Chapter 6: Problem 30
Find the probability that a piece of data picked at random from a normal population will have a standard score \((z)\) that lies between the following pairs of \(z\)-values: a. \(\quad z=-2.75\) to \(z=-1.38\) b. \(\quad z=0.67\) to \(z=2.95\) c. \(\quad z=-2.95\) to \(z=-1.18\)
Short Answer
Expert verified
The probabilities for data points within the given z score ranges are approximately: a) 8.08%, b) 25%, and c) 11.74%
Step by step solution
01
Analyze the First Pair
For pair \(a: \quad z=-2.75 \) to \( z=-1.38 \), find the area to the left of \( z= -2.75 \) and area to the left of \( z= -1.38 \) from the standard normal distribution table. The difference between these two areas gives the required probability in this interval.
02
Calculate First Pair Probability
From the table, \( P[Z \leq -2.75] \) is approximately 0.0030 and \( P[Z \leq -1.38] \) is approximately 0.0838. Therefore, the probability that a random data point will fall between -2.75 and -1.38 is \( P[-2.75 \leq Z \leq -1.38] = P[Z \leq -1.38] - P[Z \leq -2.75] = 0.0838 - 0.0030 = 0.0808 \approx 8.08 \% \).
03
Analyze the Second Pair
We proceed similarly with the second pair \(b: \quad z=0.67 \) to \( z=2.95 \). Find the area to the left of \( z=2.95 \) and left of \( z=0.67 \) from the standard normal distribution table.
04
Calculate Second Pair Probability
From the table, \( P[Z \leq 0.67] \) is approximately 0.7486 and \( P[Z \leq 2.95] \) is approximately 0.9986. Then, the probability that a random data point will fall between 0.67 and 2.95 is \( P[0.67 \leq Z \leq 2.95] = P[Z \leq 2.95] - P[Z \leq 0.67] = 0.9986 - 0.7486 = 0.25 = 25 \% \).
05
Analyze the Third Pair
Finally, with the third pair \(c: \quad z=-2.95 \) to \( z=-1.18 \), find the area to the left of \( z= -2.95 \) and \( z= -1.18 \) from the standard normal distribution table.
06
Calculate Third Pair Probability
From the table, \( P[Z \leq -2.95] \) is approximately 0.0016 and \( P[Z \leq -1.18] \) is approximately 0.1190. So, the probability that a random data point will fall between -2.95 and -1.18 is \( P[-2.95 \leq Z \leq -1.18] = P[Z \leq -1.18] - P[Z \leq -2.95] = 0.1190 - 0.0016 = 0.1174 \approx 11.74 \% \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Normal Distribution Table
The standard normal distribution table is a tool that helps us find probabilities associated with a standard normal distribution, also known as a "Z-distribution." This distribution has a mean of 0 and a standard deviation of 1, and it is a special case of the normal distribution. The table shows cumulative probabilities that a standard normal variable, denoted as \(Z\), is less than or equal to a given \(z\)-value.
- The table only provides values for \(Z\) from negative infinity up to any positive \(z\)-value.
- Each row corresponds to the first digit and the first decimal place of a \(z\)-value, while each column corresponds to the second decimal place.
- The intersection of the row and column gives the cumulative probability.
- Locate the desired \(z\)-value by finding the appropriate row and column intersection.
- Read off the cumulative probability associated with that \(z\)-value.
- The probability found is the area under the curve to the left of the \(z\)-value.
Z-values
Z-values, or \(z\)-scores, are standardized values that indicate where a data point is located in relation to the mean of a distribution. A \(z\)-score tells us how many standard deviations a data point is from the mean.
- A \(z\)-score of 0 means the data point is exactly at the mean.
- Positive \(z\)-scores indicate values above the mean, while negative \(z\)-scores indicate ones below the mean.
- \(x\) is the data point,
- \(\mu\) is the mean of the distribution,
- \(\sigma\) is the standard deviation of the distribution.
Probability Calculation
Probability calculations using the standard normal distribution are straightforward. Once you have the \(z\)-values for your data points, calculating the probability involves looking up these values on the standard normal distribution table.
Here's a step-by-step method to find the probability between two \(z\)-values, \(z_1\) and \(z_2\):1. Find the cumulative probability for \(z_1\) from the table, which gives \(P[Z \leq z_1].\)2. Similarly, find the cumulative probability for \(z_2\), \(P[Z \leq z_2].\)3. Subtract the smaller cumulative probability from the larger one:\[ P[z_1 \leq Z \leq z_2] = P[Z \leq z_2] - P[Z \leq z_1] \]4. The result is the probability of a data point falling between \(z_1\) and \(z_2\).
Here's a step-by-step method to find the probability between two \(z\)-values, \(z_1\) and \(z_2\):1. Find the cumulative probability for \(z_1\) from the table, which gives \(P[Z \leq z_1].\)2. Similarly, find the cumulative probability for \(z_2\), \(P[Z \leq z_2].\)3. Subtract the smaller cumulative probability from the larger one:\[ P[z_1 \leq Z \leq z_2] = P[Z \leq z_2] - P[Z \leq z_1] \]4. The result is the probability of a data point falling between \(z_1\) and \(z_2\).
- This method easily finds the probability of a range of data points without complex integration.
- Interpret the result as a percentage to express the likelihood of occurrence between these \(z\)-values.
Standard Score
Standard score, also known as a \(z\)-score, is a measure of how an individual data point relates to the mean of its distribution. It accounts for both the current data value and the variability (standard deviation) of the dataset.
- Standard scores allow comparison between different data sets by normalizing the data to the same scale.
- They make it clear how unusual or typical a data value is within its distribution.