/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 77 Explain why \(\alpha\) is not al... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why \(\alpha\) is not always the probability of rejecting the null hypothesis.

Short Answer

Expert verified
The value \(\alpha\) is not always the probability of rejecting the null hypothesis because it only represents the probability of making a Type I error - rejecting a true null hypothesis - rather than the overall probability of rejecting the null hypothesis.

Step by step solution

01

Understand the Hypothesis Testing

Start with an understanding of what hypothesis testing is. A researcher sets up a null hypothesis (often denoted as \(H_0\)), which generally represents a sceptical perspective, a status quo, or a baseline situation. An alternative hypothesis (or \(H_1\)) represents what the researcher wants to prove, which is an alternative situation or a departure from the status quo.
02

Define the Alpha Level

Define what an \(\alpha\) level is. In hypothesis testing procedures, \(\alpha\) is the pre-determined level at which the null hypothesis would be rejected. This is commonly set at 0.05, meaning a 5% 'risk' is accepted of wrongly rejecting the null hypothesis, considering it as a Type I error.
03

Explain the Distinction

The critical point to understand here is that \(\alpha\) is the risk of a Type I error – rejecting the null hypothesis when it is in fact true. It does not represent the overall probability of rejecting the null hypothesis, as that would not only depend on the \(\alpha\) but also on the nature of the data, how convincingly it supports or counters the null hypothesis, among other factors.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In the realm of statistics, the null hypothesis, typically denoted as \(H_0\), is a default stance that indicates no effect or no difference. It's the skeptical position which implies that any observed changes in data are due to chance rather than a specific intervention or exposure. For instance, if a scientist is testing a new drug, the null hypothesis would be that the drug has no effect on patients, implying that any improvement in patients' health is coincidental.

Understanding the null hypothesis is paramount because it is what researchers aim to challenge or disprove. The intent is not to 'prove' the null hypothesis but to find sufficient evidence to support the alternative hypothesis. This approach keeps scientific investigations grounded and prevents the drawing of unwarranted conclusions from noisy data.
Alpha Level
The alpha level, denoted as \(\alpha\), is a threshold value that determines the criteria for rejecting the null hypothesis in a statistical test. The alpha level is set by the researcher before collecting data and is considered the acceptable risk of making a Type I error. A common alpha level is 0.05, which means there is a 5% chance of rejecting the null hypothesis when it is actually true.

But, it's essential to recognize that the alpha level is not the probability of rejecting the null hypothesis outright. Instead, it's the probability of wrongly doing so when the null hypothesis is true. The actual probability of rejecting the null hypothesis involves more complexities, including the power of the test, the effect size, and the data itself. Therefore, the alpha level is a risk management tool, balancing the need for scientific rigor with the practicalities of data variation.
Type I Error
A Type I error occurs when a true null hypothesis is incorrectly rejected. This is equivalent to a false positive in diagnostic terms. When researchers set their alpha level at 0.05, they're saying they accept a 5% risk of committing a Type I error in their hypothesis testing. However, it is vital to note that a Type I error is not the only error to be concerned about. There is also a Type II error (a false negative), which occurs when a false null hypothesis is not rejected.

Misunderstanding the alpha level as the overall probability of rejecting the null hypothesis, rather than the risk of a Type I error, can lead to confusion. Properly distinguishing between the two helps maintain the clarity and integrity of statistical analysis, ensuring that researchers are drawing the correct conclusions from their data.
Alternative Hypothesis
Contrasting with the null hypothesis, the alternative hypothesis, usually denoted as \(H_1\) or \(H_a\), is the claim under investigation that the researcher wishes to support. It proposes that there is a meaningful effect or difference, showing that the observation is not due to random chance. For example, a researcher testing the efficacy of a medication would have an alternative hypothesis stating that the medication does indeed have an impact on treatment.

The alternative hypothesis is what drives the need for robust hypothesis testing, as proving it usually suggests new findings or advancements in a field. But proving an alternative hypothesis requires solid evidence to reject the null hypothesis beyond a reasonable doubt, as indicated by surpassing the alpha level threshold. This helps ensure that meaningful discoveries are not the results of random variance but indicative of real effects or relationships.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Who says that the more you spend on a wristwatch, the more accurately the watch will keep time? Some say that you can now buy a quartz watch for less than \(\$ 25\) that keeps time just as accurately as watches that cost four times as much. Suppose the average accuracy for all watches being sold today, regardless of price, is within 19.8 seconds per month with a standard deviation of 9.1 seconds. A random sample of 36 quartz watches priced less than \(\$ 25\) is taken, and their accuracy check reveals a sample mean error of 22.7 seconds per month. Based on this evidence, complete the hypothesis test of \(H_{o}: \mu=20\) vs. \(H_{a}: \mu>20\) at the 0.05 level of significance using the probability-value approach. a. Define the parameter. b. State the null and alternative hypotheses. c. Specify the hypothesis test criteria. d. Present the sample evidence. e. Find the probability distribution information. f. Determine the results.

For each of the following pairs of values, state the decision that will occur and why. a. \(\quad p\) -value \(=0.018, \alpha=0.01\) b. \(\quad p\) -value \(=0.033, \alpha=0.05\) c. \(\quad p\) -value \(=0.078, \alpha=0.05\) d. \(\quad p\) -value \(=0.235, \alpha=0.10\)

A lawn and garden sprinkler system is designed to have a delayed start; that is, there is a delay from the moment it is turned on until the water starts. The delay times form a normal distribution with mean 45 seconds and standard deviation 8 seconds. Several customers have complained that the delay time is considerably longer than claimed. The system engineer has selected a random sample of 15 installed systems and has obtained one delay time from each system. The sample mean is 50.1 seconds. Using \(\alpha=0.02,\) is there significant evidence to show that the customers might be correct that the mean delay time is more than 45 seconds? a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

Use a computer or calculator to select 40 random single-digit numbers. Find the sample mean and \(z\) Using \(\alpha=0.05,\) state the decision for testing \(H_{o}: \mu=4.5\) against a two-tailed alternative. Repeat it several times as in Table \(8.12 .\) Describe your findings after several tries.

A manufacturing process produces ball bearings with diameters having a normal distribution and a standard deviation of \(\sigma=0.04 \mathrm{cm} .\) Ball bearings that have diameters that are too small or too large are undesirable. To test the null hypothesis that \(\mu=0.50 \mathrm{cm},\) a sample of 25 is randomly selected and the sample mean is found to be 0.51. a. Design null and alternative hypotheses such that rejection of the null hypothesis will imply that the ball bearings are undesirable. b. Using the decision rule established in part a, what is the \(p\) -value for the sample results? c. If the decision rule in part a is used with \(\alpha=0.02\) what is the critical value for the test statistic?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.