/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 \( \mathrm{A}\) parts store sell... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\( \mathrm{A}\) parts store sells both new and used parts. Sixty percent of the parts in stock are used. Sixty-one percent are used or defective. If \(5 \%\) of the store's parts are defective, what percentage is both used and defective? Solve using a Venn diagram.

Short Answer

Expert verified
The percentage of parts both used and defective is \(4\% \).

Step by step solution

01

Identify provided values

Used parts represent \(60\% \) of total parts, defective parts represent \(5\% \) of total. The percentage parts that are used or defective is \(61\% \). The unknown value \(X\%\) represents the parts that are both used and defective.
02

Apply the formula for the union of two sets

Substitute the known values into the formula: \(61\% = 60\% + 5\% - X\%\). This simplifies to: \(61\% = 65\% - X\%\).
03

Solve for X

Add \(X\% \) and subtract \(61\% \) from both sides of the equation: \(X\% = 65\% - 61\% = 4\% \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Sets
When we talk about the 'union of sets' in statistics and mathematics, we refer to the combination of different groups, taking all the unique members from each group without duplication. The Venn diagram is a perfect visual aid for understanding unions, as it helps visualize the overlap and exclusive parts of each set.

The classical representation includes circles that overlap for common members and do not overlap for exclusive ones. When two sets A and B are combined, the union is denoted as A ∪ B and includes everything in A, everything in B, and all elements they share.

To calculate the union's size, we can add the sizes of each set and then subtract the intersection's size, because those are counted twice when we add the sizes of A and B. Remember, the formula for the union of two sets is:
\[ |A \cup B| = |A| + |B| - |A \cap B| \]
Here, |A| and |B| are the sizes of sets A and B respectively, and |A ∩ B| is the size of their intersection. In the store's parts example, this formula is applied to prevent double counting of the parts that are both used and defective.
Percentages in Statistics
Percentages play a critical role in statistics by allowing us to express proportions and comparisons in a universally understood way. When dealing with percentages, it's essential to remember that they are based on a whole of 100%. So, if a part store has 60% used parts, it means that out of every 100 parts, 60 are used.

This becomes incredibly useful when comparing data. In our case, understanding that 61% of parts are either used or defective, and 5% are defective, helps to make sense of the store's inventory. Converting these percentages to a common baseline (100%) enables one to interpret and analyze the data effortlessly.

Another key point is that percentages can overlap, which is where the concept of the union of sets intersects with percentages in statistics. When parts are categorized as 'used' or 'defective', there may be a percentage that falls into both categories, necessitating an adjustment in our calculations to avoid redundancy.
Solving for Unknown in Statistics
Solving for unknown values is a common problem in statistics. This often involves setting up an equation based on the given information and then rearranging and simplifying it to solve for the unknown variable.

In the parts store scenario, we used a fundamental property of set theory in conjunction with statistics to find the percentage of parts that are both used and defective. We began with the formula representing the union of two sets and inserted the given percentages:
\[ 61\% = 60\% + 5\% - X\% \]
Then we rearranged the equation to solve for the unknown variable, which represents the intersection of the two sets - the parts that are both used and defective. With simple subtraction, we determined X%, representing the overlap in the Venn diagram.

Understanding how to manipulate percentages and apply set theory principles is key in statistics. It allows you to uncover hidden information, such as overlapping categories or shared characteristics within the data you're working with.

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Most popular questions from this chapter

A traffic analysis at a busy traffic circle in Washington, DC, showed that 0.8 of the autos using the circle entered from Connecticut Avenue. Of those entering the traffic circle from Connecticut Avenue, 0.7 continued on Connecticut Avenue at the opposite side of the circle. What is the probability that a randomly selected auto observed in the traffic circle entered from Connecticut and will continue on Connecticut?

A and B are events defined on a sample space, with \(P(\mathrm{B})=0.5\) and \(P(\mathrm{A} \text { and } \mathrm{B})=0.4 .\) Find \(P(\mathrm{A} | \mathrm{B})\)

Union officials report that \(60 \%\) of the workers at a large factory belong to the union, \(90 \%\) make more than \(12\) per hour, and \(40 \%\) belong to the union and make more than \(12\) per hour. Do you believe these percentages? Explain. Solve using a Venn diagram.

A shipment of grapefruit arrived containing the following proportions of types: \(10 \%\) pink seedless, \(20 \%\) white seedless, \(30 \%\) pink with seeds, and \(40 \%\) white with seeds. A grapefruit is selected at random from the shipment. Find the probability of these events: a. It is seedless. b. It is white. c. It is pink and seedless. d. It is pink or seedless. e. It is pink, given that it is seedless. f. It is seedless, given that it is pink.

If \(P(A)=0.3\) and \(P(B)=0.4\) and \(A\) and \(B\) are independent events, what is the probability of each of the following? a. \(\quad P(A \text { and } B)\) b. \(\quad P(\mathbf{B} | \mathbf{A})\) c. \(\quad P(\mathrm{A} | \mathrm{B})\)

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