Chapter 9: Problem 2
Examine the uniform limiting behavior of the sequence of functions $$ f_{n}(x)=x^{2} e^{-n x} $$ On what sets can you determine uniform convergence? On what sets can you determine uniform convergence for the sequence of functions \(n^{2} f_{n}(x) ?\)
Short Answer
Expert verified
Uniform convergence of \( f_n(x) \) holds on any interval \( [a, b] \) where \( a > 0 \); \( n^2 f_n(x) \) converges uniformly on \( [a, b] \) if \( a > 1/n \), but not uniformly as \( x \to 0 \).
Step by step solution
01
Define Uniform Convergence
A sequence of functions \( \{f_n(x)\} \) converges uniformly to \( f(x) \) on a set \( S \) if for every \( \epsilon > 0 \), there exists an \( N \) such that for all \( n > N \) and all \( x \in S \), \( |f_n(x) - f(x)| < \epsilon \).
02
Analyze \( f_n(x) = x^2 e^{-nx} \)
Consider the pointwise limit of \( f_n(x) = x^2 e^{-nx} \) as \( n \to \infty \). For each fixed \( x > 0 \), we have \( e^{-nx} \to 0 \), hence \( f_n(x) \to 0 \). The limit function \( f(x) = 0 \) for all \( x > 0 \).
03
Determine Uniform Convergence for \( f_n(x) \)
To check uniform convergence on a set \( [a, b] \subset (0, \infty) \), examine \( \sup_{x \in [a, b]} |x^2 e^{-nx}| \). For any \( a > 0 \), as \( n \to \infty \), \( x^2 e^{-nx} \to 0 \) uniformly because the exponential term \( e^{-nx} \) decays faster than the polynomial term \( x^2 \) grows. Therefore, uniform convergence holds on any interval \( [a, b] \) for \( a > 0 \).
04
Analyze Function \( n^2 f_n(x) = n^2 x^2 e^{-nx} \)
Now consider the function \( n^2 f_n(x) = n^2 x^2 e^{-nx} \). The behavior of this function heavily depends on the exponential term. As \( n \to \infty \), for a fixed \( x > 0 \), \( e^{-nx} \) still decays to zero, however, \( n^2 \) grows without bounds. This means the rate of decay needs to be considered carefully over different segments of \( x \).
05
Determine Uniform Convergence for \( n^2 f_n(x) \)
On any interval \( [a, b] \) with \( a > 1/n \), as \( n \to \infty \), the term \( e^{-nx} \to 0 \) faster than \( n^2 \) grows, which leads to uniform convergence to 0. However, near zero, i.e., on intervals \( \left[0, \frac{1}{n}\right] \), \( n^2 f_n(x) \) can grow very large due to the term \( n^2 \), making uniform convergence not possible on those intervals.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sequence of Functions
In mathematics, a sequence of functions is essentially a list of functions indexed by an integer value, usually denoted as \( \{f_n(x)\} \). Each \( f_n(x) \) is a function dependent on a specific number \( n \), which can change, making the sequence potentially infinite. These sequences are essential in understanding how functions behave not just individually, but as a collective set over particular domains.
Exploring sequences allows us to analyze the behavior of functions as they approach a limit, which can provide insights into continuity, differentiability, and integrability over certain intervals.
Exploring sequences allows us to analyze the behavior of functions as they approach a limit, which can provide insights into continuity, differentiability, and integrability over certain intervals.
- Sequences are foundational in concepts such as series and calculus.
- They help in understanding convergence properties, both pointwise and uniform.
Pointwise Convergence
Pointwise convergence describes a scenario where the sequence of functions \( \{f_n(x)\} \) converges at each point \( x \) in a particular set to a function \( f(x) \). For each specific point \( x \), accumulating all terms \( f_n(x) \) in the sequence approaches \( f(x) \) as \( n \) becomes exceedingly large.
This form of convergence focuses on the behavior of the functions at each specific value of \( x \), rather than over a whole interval.
This form of convergence focuses on the behavior of the functions at each specific value of \( x \), rather than over a whole interval.
- Through pointwise convergence in the sequence \( f_n(x) = x^2 e^{-nx} \), for fixed \( x > 0 \), the sequence tends to \( f(x) = 0 \) as \( e^{-nx} \to 0 \).
- Each \( f_n(x) \) becomes negligible compared to the polynomial growth \( x^2 \) because the exponential decay is dominant.
Exponential Functions
Exponential functions, characterized by expressions such as \( e^{-nx} \), represent a fundamental class of mathematical functions where the rate of decay or growth is proportional to the function's current value. In these scenarios, the base \( e \) remains constant, while the exponent varies and significantly affects the function's behavior.
- The function \( e^{-nx} \) helps define sequences that dramatically decrease, especially as \( n \) rises or \( x \) increases.
- The exponential term leads to rapid decay, overshadowing any linear or polynomial growth as exhibited in \( f_n(x) = x^2 e^{-nx} \).
Limit Function
A limit function \( f(x) \), in the context of sequences of functions, serves as the ultimate fixed point to which a sequence \( \{f_n(x)\} \) converges. This concept is central when considering convergence behavior, particularly when analyzing properties like continuity or integrability in calculus.
For the sequence given, \( f_n(x) = x^2 e^{-nx} \), as \( n \to \infty \), the limit function is \( f(x) = 0 \) for \( x > 0 \). This results because the exponential component \( e^{-nx} \) diminishes rapidly, overpowering any other component of \( f_n(x) \).
For the sequence given, \( f_n(x) = x^2 e^{-nx} \), as \( n \to \infty \), the limit function is \( f(x) = 0 \) for \( x > 0 \). This results because the exponential component \( e^{-nx} \) diminishes rapidly, overpowering any other component of \( f_n(x) \).
- Determining limit functions helps in assessing both pointwise and uniform convergence across function sequences.
- The behavior at different points \( x \) and intervals signifies how divergent or convergent a sequence is upon infinite evaluation.