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It is believed that \(3 \%\) of a clinic's patients have cancer. A particular blood test yields a positive result for \(98 \%\) of patients with cancer, but it also shows positive for \(4 \%\) of patients who do not have cancer. One patient is chosen at random from the clinic's patient list and is tested. What is the probability that if the test result is positive, the person actually has cancer?

Short Answer

Expert verified
The probability that if the test result is positive, the person actually has cancer is approximately \(43.04 \%\).

Step by step solution

01

Identify the Known Values

Let’s denote the events as follows: C = Patient has cancer, ¬C = Patient does not have cancer, T = Patient tests positive for cancer, ¬T = Patient test negative for cancer. From the problem, the known values are: \(P(C) = 0.03\), probability that a patient has cancer; \(P(¬C) = 1 - P(C) = 0.97\), probability that patient does not have cancer; \(P(T|C) = 0.98\), probability that a patient tests positive given that they have cancer and \(P(T|¬C) = 0.04\), probability that a patient tests positive given that they do not have cancer.
02

Apply Bayes' Theorem

We apply Bayes formula to find the probability that a patient has cancer given that he/she has tested positive. Bayes’ theorem is typically expressed as \(P(A|B) = \frac{P(B|A) * P(A)}{P(B)}\). In this case we need \(P(C|T)\), the probability that a patient has cancer, given that they tested positive. With Bayes' theorem, this can be found using \(P(C|T) = \frac{P(T|C) * P(C)}{P(T)}\).
03

Calculate the Probability \(P(T)\)

To calculate P(T), the probability that a patient tests positive, we use the Total Probability theorem. It states that if we have partitioned the sample space into events A1, A2, A3, .... An then \(P(B) = P(A1) * P(B|A1) + P(A2) * P(B|A2) + ... + P(An) * P(B|An)\). Here, event T is partitioned in to events C and ¬C. So, \(P(T) = P(C) * P(T|C) + P(¬C) * P(T|¬C)\). Plugging in the numbers gives \(P(T) = 0.03 * 0.98 + 0.97 * 0.04 = 0.0294 + 0.0388 = 0.0682\).
04

Substitute \(P(T)\) Into Bayes' Theorem

Substituting \(P(T) = 0.0682\) into Bayes’ theorem: \(P(C|T) = \frac{P(T|C) * P(C)}{P(T)} = \frac{0.98 * 0.03}{0.0682} = 0.4304\)
05

Interpret the Result

The result in this context means that if a patient's test results come back positive, there is approximately a \(43.04\%\) chance that the patient actually has cancer. This reflects the balance between the relatively low occurrence of cancer (3%) and the fairly high false positive rate (4%).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics that deals with the analysis of random events. It provides the foundation for calculating the likelihood of various outcomes. In our exercise, understanding probability theory enables us to determine if a patient has cancer, given specific test results.

Key concepts in probability include:
  • Random Variables: These are values that result from random phenomena.

  • Events: Specific outcomes or combinations of outcomes.

  • Probability Distributions: Functions that describe the likelihood of different outcomes occurring.

In the context of our exercise, identifying known values first makes it easier to apply formulas and calculate probabilities accurately.
Conditional Probability
Conditional probability is the probability of an event occurring, given that another event has already occurred. In our exercise, it's crucial for determining the probability that a patient has cancer if they tested positive.

The formula for conditional probability is:
  • \( P(A|B) = \frac{P(A \cap B)}{P(B)} \)

Here, the probability of event \( A \) given event \( B \) is expressed as the probability of both events occurring together, divided by the probability of event \( B \) alone.

In the context of the exercise, we denote \( C \) as having cancer, and \( T \) as testing positive. We need to find \( P(C|T) \), which is "the probability of having cancer given a positive test result." This finds precise application through Bayes' Theorem in this scenario.
False Positive Rate
The false positive rate is a critical concept in testing scenarios. It represents the probability of a test indicating a positive result when the condition being tested for is not present. In our exercise, it's the probability of the test indicating cancer when it is not present.

Understanding the false positive rate helps set realistic expectations around diagnostic tests. For example, a 4% false positive rate implies that among people who do not have cancer, 4% might still test positive for it.

This misleading result must be carefully considered alongside the test's sensitivity and specificity. The higher the false positive rate, the lower the test's reliability for diagnosing the actual condition without additional confirmatory testing.
Total Probability Theorem
The total probability theorem is essential for handling complex probability problems, especially when they involve different competing hypotheses or pathways leading to the same result.

The theorem states that if you have a partition of the sample space, you can find the probability of any event by summing up the probabilities of that event across each part of the partition. In this exercise, it helps us figure out \( P(T) \), the probability of a positive test result, irrespective of the actual medical condition.

We express this as:
  • \( P(T) = P(C) \cdot P(T|C) + P(eg C) \cdot P(T|eg C) \)

Here, we calculate the probability of testing positive by considering both cases: testing positive with cancer and testing positive without cancer. Applying this theorem ensures our calculations accurately reflect all possible outcomes.

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Most popular questions from this chapter

If \(P(A)=0.3\) and \(P(B)=0.4\) and \(A\) and \(B\) are independent events, what is the probability of each of the following? a. \(\quad P(A \text { and } B)\) b. \(\quad P(\mathbf{B} | \mathbf{A})\) c. \(\quad P(\mathrm{A} | \mathrm{B})\)

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