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Find the mean and standard deviation for the binomial random variable \(x\) with \(n=30\) and \(p=0.6,\) using formulas (5.7) and (5.8).

Short Answer

Expert verified
The mean of the binomial distribution is 18 and the standard deviation is \( \sqrt{7.2} \).

Step by step solution

01

Find the Mean

Use formula 5.7 to calculate the mean (\( \mu \)). This formula is typically represented as follows: \( \mu = np \). Substituting given values we get \( \mu = 30 * 0.6 = 18 \). So, the mean of the binomial distribution is 18.
02

Find the Standard Deviation

Use formula 5.8 to calculate the standard deviation (\( \sigma \)). This formula is typically represented as follows: \( \sigma = \sqrt{np(1-p)} \). Substituting given values we get \( \sigma = \sqrt{30 * 0.6 * (1-0.6)} = \sqrt{7.2} \). So, the standard deviation of the binomial distribution is \( \sqrt{7.2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Binomial Distribution
In the realm of statistics, the mean of a binomial distribution is a crucial value, reflecting the average expected outcome for a set of trials. It is represented by the symbol \( \mu \). To calculate the mean of a binomial distribution, we apply the formula \( \mu = np \), where \( n \) is the number of trials and \( p \) is the probability of success on a single trial.

For instance, consider an experiment where you flip a coin 30 times and are interested in finding the number of times the coin lands on heads, assuming the probability of getting heads is 0.6. By using the formula above, you would multiply the number of trials \( n = 30 \) by the probability of success \( p = 0.6 \), resulting in a mean \( \mu = 30 \times 0.6 = 18 \). This mean, or expected value, implies that if you were to repeat this experiment many times, on average, you would get heads 18 times out of 30 coin flips.

Understanding the mean provides valuable insight into the behavior of the binomial random variable and helps in predicting outcomes over the long run.
Standard Deviation of Binomial Distribution
The standard deviation of a binomial distribution represents the degree to which individual outcomes spread out from the mean or expected value. It quantifies the variability or dispersion of the data. The symbol \( \sigma \) denotes the standard deviation, and it's calculated using the formula \( \sigma = \sqrt{np(1-p)} \).

Using the parameters from the previous example, with \( n = 30 \) trials and a success probability \( p = 0.6 \), we find the standard deviation by plugging these figures into the formula, obtaining \( \sigma = \sqrt{30 \times 0.6 \times (1-0.6)} = \sqrt{7.2} \). This tells us that in our coin flipping scenario, the number of times you get heads will typically vary by the square root of 7.2 from the mean value of 18.

Knowing the standard deviation helps determine how much the outcome can fluctuate, which is especially useful when assessing the reliability of the results or setting confidence intervals.
Binomial Random Variable
A binomial random variable is fundamentally associated with a binomial distribution, vital for statistical analysis when dealing with two possible outcomes, typically referred to as 'success' and 'failure'. The binomial random variable \( X \) records the number of successes achieved in a fixed number of independent trials, each with the same probability of success.

For example, if a basketball player shoots 30 free throws and the chance of making each shot is 0.6, the number of successful free throws is a binomial random variable. Each throw is independent, as the outcome of one does not affect the others, and there are only two outcomes: success (making the shot) or failure (missing it). The probabilistic model used to describe this scenario is the binomial distribution.

Grasping the concept of a binomial random variable enables students to effectively analyze scenarios where events have a discrete number of outcomes, aiding in numerous real-world applications, such as quality control testing, opinion polls, and medical research.

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Most popular questions from this chapter

In a germination trial, 50 seeds were planted in each of 40 rows. The number of seeds germinating in each row was recorded as listed in the following table. $$\begin{array}{cc|cc}\begin{array}{c}\text { Number } \\\\\text { Germinated }\end{array} & \begin{array}{c}\text { Number } \\\\\text { of Rows }\end{array} & \begin{array}{c}\text { Number } \\\\\text { Germinated }\end{array} & \begin{array}{c}\text { Number } \\\\\text { of Rows }\end{array} \\\\\hline 39 & 1 & 45 & 8 \\\40 & 2 & 46 & 4 \\\41 & 3 & 47 & 3 \\\42 & 4 & 48 & 1 \\\43 & 6 & 49 & 1 \\\44 & 7 & & \\\\\hline\end{array}$$ a. Use the preceding frequency distribution table to determine the observed rate of germination for these seeds. b. The binomial probability experiment with its corresponding probability distribution can be used with the variable "number of seeds germinating per row" when 50 seeds are planted in every row. Identify the specific binomial function and list its distribution using the germination rate found in part a. Justify your answer. c. Suppose you are planning to repeat this experiment by planting 40 rows of these seeds, with 50 seeds in each row. Use your probability model from part b to find the frequency distribution for \(x\) that you would expect to result from your planned experiment. d. Compare your answer in part c with the results that were given in the preceding table. Describe any similarities and differences.

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