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If \(n_{1}=40, p_{1}^{\prime}=0.9, n_{2}=50,\) and \(p_{2}^{\prime}=0.9:\) a. Find the estimated values for both \(n p\) 's and both \(n q^{\prime} \mathrm{s}\) b. Would this situation satisfy the guidelines for approximately normal? Explain.

Short Answer

Expert verified
a) The estimated values for \(n_1p_{1}^{\prime}\) and \(n_1q_{1}^{\prime}\) are 36 and 4, respectively, whereas for \(n_2p_{2}^{\prime}\) and \(n_2q_{2}^{\prime}\), the values are 45 and 5, respectively. b) Both situations do satisfy the conditions for being approximately normal because in both cases, the calculated values for \(np\) and \(nq\) are greater or equal to 5.

Step by step solution

01

Compute the \(np\) and \(nq\) for the first scenario

For the first scenario, since \(n_1=40\) and \(p_{1}^{\prime}=0.9\), we will use these values to compute for \(n_1p_{1}^{\prime}\) and \(n_1q_{1}^{\prime}\). Remember that \( q_{1}^{\prime} = 1 - p_{1}^{\prime} \). Thus, we get: \n\(n_1p_{1}^{\prime} = 40(0.9) = 36 \)\nand \(n_1q_{1}^{\prime} = 40(1-0.9) = 4\).
02

Compute the \(np\) and \(nq\) for the second scenario

For the second scenario, where \(n_2=50\) and \(p_{2}^{\prime}=0.9\), we will calculate \(n_2p_{2}^{\prime}\) and \(n_2q_{2}^{\prime}\). Remember that \( q_{2}^{\prime} = 1 - p_{2}^{\prime} \). We get:\n\(n_2p_{2}^{\prime} = 50(0.9) = 45 \)\nand \(n_2q_{2}^{\prime} = 50(1 - 0.9) = 5\).
03

Check the conditions for the distributions to be approximately normal

We need to check if both scenarios satisfy the conditions to be considered approximately normal. The conditions state that both \(np\) and \(nq\) must be greater or equal to 5. Now, we can see that in both scenarios, the calculated values for \(np\) and \(nq\) are all greater or equal to 5. Therefore, both situations satisfy the conditions and their distributions can be considered approximately normal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Approximation
Normal approximation is a useful technique when dealing with probability distributions, particularly the binomial distribution. The idea is that under certain conditions, the binomial distribution can be approximated by the normal distribution. This gives us a simpler way to perform calculations, especially when the number of trials is large and calculations become cumbersome.
The basic rule for normal approximation is \ extit{"If the sample size is large enough, the shape of the binomial distribution becomes more like a normal distribution."}\ To determine this, we look at the products \( np \) and \( nq \), where \( n \) is the number of trials, \( p \) is the probability of success, and \( q \) is the probability of failure (\( q = 1 - p \)). If both \( np \) and \( nq \) are greater than or equal to 5, we can safely use normal approximation.
Using normal approximation helps us to utilize the standard normal distribution, making it easier to work out problems involving probabilities, like finding areas under the normal curve.
Binomial Distribution
The binomial distribution is a key concept in statistics, and it models the number of successes in a fixed number of independent, binary trials. Each trial has only two possible outcomes, often labeled as "success" and "failure".
Three key parameters define a binomial distribution:
  • The number of trials \( n \), which is the total number of observations or experiments.
  • The probability of success \( p \) in each trial.
  • The probability of failure \( q \), where \( q = 1 - p \).
Binomial distribution lets you calculate the probability of obtaining a certain number of successes in \( n \) trials. It's a powerful tool when calculating probabilities over multiple trials, like flipping a coin, determining defective parts in manufacturing, or more complex events.
For small sample sizes, manual computation of probabilities can be straightforward. However, as sample size increases, the calculations become complicated, leading us to consider approximations, such as the normal approximation, under appropriate conditions.
Statistical Guidelines
Statistical guidelines play an essential role in determining the appropriate methods and formulas when dealing with statistical problems. When using approximations or certain distributions, specific guidelines must be adhered to ensure accurate and reliable results.
For the normal approximation of the binomial distribution, key guidelines include:
  • Both \( np \) and \( nq \) should be greater than or equal to 5. This checks that the distribution's shape is sufficiently bell-shaped, much like the normal curve.
  • The number of trials \( n \) should be large enough so that the binomial distribution resembles a normal distribution.
Understanding and following these statistical guidelines help ensure that we apply the right techniques under appropriate conditions. This minimizes errors and improves accuracy in making statistical inferences or predictions.
Adhering to these guidelines is important in both academic homework settings and real-world statistical analysis, providing a solid foundation for robust statistical conclusions.

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Most popular questions from this chapter

A typical month, men spend \(\$ 178\) and women spend \(\$ 96\) on leisure activities," according to the results of an International Communications Research (ICR) for American Express poll, as reported in a USA Today Snapshot found on the Internet June 25,2005 Suppose random samples were taken from the population of male and female college students. Each student was asked to determine his or her expenditures for leisure activities in the prior month. The sample data results had a standard deviation of \(\$ 75\) for the men and a standard deviation of \(\$ 50\) for the women. a. If both samples were of size \(20,\) what is the standard error for the difference of two means? b. Assuming normality in leisure activity expenditures, is the difference found in the ICR poll significant at \(\alpha=0.05\) if the samples in part a are used? Explain.

Show that the standard error of \(p_{1}^{\prime}-p_{2}^{\prime},\) which is \(\sqrt{\left(\frac{p_{1} q_{1}}{n_{1}}\right)+\left(\frac{p_{2} q_{2}}{n_{2}}\right)},\) reduces to \(\sqrt{p q\left[\left(\frac{1}{n_{1}}\right)+\left(\frac{1}{n_{2}}\right)\right]}\) when \(p_{1}=p_{2}=p\)

Use a computer to demonstrate the truth of the statement describing the sampling distribution of \(\bar{x}_{1}-\bar{x}_{2}\) Use two theoretical normal populations: \(N_{1}(100,20)\) and \(N_{2}(120,20)\) a. To get acquainted with the two theoretical populations, randomly select a very large sample from each. Generate 2000 data values, calculate mean and standard deviation, and construct a histogram using class boundaries that are multiples of one-half of a standard deviation (10) starting at the mean for each population. b. If samples of size 8 are randomly selected from each population, what do you expect the distribution of \(\bar{x}_{1}-\bar{x}_{2}\) to be like (shape of distribution, mean, standard error \() ?\) c. Randomly draw a sample of size 8 from each population, and find the mean of each sample. Find the difference between the sample means. Repeat 99 more times. d. The set of \(100\left(\bar{x}_{1}-\bar{x}_{2}\right)\) values forms an empirical sampling distribution of \(\bar{x}_{1}-\bar{x}_{2} .\) Describe the empirical distribution: shape (histogram), mean, and standard error. (Use class boundaries that are multiples of standard error from mean for easy comparison to the expected.) e. Using the information found in parts a-d, verify the statement about the \(\bar{x}_{1}-\bar{x}_{2}\) sampling distribution made on page 496 f. Repeat the experiment a few times and compare the results.

Determine the \(p\) -value for the following hypothesis tests for the difference between two means with population variances unknown. a. \(\quad H_{a}: \mu_{1}-\mu_{2}>0, n_{1}=6, n_{2}=10, t \star=1.3\) b. \(\quad H_{a}: \mu_{1}-\mu_{2}<0, n_{1}=16, n_{2}=9, t \star=-2.8\) c. \(\quad H_{a}: \mu_{1}-\mu_{2} \neq 0, n_{1}=26, n_{2}=16, t \star=1.8\) d. \(\quad H_{a}: \mu_{1}-\mu_{2} \neq 5, n_{1}=26, n_{2}=35, t *=-1.8\)

A study was conducted to determine whether or not there was equal variability in male and female systolic blood pressure readings. Random samples of 16 men and 13 women were used to test the experimenter's claim that the variances were unequal. MINITAB was used to calculate the standard deviations, \(F\star,\) and the \(p\) -value. Assume normality.

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