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State the null hypothesis, \(H_{o}\), and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. The standard deviation has increased from its previous value of 24. b. The standard deviation is no larger than 0.5 oz. c. The standard deviation is not equal to \(10 .\) d. The variance is no less than \(18 .\) e. The variance is different from the value of \(0.025,\) the value called for in the specs.

Short Answer

Expert verified
Hypotheses for the problems are as follows: a. \(H_{0}: \sigma = 24\), \(H_{a}: \sigma > 24\); b. \(H_{0}: \sigma > 0.5\), \(H_{a}: \sigma \leq 0.5\); c. \(H_{0}: \sigma = 10\), \(H_{a}: \sigma \neq 10\); d. \(H_{0}: \sigma^2 < 18\), \(H_{a}: \sigma^2 \geq 18\); e. \(H_{0}: \sigma^2 = 0.025\), \(H_{a}: \sigma^2 \neq 0.025\).

Step by step solution

01

a. Testing the claim on the standard deviation

The claim is that the standard deviation has increased from its previous value of 24. Hence, the null hypothesis, \(H_{0}\), is going to be that the standard deviation, denoted as \(\sigma\), is still 24. The alternative hypothesis, \(H_{a}\), will be that \(\sigma\) is more than 24. Formulated mathematically: \[H_{0}: \sigma = 24\] \[H_{a}: \sigma > 24\]
02

b. Testing the claim on the standard deviation

The claim is that the standard deviation is no larger than 0.5 oz. Hence, the null hypothesis, \(H_{0}\), is going to be that \(\sigma\) is more than 0.5 oz. The alternative hypothesis, \(H_{a}\), will be that \(\sigma\) is less than or equal to 0.5 oz. Formulated mathematically: \[H_{0}: \sigma > 0.5\] \[H_{a}: \sigma \leq 0.5\]
03

c. Testing the claim on the standard deviation

The claim is that the standard deviation is not equal to 10. Hence, the null hypothesis, \(H_{0}\), is going to be that \(\sigma = 10\). The alternative hypothesis, \(H_{a}\), will be that \(\sigma \neq 10\). Formulated mathematically: \[H_{0}: \sigma = 10\] \[H_{a}: \sigma \neq 10\]
04

d. Testing the claim on the variance

The claim is that the variance, denoted as \(\sigma^2\), is no less than 18. Hence, the null hypothesis, \(H_{0}\), is going to be that the variance is less than 18. The alternative hypothesis, \(H_{a}\), will be that \(\sigma^2 \geq 18\). Formulated mathematically: \[H_{0}: \sigma^2 < 18\] \[H_{a}: \sigma^2 \geq 18\]
05

e. Testing the claim on the variance

The claim is that the variance is different from 0.025. Hence, the null hypothesis, \(H_{0}\), is going to be that the variance is 0.025. The alternative hypothesis, \(H_{a}\), will be that \(\sigma^2 \neq 0.025\). Formulated mathematically: \[H_{0}: \sigma^2 = 0.025\] \[H_{a}: \sigma^2 \neq 0.025\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In the realm of hypothesis testing in statistics, the null hypothesis (\(H_{0}\)) acts as a starting point. It's a statement suggesting that there is no significant effect or that there is no difference from the norm. It represents the status quo or a position of skepticism, essentially asserting that any observed variations in data are attributable to chance rather than to a specific cause or intervention.

For example, if a quality control manager believes that the standard deviation of a production process has not changed, they would propose a null hypothesis stating that the current standard deviation is equal to the historical standard deviation. In hypothesis testing, this is the hypothesis we attempt to refute through statistical analysis, seeking evidence that supports the alternative hypothesis instead.
Alternative Hypothesis
The alternative hypothesis (\(H_{a}\)) is the counterclaim to the null hypothesis and is supported when the null is rejected. It represents what researchers aim to prove or manifest—suggesting that there is indeed a significant effect, or that a particular parameter differs from its standard value.

Continuing with our example of the quality control manager, if they suspect that the standard deviation has increased, they would articulate an alternative hypothesis stating that the current standard deviation is greater than the historical value. In conducting a test, if sufficient evidence arises to discredit the null hypothesis, it is concluded that there is enough support for the alternative hypothesis.
Standard Deviation
Standard deviation is a widely used measure of the amount of variation or dispersion in a set of values. It quantifies how much the numbers in a data set deviate from their mean (average) value. A low standard deviation indicates that the data points are clustered closely around the mean, suggesting consistency or uniform performance. Conversely, a high standard deviation signifies greater variability and potential unpredictability or inconsistency in the data set.

In hypothesis testing, the standard deviation is crucial for determining the normalcy of data variation and for comparing it against what is expected or what has been claimed. A key application is assessing whether the variability in a process has changed, often with implications for quality control or process improvement.
Variance
Variance is another statistical measure of dispersion, quite similar to standard deviation but with a key difference—it is the square of the standard deviation. Variance provides a squared measure of how much a set of numbers is spread out. While the standard deviation is more commonly noticed due to its units being the same as those of the original data, variance is equally important, especially in analytical methods that require it specifically.

When hypothesis testing concerns variance, such as determining if the variance is no less than a specified value, the test aims to verify if the spread of the data corresponds to established standards or expectations. Interpretation of variance tests is critical to understand the spread of data and often influences decisions about the variability of processes.

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Most popular questions from this chapter

A manufacturer of television sets claims that the maintenance expenditures for its product will average no more than \(110\)dollar during the first year following the expiration of the warranty. A consumer group has asked you to substantiate or discredit the claim. The results of a random sample of 50 owners of such television sets showed that the mean expenditure was \(131.60\)dollar and the standard deviation was \(42.46\)dollar At the 0.01 level of significance, should you conclude that the manufacturer's claim is true or not likely to be true?

Calculate the test statistic \(z \star\) used in testing the following: a. \(H_{o}: p=0.70\) vs. \(H_{a}: p>0.70,\) with the sample \(n=300\) and \(x=224\) b. \(H_{o}: p=0.50\) vs. \(H_{a}: p<0.50,\) with the sample \(n=450\) and \(x=207\) c. \(H_{o}: p=0.35\) vs. \(H_{a}: p \neq 0.35,\) with the sample \(n=280\) and \(x=94\) d. \(H_{o}: p=0.90\) vs. \(H_{a}: p>0.90,\) with the sample \(n=550\) and \(x=508\)

Find \(\alpha,\) the area of one tail, and the confidence coefficients of \(z\) that are used with each of the following levels of confidence. a. \(1-\alpha=0.80\) b. \(1-\alpha=0.98\) c. \(1-\alpha=0.75\)

It is claimed that the students at a certain university will score an average of 35 on a given test. Is the claim reasonable if a random sample of test scores from this university yields \(33,42,38,37,30,42 ?\) Complete a hypothesis test using \(\alpha=0.05 .\) Assume test results are normally distributed. a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

The chief executive officer (CEO) of a small business wishes to hire your consulting firm to conduct a simple random sample of its customers. She wants to determine the proportion of her customers who consider her company the primary source of their products. She requests the margin of error in the proportion be no more than \(3 \%\) with \(95 \%\) confidence. Earlier studies have indicated that the approximate proportion is \(37 \%\). a. What is the minimum size of the sample that you would recommend to meet the requirements of your client if you use the earlier results? b. What is the minimum size of the sample that you would recommend to meet the requirements of your client if you ignore the earlier results? c. Is the approximate proportion of value needed in conducting the survey? Explain.

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