Chapter 2: Problem 2
Define a sequence \(\left\\{t_{n}\right\\}\) recursively by setting \(t_{1}=1\) and $$ t_{n}=\sqrt{t_{n-1}+1} $$ Does this sequence converge? To what?
Short Answer
Expert verified
The sequence converges to \( L = \frac{1 + \sqrt{5}}{2} \).
Step by step solution
01
Understanding the Sequence
The sequence is defined recursively, meaning each term depends on the previous term. We start with the first term defined as \(t_1 = 1\). The general term for \(n \geq 2\) is given by \(t_n = \sqrt{t_{n-1}+1}\). Our task is to determine whether this sequence has a limit and if so, find its limit.
02
Assume and Determine Limit
Let's assume the sequence \( \{t_n\} \) converges to a limit \( L \). If the sequence converges, the terms must approach \( L \). Thus, we have:\[ L = \sqrt{L + 1} \]We need to solve this equation for \( L \).
03
Solve the Limit Equation
Square both sides of the equation \( L = \sqrt{L + 1} \) to remove the square root:\[ L^2 = L + 1 \]Rearrange it to form a quadratic equation:\[ L^2 - L - 1 = 0 \]
04
Solve the Quadratic Equation
We solve the quadratic equation \( L^2 - L - 1 = 0 \) using the quadratic formula: \[ L = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Here, \( a = 1 \), \( b = -1 \), and \( c = -1 \). The solutions are:\[ L = \frac{1 \pm \sqrt{1 + 4}}{2} = \frac{1 \pm \sqrt{5}}{2} \]
05
Determine the Valid Solution
The solutions to the quadratic equation are \( L = \frac{1 + \sqrt{5}}{2} \) and \( L = \frac{1 - \sqrt{5}}{2} \). Since \( \{t_n\} \) consists of real and positive terms due to the square root function, we discard the negative solution. Therefore, \( L = \frac{1 + \sqrt{5}}{2} \), which is the positive root.
06
Confirm Convergence
To ensure convergence, we observe that each term \( t_n = \sqrt{t_{n-1} + 1} \) is greater than \( t_{n-1} \) when \( t_{n-1} < L \), suggesting an increasing sequence bounded above by \( L = \frac{1 + \sqrt{5}}{2} \). Thus, the sequence converges to the limit \( L \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Recursive Definition
In mathematics, a recursive definition is a way to define a sequence or a set where each term is computed using preceding terms. Different from an explicit definition, which provides a direct formula for any term, recursive definitions are built step-by-step.
- To start a recursive sequence, you need a base case, like \( t_1 = 1 \) in the example above.
- The relationship that ties each term to its predecessor is essential, as seen in \( t_n = \sqrt{t_{n-1} + 1} \), which means each term is the square root of the previous term plus one.
Limit of a Sequence
The limit of a sequence refers to the value the terms of a sequence approach as the index (typically denoted by \( n \)) becomes very large. If a sequence has a limit, it is called convergent, meaning its terms get progressively closer to a specific number.
To determine whether a recursive sequence like \( \{t_n\} \) converges:
To determine whether a recursive sequence like \( \{t_n\} \) converges:
- Assume it converges to a limit \( L \).
- Substitute \( L \) back into the recursive formula, replacing \( t_n \) to find a feasible solution that satisfies the equation \( L = \sqrt{L + 1} \).
Quadratic Equation
Quadratic equations are polynomial equations of the form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants. These equations are paramount in mathematics because they model many natural phenomena and processes.
In solving \( L = \sqrt{L + 1} \), we ended up with a quadratic equation, \( L^2 - L - 1 = 0 \), a typical form that results when solving recursive sequences for convergence.
Using the quadratic formula:
\[L = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]we found the possible values of \( L \). The solutions to this equation \( \frac{1 \pm \sqrt{5}}{2} \) give us potential limits of our sequence. We chose \( \frac{1 + \sqrt{5}}{2} \) as it fits the context where sequence terms are positive numbers.
In solving \( L = \sqrt{L + 1} \), we ended up with a quadratic equation, \( L^2 - L - 1 = 0 \), a typical form that results when solving recursive sequences for convergence.
Using the quadratic formula:
\[L = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]we found the possible values of \( L \). The solutions to this equation \( \frac{1 \pm \sqrt{5}}{2} \) give us potential limits of our sequence. We chose \( \frac{1 + \sqrt{5}}{2} \) as it fits the context where sequence terms are positive numbers.
Real Analysis
Real analysis is a field of mathematics focusing on real numbers and real-valued functions. It delves deep into various mathematical concepts such as limits, continuity, differentiation, and integration. Understanding sequences and their convergence is a fundamental topic in real analysis.
In the context of real analysis:
In the context of real analysis:
- We rigorously examine the behavior of sequences and series to determine if they approach a specific value as the number of terms grows.
- For a mathematician or student of real analysis, proving convergence and solving for limits like the one in \( \{t_n\} \) is essential.