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\( \quad\) Let \(X\) have finite variance, and set \(v(x)=\mathbf{E}(X-x)^{2}\). Show that \(\mathbf{E} v(X)=2 \operatorname{var} X\).

Short Answer

Expert verified
The result holds: \( \mathbf{E}[v(X)] = 2\operatorname{var}(X) \).

Step by step solution

01

Expand the Expression

The function given is \( v(x) = \mathbf{E}(X-x)^2 \), which represents the expected value of the squared difference between \(X\) and \(x\). We can expand \((X-x)^2\) using the binomial expansion: \((X-x)^2 = (X^2 - 2Xx + x^2)\).
02

Compute the Expected Value of the Expression

Substitute the expanded form into the expectation: \[ \mathbf{E}[v(X)] = \mathbf{E}[\mathbf{E}(X^2 - 2Xx + x^2)] = \mathbf{E}[\mathbf{E}(X^2) - 2\mathbf{E}(X)x + \mathbf{E}(x^2)] \] Using the linearity of expectation, this simplifies to: \[ \mathbf{E}(X^2) - 2x\mathbf{E}(X) + x^2 \].
03

Simplify with Properties of Variance

Recognize that \( \mathbf{E}(X^2) = \operatorname{var}(X) + \mathbf{E}(X)^2 \). Thus, substituting in our equation we have: \[ \mathbf{E}[v(X)] = \operatorname{var}(X) + \mathbf{E}(X)^2 - 2x\mathbf{E}(X) + x^2 \] Further, variance is defined as \( \operatorname{var}(X) = \mathbf{E}(X^2) - (\mathbf{E}(X))^2 \).
04

Use Definition of Variance

Substitute back \( \operatorname{var}(X) = \mathbf{E}(X^2) - (\mathbf{E}(X))^2 \) and rewrite: \[ \mathbf{E}[v(X)] = \operatorname{var}(X) + \mathbf{E}(X)^2 - (\mathbf{E}(X))^2 \] This simplifies to: \[ 2\operatorname{var}(X) \].
05

Conclude the Verification

We have shown that \( \mathbf{E}[v(X)] = 2\operatorname{var}(X) \) through correct expansion, usage of variance properties, and expectation properties. Therefore, affirmative: the problem statement is valid and proven.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
The expected value is a fundamental concept in probability and statistics. It represents the average or mean value that you would expect from a random variable if the experiment were repeated many times. For a random variable \(X\), the expected value is denoted by \(\mathbf{E}(X)\). It is calculated by summing the products of all possible outcomes and their respective probabilities:
  • \[ \mathbf{E}(X) = \sum_{i} x_i \, P(x_i) \]
This concept helps in quantifying the center of the distribution of the random variable \(X\). In the exercise, the expected value appears in the function \(v(x) = \mathbf{E}(X-x)^2\), guiding the analysis of variance by calculating the squared deviation of \(X\) from a point \(x\), averaged over many trials. Recognizing how expected value integrates into broader calculations provides tools for handling a wide array of statistical tasks.
Binomial Expansion
The binomial expansion is a powerful algebraic method for expanding expressions that are squared or raised to a power. In the context of the exercise, it applies when you need to expand \((X-x)^2\). The binomial theorem outlines the expansion of expressions like this:
  • \[ (X-x)^2 = X^2 - 2Xx + x^2 \]
This expansion is essential because it simplifies the process of finding the expected value of a squared deviation. You break down the expression into a sum of simpler elements, whose expected values can be more easily calculated or interpreted. The understanding of binomial expansion is crucial when manipulating terms to reveal underlying properties, as seen in this problem where it's used to express \(v(x)\) in a more tractable form.
Linearity of Expectation
Linearity of expectation is a property that greatly simplifies the calculation of expected values, particularly in expressions with sums. This property states that the expected value of a sum of random variables equals the sum of their expected values, regardless of whether these variables are dependent or independent:
  • \[ \mathbf{E}(aX + bY) = a\mathbf{E}(X) + b\mathbf{E}(Y) \]
In the exercise, this principle was applied to break down the expression \((X^2 - 2Xx + x^2)\) into its individual components to separately evaluate their expected values. Linearity of expectation is particularly useful for simplifying complex expressions, allowing each component to be dealt with separately, thereby making the evaluation process more straightforward.
Properties of Variance
Variance is a measure of the spread or dispersion of a random variable's possible values. It tells us how much the values deviate from the mean. The variance of a random variable \(X\) with expected value \(\mathbf{E}(X)\) is given by:
  • \[ \operatorname{var}(X) = \mathbf{E}(X^2) - (\mathbf{E}(X))^2 \]
The properties of variance help us manipulate and understand these deviations more clearly. For example, variance remains unchanged by subtracting a constant, but it is affected by multiplying by a constant:
  • \(\operatorname{var}(aX) = a^2 \operatorname{var}(X)\)
In the exercise, variance properties were leveraged to reach the final conclusion that \(\mathbf{E}[v(X)] = 2\operatorname{var}(X)\). This establishes a relationship between the squared deviations averaging around a point \(x\) and the inherent variability of \(X\). These properties ensure that one can understand the extent of variation in data and apply it effectively in more complex statistical analyses.

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