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In a metric space, show that every dense set of type \(\mathcal{G}_{\delta}\) is residual.

Short Answer

Expert verified
A dense \( \mathcal{G}_{\delta} \) set in a metric space is residual because its complement is of the first category (a countable union of nowhere dense sets).

Step by step solution

01

Define Metric Space Components

A metric space is a set \( X \) together with a metric \( d \). We are given a dense set \( D \) of type \( \mathcal{G}_{\delta} \) in this space. This means \( D \) can be expressed as a countable intersection of open dense sets, i.e., \( D = \bigcap_{n=1}^{\infty} U_n \), where each \( U_n \) is open and dense in \( X \).
02

Understand Residual Sets

A set is residual if its complement is of the first category, meaning it can be expressed as a countable union of nowhere dense sets. To show that \( D \) is residual, it suffices to show that the complement of \( D \), \( D^c = X \setminus D \), is of the first category.
03

Express the Complement

Since \( D = \bigcap_{n=1}^{\infty} U_n \), the complement is \( D^c = X \setminus \bigcap_{n=1}^{\infty} U_n = \bigcup_{n=1}^{\infty} (X \setminus U_n) \). Thus, \( D^c \) is a countable union of the complements of \( \mathcal{G}_{\delta} \) set's terms, each \( X \setminus U_n \).
04

Show Each Complement is Nowhere Dense

Since each \( U_n \) is dense in \( X \), the complement \( X \setminus U_n \) is nowhere dense. By definition, a set is nowhere dense if its closure has an empty interior. Since \( U_n \) is dense, any open set in \( X \) intersects \( U_n \), making \( X \setminus U_n \)'s interior empty.
05

Conclude with First Category

Since \( D^c = \bigcup_{n=1}^{\infty} (X \setminus U_n) \) and each \( X \setminus U_n \) is nowhere dense, \( D^c \) is indeed of the first category. Hence, \( D \) is residual, being the complement of a first category set.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dense Set
In the context of metric spaces, a dense set is a set where every point in the space is either in the set or is a limit point of the set. This means for any chosen point in the space, we can find a point in the dense set that is arbitrarily close. A simple example of a dense set is the set of rational numbers in the set of real numbers. Every real number can be approached as closely as desired by some rational number.
A special type of dense set is a \( \mathcal{G}_{\delta} \), which is an intersection of countable open dense sets. This combination often helps in advanced analysis and illustrates powerful properties in the topological structure of the space.
  • A dense set ensures proximity to all regions of the space.
  • \( \mathcal{G}_{\delta} \) dense sets are significant for their topological implications.
Residual Set
A residual set in a metric space is a set whose complement is of first category. This means the complement is a union of nowhere dense sets. Residual sets are important because their properties provide robust results in analysis, particularly in spaces like Baire spaces where residuality carries strong conclusions.
In the context of the given solution, when a dense set \( D \) is expressed as a \( \mathcal{G}_{\delta} \) set, its complement is shown to be a first category set, making \( D \) residual. This shows us that dense sets which meet certain conditions (i.e., being \( \mathcal{G}_{\delta} \)) possess a powerful nature, allowing us to infer meaningful properties about the space.
  • Residual sets encompass large "algebraic magnitude" within a space.
  • They allow mathematicians to derive strong results about the space's structure.
First Category
A set is of the first category (or meager) in a metric space if it is a countable union of nowhere dense sets. These kinds of sets are often considered small or negligible, especially in terms of topological magnitude. This is because nowhere dense sets have their closures with an empty interior, indicating sparse distribution.
In our problem, the complement of a \( \mathcal{G}_{\delta} \) dense set is shown to be first category, emphasizing its smallness relative to the residual set. It helps students understand the relationship between sparsity and density in a nuanced metric space.
  • First category sets are viewed as "small" because of their sparse nature.
  • Understanding first category sets aids in comprehending the full breadth of a metric space.
Nowhere Dense Set
A nowhere dense set is a set whose closure has an empty interior. Practically, this means the set cannot contain any open ball or area in the space, illustrating a highly scattered distribution.
These sets, when unioned countably, form sets of the first category. In our specific context, each complement of \( U_n \) was nowhere dense, thus allowing the complement of the \( \mathcal{G}_{\delta} \) set to be a first category set.
Nowhere dense sets allow students to think about how space can be sparsely filled and how that interacts with dense sets, giving new insights into the distribution of elements in a manifold.
  • They illustrate sparse and scattered distribution.
  • Nowhere dense sets provide the building blocks for first category sets.

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Most popular questions from this chapter

Prove this special version of the intermediate value theorem: If \(f\) is a differentiable function on the interval \([a, b]\) with \(f(a)<0

This problem requires a bit of knowledge about complex numbers and transcendental numbers. We exhibit two sets \(R\) and \(T\) in \(\mathbb{R}^{2}\) such that \(R\) and \(T\) are congruent and each is congruent to their union \(S=R \cup T\). For each complex number \(z\), let \(t(z)=z+1, r(z)=e^{i} z\). Thus \(t\) is just a right translation by 1 unit and \(r\) is a rotation by 1 radian. Let \(S\) consist of those points that can be obtained by a finite number of applications of \(t\) and \(r\) starting from the origin. Each member of \(S\) can be represented as a polynomial in \(e^{i}\) with positive integer coefficients. (For example, if we translate five times, then rotate twice, then translate once more, the resulting point can be represented as \(5 e^{2 i}+1 .\) Since \(e^{i}\) is transcendental, the representation is unique. Let \(R\) consist of those points that have no constant term in their representation, and let \(T=S \backslash R\). Prove that \(t(S)=T\) and \(r(S)=R\) so \(R, T\) and \(S=R \cup T\) are pairwise isometric. Note that the isometries involved are isometries of \(\mathbb{R}^{2}\) onto \(\mathbb{R}^{2}\), not just isometries among the sets \(R, S\), and \(T\).

Let \(\mathcal{C}^{1}[a, b]\) consist of the continuously differentiable functions on \([a, b]\). Define for \(f, g \in \mathcal{C}^{1}[a, b]\) $$d(f, g)=\max _{a \leq t \leq b}|f(t)-g(t)|+\max _{a \leq t \leq b}\left|f^{\prime}(t)-g^{\prime}(t)\right|$$ (a) Prove that \(d\) is a metric. (b) Let \(D: \mathcal{C}^{1}[a, b] \rightarrow \mathcal{C}[a, b]\) be defined by \(D(f)=f^{\prime}\). Prove that \(D\) is continuous. (Here, as usual, \(\mathcal{C}[a, b]\) has the sup metric.)

Let \(\sigma\) be continuous and nondecreasing on \([0, \infty)\), with \(\sigma(0)=0\). A function \(f \in \mathcal{C}[a, b]\) has modulus of continuity \(\sigma\) if $$ |f(x)-f(y)| \leq \sigma(|x-y|) $$ for all \(x, y \in[a, b] .\) Let \(\boldsymbol{C}(\sigma)\) denote \(\\{f: \sigma\) is a modulus of continuity for \(f\\}\). (a) Show that every \(f \in \mathcal{C}[a, b]\) has a modulus of continuity. (b) Let \(\sigma\) be a modulus of continuity. Show that \(\boldsymbol{C}(\sigma)\) is an equicontinuous family. (c) Exhibit a modulus of continuity for the class of Lipschitz functions with constant \(M\). (d) Let \(\sigma\) be a modulus of continuity. Is it necessarily true that \(\sigma \in\) \(\boldsymbol{C}(\sigma)\) on \([a, b] ?\) What if \(\sigma\) is concave down? (e) Prove that the set $$ K=\\{f \in \mathcal{C}[0,1]:|f(x)-f(y)| \leq \sqrt{|x-y|} \text { and } f(0)=0\\} $$ is a compact subset of \(\mathcal{C}[0,1] .\) Is \(\sqrt{x} \in K ?\) What about \(x^{2} ?\)

Show that $$ Y=\\{f \in M[a, b]: f \text { is one-to-one }\\} $$ is a residual subset of the space \(M[a, b]\) of bounded functions on \([a, b]\).

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