm 141.68 \), which gives an interval from \(3408.32\) to \(3691.68\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Fee Estimation
The mean fee estimation refers to the process of determining the average charge for a specific service, in our case, the physician fee for cataract removal. This average provides a central value around which individual fees are expected to vary. In statistical terms, the mean fee is denoted by the symbol \( \mu \), which represents the true mean of the entire population. When conducting studies, as with the medical study example, it is often impractical or impossible to measure the entire population, so a random sample is taken. Here, the average fee from 25 cases was \( \$3550 \), which serves as our best estimate of the population mean. Using this sample information to estimate the population mean is a foundational concept in statistics known as 'point estimation'.
Standard Deviation
Standard deviation is a measure of the amount of variation or dispersion in a set of values. A low standard deviation means that the values tend to be close to the mean, while a high standard deviation means that the values are spread out over a wider range. In the context of the medical study, the standard deviation of \( \$275 \) indicates the extent to which individual physician fees deviate from the average fee. Understanding standard deviation is crucial when analyzing the reliability of the mean fee estimation because it gives context to how much variability exists within the fee amounts.
Sample Size
Sample size, denoted as \( n \), is the number of observations in a sample. It plays a critical role in the calculation of confidence intervals as it directly impacts the standard error. The larger the sample size, the smaller the standard error, and hence the more precise our confidence interval becomes. In our example, the sample size is 25. When calculating confidence intervals, it's vital to ensure that the sample size is large enough to provide reliable estimates but also manageable in terms of practicality and resources available for the study.
Z-score
The z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations. It is a dimensionless quantity that is especially useful in determining the number of standard deviations a data point is from the mean. When constructing confidence intervals, the z-score helps in defining the range within which the population mean is likely to be found. A 99% confidence level corresponds to a z-score of \( \pm 2.576 \), which encompasses the middle 99% of the data on a standard normal distribution curve.
Standard Error
The standard error (SE) is a statistical term that measures the accuracy with which a sample distribution represents a population using standard deviation and sample size. It is calculated by dividing the standard deviation by the square root of the sample size. In our exercise, the standard error is \( \$55 \), which is the estimated standard deviation of the sample mean. This value is used alongside the z-score to calculate the margin of error, which provides the range above and below the sample mean to create the confidence interval for the population mean. The standard error plays a pivotal role because it provides a quantifiable metric to indicate the precision of our mean fee estimate.

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Most popular questions from this chapter

Acetaminophen is an active ingredient found in more than 600 over-the-counter and prescription medicines, such as pain relievers, cough suppressants, and cold medications. It is safe and effective when used correctly, but taking too much can lead to liver damage. A researcher believes the mean amount of acetaminophen per tablet in a particular brand of cold tablets is different from the 600 mg claimed by the manufacturer. A random sample of 30 tablets had a mean acetaminophen content of \(596.3 \mathrm{mg}\) with a standard deviation of \(4.7 \mathrm{mg}\). a. Is the assumption of normality reasonable? Explain. b. Construct a \(99 \%\) confidence interval for the estimate of the mean acetaminophen content. c. What does the confidence interval found in part b suggest about the mean acetaminophen content of one pill? Do you believe there is 600 mg per tablet? Explain.

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