Chapter 11: Problem 11
Prove that if \(\mathbf{f}: \mathbb{R}^{n} \rightarrow \mathbb{R}^{m}\) is continuous, then \(\|\mathbf{f}(\mathbf{x})\|\) is continuous on \(\mathbb{R}^{n}\).
Short Answer
Expert verified
Since \(\mathbf{f}(\mathbf{x})\) is continuous, \(\|\mathbf{f}(\mathbf{x})\|\) is also continuous by the triangle inequality.
Step by step solution
01
Understand the Given Problem
We need to prove that if a function \(\mathbf{f}: \mathbb{R}^{n} \rightarrow \mathbb{R}^{m}\) is continuous, then the norm \(\|\mathbf{f}(\mathbf{x})\|\) is also continuous. This involves showing that small changes in \(\mathbf{x}\) result in small changes in \|\mathbf{f}(\mathbf{x})\|, a function from \(\mathbb{R}^n\) to \(\mathbb{R}\).
02
Recall the Definition of Continuity
A function \(\mathbf{f}(\mathbf{x})\) is continuous at a point \(\mathbf{a}\) if for every \(\epsilon > 0\), there exists \(\delta > 0\) such that if \(\|\mathbf{x} - \mathbf{a}\| < \delta\), then \(\|\mathbf{f}(\mathbf{x}) - \mathbf{f}(\mathbf{a})\| < \epsilon\). We want to apply this to the function \(\|\mathbf{f}(\mathbf{x})\|\).
03
Use the Triangle Inequality
Let \(\|\cdot\|\) be the norm in \(\mathbb{R}^m\). For any \(\mathbf{x}, \mathbf{a} \in \mathbb{R}^n\), the triangle inequality gives us \(\|\|\mathbf{f}(\mathbf{x})\| - \|\mathbf{f}(\mathbf{a})\|\| \leq \|\mathbf{f}(\mathbf{x}) - \mathbf{f}(\mathbf{a})\|\).
04
Apply Continuity of \(\mathbf{f}(\mathbf{x})\)
Since \(\mathbf{f}(\mathbf{x})\) is continuous, for every \(\epsilon > 0\), there exists \(\delta > 0\) such that if \(\|\mathbf{x} - \mathbf{a}\| < \delta\), then \(\|\mathbf{f}(\mathbf{x}) - \mathbf{f}(\mathbf{a})\| < \epsilon\). By the triangle inequality, \(\|\|\mathbf{f}(\mathbf{x})\| - \|\mathbf{f}(\mathbf{a})\|\| < \epsilon\).
05
Conclusion
We have shown that for an arbitrary \(\epsilon > 0\), a corresponding \(\delta > 0\) exists in such a way that \(\|\|\mathbf{f}(\mathbf{x})\| - \|\mathbf{f}(\mathbf{a})\|\| < \epsilon\) whenever \(\|\mathbf{x} - \mathbf{a}\| < \delta\). This implies that \(\|\mathbf{f}(\mathbf{x})\|\) is continuous at \(\mathbf{a}\).
06
Generality
Since \(\mathbf{a}\) is arbitrary, this proof holds for any point in \(\mathbb{R}^{n}\). Therefore, \(\|\mathbf{f}(\mathbf{x})\|\) is continuous on \(\mathbb{R}^{n}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Norm of a function
In real analysis, the norm of a function is a way to measure the size or length of vectors. When we talk about a function \(\mathbf{f}: \mathbb{R}^n \rightarrow \mathbb{R}^m\), its norm, noted as \(\|\mathbf{f}(\mathbf{x})\|\), tells us how large the output vector is in \(\mathbb{R}^m\). To be more specific, the norm \(\|\cdot\|\) in this context could often be the Euclidean norm.
- The Euclidean norm \(\|\mathbf{v}\|\) is calculated as \(\sqrt{v_1^2 + v_2^2 + \ldots + v_m^2}\), where \(v_i\) are the components of the vector \(\mathbf{v}\).
- It provides a non-negative value that indicates the "distance" from the origin to the point \(\mathbf{v}\) in \(\mathbb{R}^m\).
- This property is crucial in defining breadth and understanding vector spaces.
Triangle inequality
The triangle inequality is a fundamental concept in mathematics that ties closely with norms. It provides a bound on the length of one side of a triangle depending on the other two sides. The triangle inequality states: \[\|\mathbf{a} + \mathbf{b}\| \leq \|\mathbf{a}\| + \|\mathbf{b}\|\] This works like this:
- Consider \(\mathbf{a}\) and \(\mathbf{b}\) as vectors in \(\mathbb{R}^n\). The norm of their sum is not "larger" than the sum of their norms.
- This concept assures that small changes in vector \(\mathbf{x}\) result only in small deviations in the norm \(\|\mathbf{f}(\mathbf{x})\|\).
- In context, this inequality helps ensure the continuity of norms by showing there is a bound on how much the output can change.
Continuity definition
Continuity is a core concept in calculus and analysis, providing a formal way of capturing the idea of unbroken or un-interrupted behavior of functions. A function \(\mathbf{f}: \mathbb{R}^n \rightarrow \mathbb{R}^m\) is said to be continuous at a particular point \(\mathbf{a}\) if:
- For every \(\epsilon > 0\), there exists a \(\delta > 0\) such that whenever \(\|\mathbf{x} - \mathbf{a}\| < \delta\), it follows that \(\|\mathbf{f}(\mathbf{x}) - \mathbf{f}(\mathbf{a})\| < \epsilon\).
- This essentially means that small tweaks in input \(\mathbf{x}\) around \(\mathbf{a}\) produce only tiny shifts in output of \(\mathbf{f}(\mathbf{x})\).