Chapter 13: Problem 6
Verify the inclusions $$ \ell_{1} \subset \ell_{2} \subset \ell_{\infty} $$ for the sequence spaces in this section. Is any one of these a subspace of any other?
Short Answer
Expert verified
Yes, each space is a subspace of the next: \(\ell_1 \subset \ell_2 \subset \ell_\infty\).
Step by step solution
01
Understanding the Inclusion
First, we need to understand the definitions of the sequence spaces \(\ell_1\), \(\ell_2\), and \(\ell_\infty\). The space \(\ell_1\) consists of sequences whose absolute sum is finite: \[\ell_1 = \{ x = (x_n) : \sum_{n=1}^{\infty} |x_n| < \infty \}.\] The space \(\ell_2\) consists of sequences whose square sums are finite: \[\ell_2 = \{ x = (x_n) : \sum_{n=1}^{\infty} |x_n|^2 < \infty \}.\] The space \(\ell_\infty\) consists of bounded sequences: \[\ell_\infty = \{ x = (x_n) : \sup_n |x_n| < \infty \}.\] We now need to verify if these inclusions are correct.
02
Inclusion \(\ell_1 \subset \ell_2\)
Consider a sequence \(x = (x_n) \in \ell_1\), meaning \(\sum_{n=1}^{\infty} |x_n| < \infty\). For convergence of the sum of squares:\(|x_n|^2 \leq |x_n|\) (since each \(|x_n|\) is non-negative and if it converges, then surely its square is also finite if summed). Thus, \(\sum_{n=1}^{\infty} |x_n|^2 \leq \sum_{n=1}^{\infty} |x_n| < \infty\), proving \(x \in \ell_2\). Thus, \(\ell_1 \subset \ell_2\).
03
Inclusion \(\ell_2 \subset \ell_\infty\)
Consider \(x = (x_n) \in \ell_2\), which satisfies \(\sum_{n=1}^{\infty} |x_n|^2 < \infty\). If the square sum is finite, then \(x_n \to 0\) as \(n \to \infty\), implying that the terms must be bounded. As such, there exists some \(M\) such that \(|x_n| < M\). Therefore, \(x \in \ell_\infty\), showing that \(\ell_2 \subset \ell_\infty\).
04
Conclusion on Subspaces
From the steps above, we have shown that \(\ell_1 \subset \ell_2\) and \(\ell_2 \subset \ell_\infty\), meaning each space is a subspace of the succeeding space. Thus, each inclusion is correct, and the sets are subspaces of the next set in the sequence.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Subspace
In the context of sequence spaces, a subspace is essentially a smaller set that completely fits within a larger sequence space. When we say that one sequence space is a subspace of another, we're saying that every sequence in the smaller space (subspace) can also be found in the larger space. This is crucial when dealing with
- the notation \( \ell_1 \subset \ell_2 \subset \ell_{\infty} \),
- which implies that \( \ell_1 \) is a subspace of \( \ell_2 \) and \( \ell_2 \) is a subspace of \( \ell_{\infty} \).
Inclusion
In the world of sequence spaces, inclusion is a way of describing how one space fits into another. If a set \( A \) is included in set \( B \) (denoted as \( A \subset B \)), it means every element of \( A \) is also an element of \( B \).
This is what we're proving when we say \( \ell_1 \subset \ell_2 \subset \ell_{\infty} \).
This is what we're proving when we say \( \ell_1 \subset \ell_2 \subset \ell_{\infty} \).
- For instance, \( \ell_1 \) contains sequences whose elements, when summed absolutely, result in a finite number.
- When you move these sequences to \( \ell_2 \), they are still valid because their squared sums are finite.
- Likewise, given finiteness in \( \ell_2 \), these sequences can form part of \( \ell_{\infty} \) since they must tend towards zero, making them inherently bounded.
Convergence
Convergence refers to the behavior of a sequence as it approaches a fixed point or value as the index goes to infinity. In the context of sequence spaces:
- \( \ell_2 \), for example, demands that the sequence's element squares sum up to a finite number.
- As the elements of such sequences continue, they tend to grow smaller, approaching zero.
- This is an essential property of convergence.
Bounded Sequences
A bounded sequence is one where its elements do not exceed a certain absolute value, no matter how far along the sequence you go. In technical terms, for the space \( \ell_{\infty} \), a sequence \( (x_n) \) is bounded if there is some number \( M \) such that \( |x_n| < M \) for all \( n \). This boundedness is a critical concept for a few reasons:
- It ensures sequences within \( \ell_2 \) and \( \ell_{\infty} \) don't exhibit unrestrained growth.
- Bounded sequences in \( \ell_{\infty} \) accommodate those sequences from \( \ell_2 \) since the latter's elements asymptotically approach zero.