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Determine the value of the confidence coefficient \(z(\alpha / 2)\) for each situation described: a. \(1-\alpha=0.90\) b. \(1-\alpha=0.95\)

Short Answer

Expert verified
The confidence coefficients for the situations are \(Z(\alpha / 2)=1.645\) for \(1-\alpha=0.90\) and \(Z(\alpha / 2)=1.96\) for \(1-\alpha=0.95\)

Step by step solution

01

Determination of Alpha (α)

Identify the value of alpha (α) from the problem. Alpha (α) is the significance level and it can be found by subtracting the confidence level \(1-\alpha\) from 1. That is, \(\alpha = 1 - (1-\alpha)\).
02

Calculating for α/2

After determining α, divide it by 2. This is because \(z(\alpha / 2)\) represents a two-tailed test, where the rejection region is divided equally at both ends of the distribution curve. Therefore, calculate \(\alpha / 2\) in order to secure the right critical value.
03

Finding the Confidence Coefficient

Next, determine the confidence coefficient \(Z(\alpha / 2)\) using a standard normal distribution table. Look up the value that corresponds to \((1 - \alpha / 2)\) in the table. This value represents how many standard deviations we are from the mean.
04

Applying to problem part a

For \(1-\alpha=0.90\), we calculate \(\alpha\) as \(1 - 0.9 =0.1\). Then, \(\alpha / 2 = 0.1 / 2 = 0.05\). Using the Z-table, the \(Z(\alpha / 2) = 1.645\).
05

Applying to problem part b

For \(1-\alpha=0.95\), we calculate \(\alpha\) as \(1 - 0.95 = 0.05\). Then, \(\alpha / 2 = 0.05 / 2 = 0.025\). Using the Z-table, the \(Z(\alpha / 2)= 1.96\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
The confidence level is a measure that indicates how frequently we can expect the outcome of a statistical parameter to fall within certain range when we repeat the same study numerous times. It is often expressed as a percentage, like 90% or 95%. These percentages reflect how confident we are that our interval estimates such as a mean or proportion fall within the true population parameters.

This confidence level relates to the probability that the calculated interval actually includes the true parameter value of interest. For instance, if you have a 95% confidence level, it implies that if you were to take 100 random samples and compute a 95% confidence interval for each one, you would expect about 95 of these intervals to contain the true population parameter.

When formulating a confidence interval, the corresponding confidence coefficient, denoted as \(Z(\alpha / 2)\), will be looked up in a standard normal distribution table. This is key in knowing how many standard deviations we are considering on each tail of the bell curve.
Significance Level
The significance level, symbolized by \(\alpha\), is a threshold set by the researcher which defines the risk of incorrectly rejecting a true null hypothesis. This is an important concept in hypothesis testing.

Often, significance levels are set to 0.05 (5%) or 0.01 (1%), indicating a 5% or 1% risk of concluding that a difference exists when, in fact, it does not. These complement the confidence levels. For instance, a 95% confidence level implies a significance level of 0.05; in turn, this means there is a 5% chance that the effect observed is due to random variation in the sample rather than a true effect.

To compute the confidence coefficient \(Z(\alpha / 2)\), after defining \(\alpha\), you divide it by 2 to account for the two tails of the distribution curve, characteristic of a two-tailed test. This division acknowledges that extreme deviations from the mean can occur on both sides.
Standard Normal Distribution
The standard normal distribution is a special type of probability distribution that is critical in statistics. It's a bell-shaped curve where the mean is 0 and the standard deviation is 1.

This distribution is used extensively for its mathematical properties and interprets many natural phenomena. When discussing the confidence coefficient \(Z(\alpha / 2)\), standard normal distribution tables are referenced to find the critical value that corresponds with \((1 - \alpha / 2)\). These critical values indicate the number of standard deviations needed to encompass the required percentage of data around the mean.

In essence, the standard normal distribution acts as the foundational tool for understanding how data values spread around a mean in a normal distribution, making it indispensable for hypothesis testing and calculating confidence intervals.

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Most popular questions from this chapter

Nationally, the ratio of nurses to students falls short of the recommended federal standard, according to the USA Today article "School nurses in short supply" (August \(11,2009) .\) The recommendation from the Centers for Disease Control and Prevention (CDC) is 1 nurse per 750 students. Use the sample below from 38 randomly selected schools in the state of New York to test the statement "The New York mean number of students per school nurse is significantly higher than the CDC standard of \(750 . "\) Assume \(\sigma=540\) $$\begin{array}{lllllllllll} \hline 1062 & 1070 & 353 & 675 & 1557 & 1374 & 459 & 302 & 1946 & 487 & 295 \\\ 1047 & 1751 & 784 & 480 & 377 & 883 & 1035 & 332 & 330 & 989 & 1098 \\ 1241 & 778 & 1691 & 963 & 1645 & 1594 & 2125 & 338 & 1380 & 885 & 707 \\ 1267 & 1412 & 1037 & 1603 & 915 & & & & & & \\ \hline \end{array}$$ a. Describe the parameter of interest. b. State the null and alternative hypothesis. c. Calculate the value for \(z \star\) and find the \(p\) -value d. State your decision and conclusion using \(\alpha=0.01\)

A high-tech company wants to estimate the mean number of years of college education its employees have completed. A good estimate of the standard deviation for the number of years of college is \(1.0 .\) How large a sample needs to be taken to estimate \(\mu\) to within 0.5 of a year with \(99 \%\) confidence?

When a parachute is inspected, the inspector is looking for anything that might indicate the parachute might not open. a. State the null and alternative hypotheses. b. Describe the four possible outcomes that can result depending on the truth of the null hypothesis and the decision reached. c. Describe the seriousness of the two possible errors.

A manufacturing process produces ball bearings with diameters having a normal distribution and a standard deviation of \(\sigma=0.04 \mathrm{cm} .\) Ball bearings that have diameters that are too small or too large are undesirable. To test the null hypothesis that \(\mu=0.50 \mathrm{cm},\) a sample of 25 is randomly selected and the sample mean is found to be 0.51. a. Design null and alternative hypotheses such that rejection of the null hypothesis will imply that the ball bearings are undesirable. b. Using the decision rule established in part a, what is the \(p\) -value for the sample results? c. If the decision rule in part a is used with \(\alpha=0.02\) what is the critical value for the test statistic?

The calculated \(p\) -value for a hypothesis test is 0.084 What decision about the null hypothesis would occur in the following? a. The hypothesis test is completed at the 0.05 level of significance. b. The hypothesis test is completed at the 0.10 level of significance.

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