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Let \(x_{1}=\theta\) and define a sequence recursively by $$ x_{n+1}=\frac{x_{n}}{1+x_{n} / 2} $$ For what values of \(\theta\) is it true that \(x_{n} \rightarrow 0 ?\)

Short Answer

Expert verified
The sequence \(x_n\) converges to 0 for \(\theta < 2\).

Step by step solution

01

Understanding the Problem

We are given an initial term \(x_1 = \theta\) and a recursive sequence defined by \(x_{n+1} = \frac{x_n}{1 + x_n / 2}\). We need to find for which values of \(\theta\), the sequence converges to 0 as \(n\) approaches infinity.
02

Analyzing the Recursive Formula

The recursive formula \(x_{n+1} = \frac{x_n}{1 + x_n / 2}\) simplifies to \(x_{n+1} = \frac{2x_n}{2 + x_n}\). We need to analyze this fraction to determine the limiting behavior of the sequence when \(x_n > 0\).
03

Sequence Convergence Analysis

For the sequence to approach 0, \(x_{n+1} < x_n\) should hold for all \(n\). This occurs if \(\frac{2x_n}{2 + x_n} < x_n\), leading to the inequality \(0 < x_n < 2\). Therefore, if the initial \(x_1 = \theta < 2\), then \(x_n\) will keep decreasing and approach 0.
04

Conclusion of Convergence Condition

By analyzing the inequality, we conclude that the sequence \(x_n\) approaches 0 if the original term \(\theta = x_1 < 2\). If \(\theta \geq 2\), the sequence will not converge to 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Recursive Sequences
Recursive sequences are fundamental in mathematics. They offer a way to define sequences based on preceding terms, rather than a direct formula. A recursive formula allows you to express each term of a sequence as a function of its previous term. In our example, the sequence is defined recursively by \( x_{n+1} = \frac{x_n}{1 + x_n / 2} \). This means that each term depends on the one before it, using the given rule.

Understanding recursive sequences is crucial because they show up in various fields, including computer science, physics, and finance. They are used to model processes where each step depends on the previous one.
  • The initial term \( x_1 = \theta \) is given, which seeds the sequence.
  • Subsequent terms are computed using the recursive formula.
By calculating a few initial terms, you can usually discern the behavior of the sequence, leading to insights about its convergence or divergence.
Limit Behavior
Limit behavior of a sequence refers to what happens to the terms of the sequence as they go towards infinity. It's essential to understand whether the terms approach a specific value, grow without bound, or oscillate.

In our sequence \( x_{n+1} = \frac{x_n}{1 + x_n / 2} \), we are interested in the conditions under which the sequence approaches 0. This is a question about the limit behavior.
  • If the sequence converges to a limit as \( n \rightarrow \infty \), that limit can be 0, a finite number, or even infinity.
  • Checking if \( x_{n+1} < x_n \) is a common test for monotonic sequence convergence.
For the given sequence to converge to 0, the initial value \( \theta < 2 \) is essential. This ensures each term progressively gets smaller until it approaches zero as \( n \) becomes very large.
Sequence Analysis
Sequence analysis involves understanding and predicting the behavior of a sequence using various mathematical tools and techniques. In analyzing sequences like the one in our example, you often look for patterns, convergence, and the conditions under which these occur.

For the sequence defined as \( x_{n+1} = \frac{x_n}{1 + x_n / 2} \), we perform sequence analysis to find values of \( \theta \) that lead the sequence towards zero.
  • The recursive formula \( x_{n+1} = \frac{2x_n}{2 + x_n} \) can be analyzed for inequality: \( \frac{2x_n}{2 + x_n} < x_n \).
  • If rearranged, this inequality shows that the terms are decreasing if \( 0 < x_n < 2 \).
By ensuring the starting point \( x_1 = \theta < 2 \), we find that the sequence naturally approaches 0, as the terms are pulled smaller and smaller. This kind of analysis not only discovers the convergence condition but deepens the understanding of the recursive sequence's nature.

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Most popular questions from this chapter

Prove that if \(s_{n} \rightarrow \infty\) then \(-s_{n} \rightarrow-\infty\).

If a sequence \(\left\\{x_{n}\right\\}\) has the property that $$ \lim _{n \rightarrow \infty} x_{2 n}=\lim _{n \rightarrow \infty} x_{2 n+1}=\infty $$ show that the sequence \(\left\\{x_{n}\right\\}\) diverges to \(\infty\).

As a computer experiment compute the values of the sequence $$ s_{n}=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\cdots+\frac{1}{n} $$ for large values of \(n .\) Is there any indication in the numbers that you see that this sequence fails to converge or must be unbounded?

Which statements are true? (a) If \(\left\\{s_{n}\right\\}\) is unbounded then it is true that either \(\lim _{n \rightarrow \infty} s_{n}=\infty\) or else \(\lim _{n \rightarrow \infty} s_{n}=-\infty\) (b) If \(\left\\{s_{n}\right\\}\) is unbounded then \(\lim _{n \rightarrow \infty}\left|s_{n}\right|=\infty\). (c) If \(\left\\{s_{n}\right\\}\) and \(\left\\{t_{n}\right\\}\) are both bounded then so is \(\left\\{s_{n}+t_{n}\right\\}\). (d) If \(\left\\{s_{n}\right\\}\) and \(\left\\{t_{n}\right\\}\) are both unbounded then so is \(\left\\{s_{n}+t_{n}\right\\}\). (e) If \(\left\\{s_{n}\right\\}\) and \(\left\\{t_{n}\right\\}\) are both bounded then so is \(\left\\{s_{n} t_{n}\right\\}\). (f) If \(\left\\{s_{n}\right\\}\) and \(\left\\{t_{n}\right\\}\) are both unbounded then so is \(\left\\{s_{n} t_{n}\right\\}\). (g) If \(\left\\{s_{n}\right\\}\) is bounded then so is \(\left\\{1 / s_{n}\right\\}\). (h) If \(\left\\{s_{n}\right\\}\) is unbounded then \(\left\\{1 / s_{n}\right\\}\) is bounded.

What relation, if any, can you state for the lim sups and lim infs of a sequence \(\left\\{a_{n}\right\\}\) and one of its subsequences \(\left\\{a_{n_{k}}\right\\} ?\)

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