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A binomial random variable is based on \(n=20\) and \(p=0.4 .\) Find \(\Sigma x^{2} P(x).\)

Short Answer

Expert verified
The value of \(\Sigma x^{2} P(x)\) for the given binomial random variable is 4.8.

Step by step solution

01

Identify Given Values

In the given exercise, it's mentioned that the variable is binomial with \(n\) equals 20, and \(p\) equals 0.4. These are the two parameters of a binomial distribution, where \(n\) is number of trials and \(p\) is the probability of success.
02

Understand the Problem

Here, we are asked to find the value of \(\Sigma x^{2} P(x)\) which is nothing but the variance of a binomial distribution. So we need to calculate the variance.
03

Use Variance Formula for Binomial Distribution

The variance formula for a binomial distribution is \( Var(X) = np(1-p) \). Substituting our given values of \(n\) and \(p\) into this formula, we get the variance = \( 20 * 0.4 * (1-0.4) \).
04

Calculate the Variance

On further calculation, we find our variance = \( 20 * 0.4 * 0.6 = 4.8 \). This is the value of \(\Sigma x^{2} P(x)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Random Variable
A binomial random variable represents the number of successes in a series of independent and identical trials. To properly understand this concept, let's examine the key characteristics that define it.

First, there must be a fixed number of trials, denoted as 'n.' In the context of our example, we have 20 trials. Each trial is an independent event; the result of one trial does not influence the outcome of another. Secondly, there are only two possible outcomes for each trial, commonly referred to as 'success' and 'failure.' In this scenario, 'success' may be a positive response that we're looking to record. Each outcome has a fixed probability that remains consistent from trial to trial - this probability of success is symbolized as 'p.'

To summarize, a trial system with a finite number of identical trials, each independent from the others and with only two possible outcomes, will follow the structure of a 'binomial' process, leading to a binomial random variable as a result when counting successes.
Probability of Success
Understanding the 'probability of success' is essential when dealing with binomial random variables. This probability, indicated as 'p,' can be described as the likelihood of encountering the desired outcome in each trial. In the given exercise, this probability is said to be 0.4, meaning there is a 40% chance of success in any given trial.

The concept of 'probability of success' is central to the binomial distribution, as it directly influences not only the expected value but also the variance and overall shape of the distribution. When 'p' is high, the distribution skews towards more successes; conversely, a low 'p' value will skew the distribution towards fewer successes.

For learners trying to get to grips with this concept, it is crucial to remember that 'p' is constant across all trials in a binomial experiment, which is a fundamental property that differentiates binomial situations from non-binomial scenarios.
Variance Formula
The variance of a binomial distribution measures the dispersion of the distribution, or in simpler terms, how spread out the successes are over the number of trials. The formula for variance is a pivotal tool, and it incorporates both the number of trials and the probability of success: \( Var(X) = np(1-p) \).

In our example, we use this formula to calculate the variance. With an 'n' of 20 and a 'p' of 0.4, the calculation becomes \( 20 \times 0.4 \times (1-0.4) \), which simplifies to \( 20 \times 0.4 \times 0.6 \), and results in a variance of 4.8. This indicates that, on average, the number of successes will vary by approximately 4.8 from the mean number of successes in our set of trials.

A practical tip for students is to think of the variance as a measure of uncertainty. If the variance is high, predicting the number of successes in a given trial becomes more difficult, whereas a low variance suggests predictability and less deviation from the average. Remembering this will help interpret the significance of the variance value calculated using the formula.

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Most popular questions from this chapter

The random variable \(\bar{x}\) has the following probability distribution: $$\begin{array}{l|ccccc}\hline \overline{\mathbf{x}} & 1 & 2 & 3 & 4 & 5 \\\\\boldsymbol{P}(\bar{x}) & 0.6 & 0.1 & 0.1 & 0.1 & 0.1 \\\\\hline\end{array}$$ a. Find the mean and standard deviation of \((\bar{x}).\) b. What is the probability that \(\bar{x}\) is between \(\mu-\sigma\) and \(\mu+\sigma ?\)

Did you ever buy an incandescent light bulb that failed (either burned out or did not work) the first time you turned the light switch on? When you put a new bulb into a light fixture, you expect it to light, and most of the time it does. Consider 8 -packs of 60 -watt bulbs and let \(x\) be the number of bulbs in a pack that "fail" the first time they are used. If 0.02 of all bulbs of this type fail on their first use and each 8 -pack is considered a random sample, a. List the probability distribution and draw the histogram of \(x.\) b. What is the probability that any one 8 -pack has no bulbs that fail on first use? c. What is the probability that any one 8 -pack has no more than one bulb that fails on first use? d. Find the mean and standard deviation of \(x .\) e. What proportion of the distribution is between \(\mu-\sigma\) and \(\mu+\sigma ?\) f. What proportion of the distribution is between \(\mu-2 \sigma\) and \(\mu+2 \sigma ?\) g. How does this information relate to the empirical rule and Chebyshev's theorem? Explain. h. Use a computer to simulate testing 1008 -packs of bulbs and observing \(x,\) the number of failures per 8 -pack. Describe how the information from the simulation compares with what was expected (answers to parts a-g describe the expected results). i. \(\quad\) Repeat part h several times. Describe how these results compare with those of parts a-g and with part h.

A USA Today Snapshot (March 4, 2009) presented a pie chart depicting how workers damage their laptops. Statistics were derived from a survey conducted by Ponemon Institute for Dell of 714 IT managers. Is this a probability distribution? Explain. $$\begin{array}{lc}\text { Reason for Damage to Laptop } & \text { Percentage (\%) } \\\\\hline \text { Spilled food or liquids } & 34 \\\\\text { Dropping them } & 28 \\\\\text { Not protecting during travel } & 25 \\\\\text { Worker anger } & 13 \\\\\hline\end{array}$$

Harris Interactive conducted a survey for Tylenol PM asking U.S. drivers what they do if they are driving while drowsy. The results were reported in a USA Today Snapshot on January \(18,2005,\) with \(40 \%\) of the respondents saying they "open the windows" to fight off sleep. Suppose that 35 U.S. drivers are interviewed. What is the probability that between 10 and 20 of the drivers will say they "open the windows" to fight off sleep?

In a germination trial, 50 seeds were planted in each of 40 rows. The number of seeds germinating in each row was recorded as listed in the following table. $$\begin{array}{cc|cc}\begin{array}{c}\text { Number } \\\\\text { Germinated }\end{array} & \begin{array}{c}\text { Number } \\\\\text { of Rows }\end{array} & \begin{array}{c}\text { Number } \\\\\text { Germinated }\end{array} & \begin{array}{c}\text { Number } \\\\\text { of Rows }\end{array} \\\\\hline 39 & 1 & 45 & 8 \\\40 & 2 & 46 & 4 \\\41 & 3 & 47 & 3 \\\42 & 4 & 48 & 1 \\\43 & 6 & 49 & 1 \\\44 & 7 & & \\\\\hline\end{array}$$ a. Use the preceding frequency distribution table to determine the observed rate of germination for these seeds. b. The binomial probability experiment with its corresponding probability distribution can be used with the variable "number of seeds germinating per row" when 50 seeds are planted in every row. Identify the specific binomial function and list its distribution using the germination rate found in part a. Justify your answer. c. Suppose you are planning to repeat this experiment by planting 40 rows of these seeds, with 50 seeds in each row. Use your probability model from part b to find the frequency distribution for \(x\) that you would expect to result from your planned experiment. d. Compare your answer in part c with the results that were given in the preceding table. Describe any similarities and differences.

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