Chapter 5: Problem 36
Suppose that $$ f(x)=\sum_{i=1}^{M} a_{i} \chi_{A_{i}} $$ where the \(A_{i}\) are intervals. Show that \(f\) is a step function; that is, that \(f\) assumes finitely many values, and for each \(b\) in the range of \(f\) the set \(f^{-1}(b)\) is a finite union of intervals or singleton sets. Where are the discontinuities of such a function?
Short Answer
Step by step solution
Definition of a Step Function
Recognize the Structure of f(x)
Show That f(x) Assumes Finitely Many Values
Identify f^{-1}(b) as Unions of Sets
Determine the Points of Discontinuity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Characteristic Function
- \( \chi_{A}(x) = 1 \) if \( x \) is in the set \( A \)
- \( \chi_{A}(x) = 0 \) if \( x \) is not in the set \( A \)
Piecewise Constant Function
This means it takes different constant values depending on the segment or interval \( x \) belongs to.
- Over interval \( A_1 \), \( f(x) \) takes the value of \( a_1 \)
- Over interval \( A_2 \), \( f(x) \) takes the value of \( a_2 \)
- And so on for each \( A_i \)
Discontinuities
When you move from one interval to another, the function switches from one constant value to another, causing a jump. This behavior is characteristic of step functions:
- Within an interval \( A_i \), the function value \( f(x) \) remains constant, and hence continuous.
- At the edges of interval \( A_i \), if \( f(x) \) changes its value, these points are the discontinuities.
Finite Union of Intervals
- If intervals \( A_1, A_2, \ldots, A_M \) are combined, their union is \( \bigcup_{i=1}^{M} A_i \).
- This union forms the domain where the characteristic functions contribute to \( f(x) \).
Preimage of a Function
- \( f^{-1}(b) = \{ x : f(x) = b \} \)
- For example, if \( f(x) = a_1 \) over interval \( A_1 \), the preimage \( f^{-1}(a_1) \) includes all \( x \) in \( A_1 \)