Chapter 11: Problem 3
Show that the function \(f(\mathbf{x})=\|\mathbf{x}\|\) is uniformly continuous on \(\mathbb{R}^{n}\).
Short Answer
Expert verified
The Euclidean norm function \( f(\mathbf{x}) = \| \mathbf{x} \| \) is uniformly continuous on \( \mathbb{R}^n \) since \( |\|\mathbf{x}\| - \|\mathbf{y}\|| \leq \|\mathbf{x} - \mathbf{y}\| \).
Step by step solution
01
Recall the definition of uniform continuity
A function \( f : A \to \mathbb{R} \) is uniformly continuous on \( A \) if for every \( \epsilon > 0 \) there exists a \( \delta > 0 \) such that for all \( \mathbf{x}, \mathbf{y} \in A \), if \( \| \mathbf{x} - \mathbf{y} \| < \delta \), then \( |f(\mathbf{x}) - f(\mathbf{y})| < \epsilon \).
02
Consider the Euclidean norm function
The function \( f(\mathbf{x}) = \| \mathbf{x} \| \) is the Euclidean norm of \( \mathbf{x} \) in \( \mathbb{R}^n \), which measures the distance from the origin to the point \( \mathbf{x} \).
03
Use the triangle inequality
Recall the triangle inequality, which states \( \| \mathbf{x} \| \leq \| \mathbf{x} - \mathbf{y} \| + \| \mathbf{y} \| \). Applying this, we have \( |\|\mathbf{x}\| - \|\mathbf{y}\|| \leq \|\mathbf{x} - \mathbf{y}\| \).
04
Show boundedness
For any \( \mathbf{x}, \mathbf{y} \in \mathbb{R}^n \), from the last inequality, \(|\| \mathbf{x} \| - \| \mathbf{y} \|| < \epsilon\) whenever \(\| \mathbf{x} - \mathbf{y} \| < \epsilon\).
05
Conclude uniform continuity
From Step 4, given any \( \epsilon > 0 \), we choose \( \delta = \epsilon \). Then for all \( \mathbf{x}, \mathbf{y} \in \mathbb{R}^n \), \(|\| \mathbf{x} \| - \| \mathbf{y} \|| < \epsilon\) whenever \(\| \mathbf{x} - \mathbf{y} \| < \delta\). Thus, \( f(\mathbf{x}) = \| \mathbf{x} \| \) is uniformly continuous.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Euclidean Norm
The Euclidean norm is a way to measure the length or size of a vector in Euclidean space. It is also commonly known as the Euclidean length or simply as norm. The Euclidean norm of a vector \( \mathbf{x} = (x_1, x_2, \ldots, x_n) \) in \( \mathbb{R}^n \) is denoted by \( \| \mathbf{x} \| \) and is calculated using the formula:\[\| \mathbf{x} \| = \sqrt{x_1^2 + x_2^2 + \cdots + x_n^2}\]
- Intuitive Explanation: Think of it as the straight-line distance from the origin \((0, 0, \ldots, 0)\) to the point \( \mathbf{x} \) in \( n \)-dimensional space.
- Example: For a 2-dimensional vector \( \mathbf{x} = (3, 4) \), the Euclidean norm is \( \sqrt{3^2 + 4^2} = 5 \).
Triangle Inequality
The triangle inequality is an essential property in mathematics that relates to the lengths of sides in a triangle. In the context of vector spaces, it states that for any vectors \( \mathbf{x} \) and \( \mathbf{y} \), the following inequality holds:\[\| \mathbf{x} + \mathbf{y} \| \leq \| \mathbf{x} \| + \| \mathbf{y} \|\]
- Why It's Important: This inequality is a critical tool for proving various properties about norms, including continuity and boundedness because it highlights how the length of a vector sum cannot exceed the sum of the individual vector lengths.
- Application: The triangle inequality is used in the solution to show that \( |\| \mathbf{x} \| - \| \mathbf{y} \|| \leq \| \mathbf{x} - \mathbf{y} \| \). This helps demonstrate that the function \( f(\mathbf{x}) = \| \mathbf{x} \| \) is uniformly continuous.
Boundedness
Boundedness refers to the idea that a function or a set does not stretch infinitely, and there exists a limit or boundary beyond which it cannot go. Specifically, for a function to be uniformly continuous, it needs to behave in a well-controlled manner over its entire domain.
- Uniform Continuity: A concept closely tied to boundedness, uniform continuity of a function \( f \) means there is a consistent level of change across the entire domain, such that if inputs are within a certain small distance \( \delta \), outputs stay within a small range \( \epsilon \).
- In Context: In the given exercise, the concept of boundedness was used to illustrate that the change \( |\| \mathbf{x} \| - \| \mathbf{y} \|| \) remains bounded by \( \epsilon \), whenever the inputs \( \mathbf{x} \) and \( \mathbf{y} \) are within a distance \( \delta = \epsilon \) of each other.
- Practical Insight: You can think of boundedness like a rubber band that can stretch within limits, ensuring that changes are manageable and controlled across the domain of the function.