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Chebyshev's theorem guarantees that what proportion of a distribution will be included between the following: a. \(\quad \bar{x}-2 s\) and \(\bar{x}+2 s\) b. \(\quad \bar{x}-3 s\) and \(\bar{x}+3 s\)

Short Answer

Expert verified
a. At least 75% of data lies within 2 standard deviations of the mean. b. At least 88.9% of data lies within 3 standard deviations of the mean.

Step by step solution

01

Calculate the proportion within 2 standard deviations

Chebyshev's theorem states that the proportion of any distribution that is within k standard deviations of the mean is at least \(1-1/k^2\). Here, k=2. Therefore, the proportion of the distribution within 2 standard deviations of the mean is at least \(1-1/2^2 = 1 - 1/4 = 0.75\) or 75%.
02

Calculate the proportion within 3 standard deviations

Using Chebyshev's theorem again, but now with k=3. Hence, the proportion of the distribution within 3 standard deviations of the mean is at least \(1-1/3^2 = 1 - 1/9 \approx 0.889\) or about 88.9%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Distribution
Imagine you've just participated in a school race, and you're curious about the overall speed of all the runners. If you collect the speed of each participant and organize this data, you're starting to look at what statisticians call a statistical distribution. This is essentially a way of showing all the possible values or outcomes of a certain variable and how often they occur. In our race example, this could give you a list of speeds from the slowest to the fastest runner.

Most real-world data can be roughly categorized into certain distribution types like the well-known bell-shaped curve, also known as the normal distribution. Other common forms of distributions include uniform, binomial, Poisson, and exponential. Each type of distribution provides a different kind of information. For example, the normal distribution is symmetric and depicts data that clusters around a central mean or average, while an exponential distribution might be used to model the time until the next event occurs, like the time between arrivals in a queue.

Understanding the type of distribution you are dealing with is crucial, as it determines the statistical methods you would use to analyze the data. The characteristics of the distribution such as its shape, spread, and central tendency must be analyzed to draw meaningful conclusions from the data.
Standard Deviation
Statistics has its own way of expressing how spread out the speeds of our runners are - it's called the standard deviation (denoted as s). Think of it like a measure of how much variation there is from the average (mean) speed. A small standard deviation means that most of the runners' speeds are close to the average speed, resulting in a tighter group of runners. A high standard deviation suggests a wider spread of speeds and a more varied group of runner performances.

Mathematically, to find the standard deviation, you would first find the mean speed, then calculate the difference of each runner's speed from the mean, square those differences, average them, and finally, take the square root of that average. This sounds complex, but it gives you a powerful piece of information. With the standard deviation, you can start to predict how varied future races might be. For instance, you could expect that in most races, a certain percentage of runners will run within a range around the average speed, depending upon the calculated standard deviation.
Mean of a Distribution
Back to the race: once you've timed all the runners, you calculate the mean of their speeds to find out the average speed. In the realm of statistics, the mean is the central value of a distribution and is a measure of the central tendency. To calculate it, you simply add up all the times of the runners and divide by the number of runners. This average represents the distribution's center and is used as a reference point to measure the deviations of each individual runner's speed.

Knowing the mean is crucial, especially when paired with the standard deviation. The mean tells you the central point of the data, but without understanding how much the data varies (which is indicated by the standard deviation), the mean can be misleading. For example, if one race had runners with very different speeds, and another race had runners with almost identical speeds, both could have the same mean speed. Yet, their distributions would look very different, which is where understanding both the mean and the standard deviation gives you a more complete picture of the data.

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Most popular questions from this chapter

The U.S. Census Bureau posted the following 2006 Report on America's Families and Living Arrangements for all races. $$\begin{array}{cc} \text { No. in Household } & \text { Percentage } \\ \hline 1 & 27 \% \\ 2 & 33 \% \\ 3 & 17 \% \\ 4 & 14 \% \\ 5 & 6 \% \\ 6 & 2 \% \\ 7+ & 1 \% \\ \hline \end{array}$$ a. Draw a relative frequency histogram for the number of people per household. b. What shape distribution does the histogram suggest? c. Based on the graph, what do you know about the households in the United States?

Oulliers 1 How often do they occur? What do we do with them? Complete part a to see how often outliers can occur. Then complete part b to decide what to do with outliers. a. Use the technology of your choice to take samples of various sizes \((10,30,100,300\) would be good choices) from a normal distribution (mean of 100 and standard deviation of 20 will work nicely) and see how many outliers a randomly generated sample contains. You will probably be surprised. Generate 10 samples of each size for a more representative result. Describe your results-in particular comment on the frequency of outliers in your samples. In practice, we want to do something about the data points that are discovered to be outliers. First, the outlier should be inspected: if there is some obvious reason why it is incorrect, it should be corrected. (For example, a woman's height of 59 inches may well be entered incorrectly as 95 inches, which would be nearly 8 feet tall and is a very unlikely height.) If the data value can be corrected, fix it! Otherwise, you must weigh the choice between discarding good data (even if they are different) and keeping erroneous data. At this level, it is probably best to make a note about the outlier and continue with using the solution. To help understand the effect of removing an outlier value, let's look at the following set of data, randomly generated from a normal distribution \(N(100,20)\). $$\begin{array}{rrrrr} \hline 74.2 & 84.5 & 88.5 & 110.8 & 97.6 \\ 110.6 & 93.7 & 113.3 & 96.1 & 86.7 \\ 102.8 & 82.5 & 107.6 & 91.1 & 95.7 \\ 100.2 & 116.4 & 78.3 & 154.8 & 144.7 \\ 97.3 & 102.8 & 91.8 & 58.5 & 120.1 \\ 98.0 & 98.4 & 81.9 & 58.5 & 118.1 \\ \hline \end{array}$$ b. Construct a boxplot and identify any outliers. c. Remove the outlier and construct a new boxplot. d. Describe your findings and comment on why it might be best and less confusing while studying introductory statistics not to discard outliers.

The Rochester Raging Rhinos Professional Soccer Team is hoping for a good 2010 season. The blend of experienced and young, energetic players should make for a solid team. The current ages for the team are: $$\begin{array}{llllllllll} \hline 23 & 24 & 25 & 32 & 30 & 20 & 31 & 24 & 30 & 24 \\ 33 & 36 & 30 & 20 & 25 & 26 & 30 & 31 & 23 & 24 \\ \hline \end{array}$$ a. Construct a grouped frequency histogram using classes \(19-21,21-23,\) and so on. b. Describe the distribution shown in the histogram. c. Based on the histogram and its shape, what would you predict for the mean and the median? Which would be higher? Why? d. Compute the mean and median. Compare answers to your predicted values in part c. e. Which measure of central tendency provides the best measure of the center? Why?

A research study of manual dexterity involved determining the time required to complete a task. The time required for each of 40 individuals with disabilities is shown here (data are ranked): $$\begin{array}{rrrrrrrrrrr} \hline 7.1 & 7.2 & 7.2 & 7.6 & 7.6 & 7.9 & 8.1 & 8.1 & 8.1 & 8.3 & 8.3 \\ 8.4 & 8.4 & 8.9 & 9.0 & 9.0 & 9.1 & 9.1 & 9.1 & 9.1 & 9.4 & 9.6 \\ 9.9 & 10.1 & 10.1 & 10.1 & 10.2 & 10.3 & 10.5 & 10.7 & 11.0 & 11.1 & 11.2 \\ 11.2 & 11.2 & 12.0 & 13.6 & 14.7 & 14.9 & 15.5 & & & & \\ \hline \end{array}$$ a. Find \(Q_{1}\). b. Find \(Q_{2}\). c. Find \(Q_{3}\). d. Find \(P_{95}\). e. Find the 5 -number summary. f. Draw the box-and-whisker display.

Each year, NCAA college football fans like to learn about the up-and-coming freshman class of players. Following are the heights (in inches) of the nation's top 100 high school football players for 2009. $$\begin{array}{lllllllllllllll} \hline 73 & 75 & 71 & 76 & 74 & 77 & 74 & 72 & 73 & 72 & 74 & 72 & 74 & 72 & 72 \\ 78 & 73 & 76 & 75 & 72 & 77 & 76 & 73 & 72 & 76 & 72 & 73 & 70 & 75 & 72 \\ 71 & 74 & 77 & 78 & 74 & 75 & 71 & 75 & 71 & 76 & 70 & 76 & 72 & 71 & 74 \\ 74 & 71 & 72 & 76 & 71 & 75 & 79 & 78 & 79 & 74 & 76 & 76 & 76 & 75 & 73 \\ 74 & 70 & 74 & 74 & 75 & 75 & 75 & 75 & 76 & 71 & 74 & 75 & 74 & 78 & 72 \\ 73 & 71 & 72 & 73 & 72 & 74 & 75 & 77 & 73 & 77 & 75 & 77 & 71 & 72 & 70 \\ 74 & 76 & 71 & 73 & 76 & 76 & 79 & 77 & 74 & 78 & & & & & \\ \hline \end{array}$$ a. Construct a histogram and one other graph of your choice that display the distribution on heights. b. Calculate the mean and standard deviation. c. Sort the data into a ranked list. d. Determine the values of \(\bar{x} \pm s, \bar{x} \pm 2 s\) and \(\bar{x} \pm 3 s\) and determine the percentage of data within \(1,2,\) and 3 standard deviations of the mean. e. Do the percentages found in part d agree with the empirical rule? What does this imply? Explain. f. Do the percentages found in part d agree with Chebyshev's theorem? What does that mean? g. Does the graph show a distribution that agrees with your answers in part e? Explain. h. Utilize one of the "testing for normality" Technology Instructions on pages \(97-98\). Compare the results with your answer to part e.

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