/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Let \(\left\\{f_{n}\right\\}\) b... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(\left\\{f_{n}\right\\}\) be a sequence of functions each of which is uniformly continuous on an open interval \((a, b) .\) If \(f_{n} \rightarrow f\) uniformly on \((a, b)\) can you conclude that \(f\) is also uniformly continuous on \((a, b) ?\)

Short Answer

Expert verified
Yes, the limit function \( f \) is uniformly continuous on \((a, b)\).

Step by step solution

01

Understand Uniform Continuity

A function is uniformly continuous on an interval if, for any \( \epsilon > 0 \), there exists a \( \delta > 0 \) such that for all \( x, y \in (a, b) \), if \( |x - y| < \delta \) then \( |f(x) - f(y)| < \epsilon \). This means the chosen \( \delta \) does not depend on the specific point in the interval.
02

Sequence of Uniformly Continuous Functions

Since \( \{f_n\} \) is a sequence of functions that are each uniformly continuous on \((a, b)\), for each \( n \), given any \( \epsilon > 0 \), there is a \( \delta_n > 0 \) such that for all \( x, y \in (a, b) \), \( |x-y| < \delta_n \) implies \( |f_n(x) - f_n(y)| < \epsilon \).
03

Uniform Convergence on Interval

The sequence \( f_n \rightarrow f \) uniformly on \((a, b)\) means that for every \( \epsilon > 0 \), there exists an \( N \) such that for all \( n \geq N \) and all \( x \in (a, b) \), \( |f_n(x) - f(x)| < \epsilon/3 \).
04

Uniform Continuity of Limit Function

To show \( f \) is uniformly continuous, choose \( \epsilon > 0 \) and use uniform convergence to find \( n_0 \) such that for all \(n \geq n_0\) and all \( x \), \( |f_n(x) - f(x)| < \epsilon/3 \). Since \( f_{n_0} \) is uniformly continuous, there is a \( \delta > 0 \) such that for all \( x, y \in (a, b) \), if \( |x - y| < \delta \), then \( |f_{n_0}(x) - f_{n_0}(y)| < \epsilon/3 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sequence of Functions
When dealing with a sequence of functions, you have a list of functions, usually denoted as \( \{f_n\} \). Each function within this sequence is identified by a subscript \( n \), which can be any natural number. The concept may seem like just a mathematical list, but it holds significance in analysis, particularly when examining how the functions behave as \( n \) increases.

Here's why sequences of functions are important:
  • They help in studying the pointwise and uniform convergence of functions.
  • They're crucial in understanding the development of functional equations and approximations.
  • They aid in exploring properties like continuity and differentiability that might 'transfer' across a sequence.
In analysis, we're often interested in what happens to the sequence as \( n \) approaches infinity. We ask questions such as: Does the sequence converge to a particular function? And if so, how? This sets the stage for discussing different types of convergence, each offering insights into how sequences behave—uniform convergence being a prime example.
Uniform Convergence
Uniform convergence is a stricter form of convergence that concerns sequences of functions. It's critical to distinguish it from pointwise convergence, which isn't as strong.


To say that \( \{f_n\} \) converges to a function \( f \) uniformly on an interval \((a, b)\), you need:
  • For every \( \epsilon > 0 \), there is an \( N \) such that, for all \( n \geq N \) and for all \( x \in (a, b) \), the difference \( |f_n(x) - f(x)| < \epsilon \).
The key point here is that the \( N \) you choose does not depend on \( x \). This is what makes uniform convergence notably more powerful than pointwise convergence.

Why does this matter?
  • Uniform convergence preserves the continuity of the limit function, assuming each \( f_n \) is continuous.
  • It simplifies error estimation in numerical methods, providing a uniform bound on the approximation error.
This type of convergence ensures that you do not have to worry about individual points behaving badly as \( n \) gets large. It provides a much wider guarantee of the behavior of the sequence.
Limit Function
The limit function of a sequence of functions \( \{f_n\} \) is essentially the function that \( f_n \) approaches as \( n \) becomes very large. When we say a sequence of functions converges to a limit function \( f \), we're looking for how the functions \( f_n \) come closer and closer to \( f \) as \( n \) increases.

With uniform convergence, once \( n \) reaches a certain point, every \( f_n \) is close enough to this limit function \( f \) uniformly across the entire interval. The concept of a limit function is crucial because:
  • It provides a target to compare every function in the sequence.
  • It maintains the same important properties (like continuity or differentiability) under uniform convergence.
  • Understanding the limit function helps in proving and deducing further properties about the sequence and its related functions.
For example, if every function \( f_n \) is continuous, and \( \{f_n\} \) converges uniformly to \( f \), then the limit function \( f \) is also continuous. This insight becomes much clearer when we see uniform convergence as ensuring a smooth transition from each \( f_n \) to \( f \) without any hiccups across the domain \((a, b)\).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.