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A random variable that can assume any one of the integer values \(1,2, \ldots, n\) with equal probabilities of \(\frac{1}{n}\) is said to have a uniform distribution. The probability function is written \(P(x)=\frac{1}{n},\) for \(x=1,2,3, \ldots, n .\) Show that \(\mu=\frac{n+1}{2}\). $$\text { (Hint: }1+2+3+\cdots+n=[n(n+1)] / 2 .)$$

Short Answer

Expert verified
\(\mu = \frac{n+1}{2}\)

Step by step solution

01

Understanding the Expected Value

The expected value (mean) of a discrete random variable X, denoted by \(E(X)\) or \(\mu\), is the sum of the products of each outcome and its probability. For this exercise, we can write the formula for \(\mu\) as follows: \(\mu = \sum_{x=1}^{n} x*P(x)\) where \(P(x) = 1/n\).\n
02

Substitute the Probability into the Formula

Substitute \(P(x) = 1/n\) into the formula. We get: \(\mu = \sum_{x=1}^{n} x*(1/n) = (1/n) * \sum_{x=1}^{n} x\).\n
03

Using the Summation Formula

The sum of the first \(n\) natural numbers \(\sum_{x=1}^{n} x\) is given by the formula: \(\frac{n(n+1)}{2}\). Substitute this into the formula: \(\mu = \frac{1}{n} * \frac{n(n+1)}{2}\).\n
04

Simplify the Expression

Simplify the above expression to obtain the value for \(\mu\). The \(n\) in the numerator and denominator cancel out: \(\mu = \frac{n+1}{2}\).\n

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value is a fundamental concept in probability, representing the average outcome we would expect from a random process if it were repeated many times. In the realm of a uniform distribution, where every outcome has an equal chance of occurring, calculating the expected value becomes a matter of arithmetic harmony.

Imagine you are rolling a fair die with six sides. Each side, numbered from one to six, has an equal probability of \frac{1}{6}. The expected value, denoted by E(X) or \(\mu\), is calculated by multiplying each possible outcome by its probability and then adding up all those products. The formula looks like this: \(\mu = \sum_{x=1}^{n} x \times P(x)\).

It's like predicting the average roll of the die over a huge number of rolls. For a uniform distribution, this computation is pleasantly straightforward, as each integer value has the same weight in the average, leading to a neatly ordered result.
Discrete Random Variable
A discrete random variable is akin to a collection of sealed boxes, each bearing a numeric label, where only one box can be selected at a time. It can take on a countable number of distinct values, like flipping a coin (heads or tails), rolling a die (1 to 6), or drawing cards (1 to 52).

In our example, the random variable is the number that comes up when we 'roll' our 'n-sided die'. Since the variable can only take on the integers from 1 to \(n\), it gives us a list of possible outcomes, each with an associated probability of \(\frac{1}{n}\). The beauty of such variables in uniform distributions is their predictability; each outcome's chance is evenly spread, simplifying our calculations and interpretations.
Summation Formula
Diving into the summation formula feels like discovering a secret shortcut through a maze. Mathematics introduces this handy tool when we need to add up a long string of numbers in sequence. For example, the sum of the first \(n\) natural numbers, symbolized as \(\sum_{x=1}^{n} x\), is defined by a beautifully simple formula: \(\frac{n(n+1)}{2}\).

This formula is a powerhouse when we deal with uniform distributions, as it simplifies the process of calculating the expected value. Rather than adding up each integer from 1 to \(n\) individually, this formula bundles them into a neat package, allowing for swift and accurate computation—no matter how large \(n\) gets.
Probability Function
The probability function, a building block in the world of statistics, tells us the likelihood of each possible outcome in a random experiment. Think of it as a guidebook that describes how a random variable behaves.

For a discrete uniform distribution, the probability function is beautifully straightforward: \(P(x) = \frac{1}{n}\) for all integer values that the variable can assume. This function is democratic, giving each potential result the same chance of occurring. It's this equality that underpins the uniformity of the distribution and directs us towards an expected value that lies centrally within the range of possible outcomes.

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