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a. Explain what is meant by the statement: "When a single die is rolled, the probability of a 1 is \(\frac{1}{6} "\) b. Explain what is meant by the statement: "When one coin is tossed one time, there is a \(50-50\) chance of getting a tail."

Short Answer

Expert verified
a. The statement means that for each roll of a fair six-sided die, the chance of getting a 1 is one out of six possible outcomes. b. The statement means that in a single toss of a fair coin, the result 'tail' is as likely to occur as the result 'head'. There are two possible outcomes, and each has a 50% chance.

Step by step solution

01

Interpretation of Dice Rolling Statement

The statement 'When a single die is rolled, the probability of a 1 is \(\frac{1}{6}\)' means that for any single roll of a regular six-sided die, the chance of landing a 1 is one out of six possible equally likely outcomes. This is because a standard die has six faces, each denoted by numbers from 1 to 6, and each number has an equal chance of appearing on a single roll.
02

Understanding the Dice Rolling Probability

The probability of an event is the ratio of the number of ways the event can occur to the total number of equally likely outcomes. So, if all outcomes are equally likely (as in the case of a fair six-sided die), and there's just one 'favourable' outcome (getting a 1), then the probability is one out of six, which is usually represented as \(\frac{1}{6}\) in fraction form.
03

Interpretation of Coin Tossing Statement

'When one coin is tossed one time, there is a 50-50 chance of getting a tail' means that in a single toss of a fair coin, the two possible outcomes (tail or head) are equally likely to occur.
04

Understanding the Coin Tossing Probability

In a single toss of a fair coin, there are two possible outcomes: head or tail. So, if we want 'tail' (which is just one of the possible outcomes), then the probability is one out of two, which in percentage form is 50%. Hence the term 50-50 chance, which means the two outcomes are equally probable.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

dice probability
Dice probability refers to the chance of a specific outcome occurring when rolling a six-sided die. Each face of a die has an equal chance of facing upwards when rolled, because standard dice are fair. If we want to find the probability of landing on a specific number, such as 1, we consider the total number of possible outcomes and the number of favorable outcomes.

For a single die:
  • Total number of outcomes: 6 (being the numbers 1 through 6)
  • Number of favorable outcomes (for rolling a 1): 1
Therefore, the probability of rolling a 1 is the ratio of favorable outcomes to total outcomes, which is \( \frac{1}{6} \). This means that on average, if you were to roll the die many times, about one out of every six rolls would likely result in a 1. Yet, it’s crucial to remember that each roll is independent, meaning past rolls do not affect future ones.
coin toss probability
When it comes to tossing a coin, probability plays a similar role but with fewer outcomes compared to dice. A standard coin has two faces: heads and tails, both equally likely to show up on a toss. So, in any single toss of a fair coin, there are two possible outcomes. When someone mentions a "50-50 chance" of getting tails, it refers to this equality in likelihood.

In detail:
  • Total number of outcomes: 2 (heads or tails)
  • Number of favorable outcomes (for tails): 1
Thus, the probability of the coin landing on tails is \( \frac{1}{2} \), which can be expressed as 50%. This means half the time, you can expect to see a tail, assuming many tosses. Each coin toss is an independent event, much like dice rolls, meaning previous tosses do not impact the outcome of the next.
equally likely outcomes
Equally likely outcomes are key to understanding basic probability. This concept highlights that each potential result of an activity or experiment has the same chance of happening as the others. Whether referring to the roll of a die or a coin toss, each possible outcome is equally probable unless stated otherwise, especially when the die or coin is fair.

For example, in a six-sided die:
  • Each face numbered 1 through 6 is an equally likely outcome.
  • The chance of rolling any specific number is the same, \( \frac{1}{6} \).
In a coin toss:
  • Both heads and tails share an equal probability.
  • The chance of either outcome is \( \frac{1}{2} \).
This concept is fundamental in computing probabilities because it allows us to predict the likelihood of events by comparing the number of favorable outcomes to the total possible outcomes. By assuming equal likelihood, you can fairly calculate probabilities and make predictions about results in situations involving chance.

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Most popular questions from this chapter

Nobody likes paying taxes, but cheating is not the way to get out of it! It is believed that \(10 \%\) of all taxpayers intentionally claim some deductions to which they are not entitled. If \(9 \%\) of all taxpayers both intentionally claim extra deductions and deny doing so when audited, find the probability that a taxpayer who does take extra deductions intentionally will deny it.

Classify each of the following as a probability or a statistics problem: a. Determining how long it takes to handle a typical telephone inquiry at a real estate office b. Determining the length of life for the 100 -watt light bulbs a company produces c. Determining the chance that a blue ball will be drawn from a bowl that contains 15 balls, of which 5 are blue d. Determining the shearing strength of the rivets that your company just purchased for building airplanes e. Determining the chance of getting "doubles" when you roll a pair of dice

Using a coin, perform the experiment discussed on pages \(180-181 .\) Toss a coin 10 times, observe the number of heads (or put 10 coins in a cup, shake and dump them into a box, and use each toss for a block of 10), and record the results. Repeat until you have 200 tosses. Chart and graph the data as individual sets of 10 and as cumulative relative frequencies. Do your data tend to support the claim that \(P(\text { head })=\frac{1}{2} ?\) Explain.

If \(P(\mathrm{A})=0.4, P(\mathrm{B})=0.5,\) and \(P(\mathrm{A} \text { and } \mathrm{B})=0.1\) find \(P(\mathrm{A} \text { or } \mathrm{B})\)

Jason attends his high school reunion. Of the attendees, \(50 \%\) are female. Common knowledge has it that \(88 \%\) of people are right-handed. Being a lefthanded male, Jason knows that of a given crowd, only approximately \(6 \%\) are left-handed males. If Jason talks to the first person he meets at the reunion, what is the probability that the person is a male or lefthanded?

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