Chapter 5: Problem 2
(a) If \(\operatorname{gcd}(a, 35)=1\), show that \(a^{12} \equiv 1(\bmod 35)\). [Hint: From Fermat's theorem \(a^{6} \equiv 1(\bmod 7)\) and \(\left.a^{4} \equiv 1(\bmod 5) .\right]\) (b) If \(\operatorname{gcd}(a, 42)=1\), show that \(168=3 \cdot 7 \cdot 8\) divides \(a^{6}-1\). (c) If \(\operatorname{gcd}(a, 133)=\operatorname{gcd}(b, 133)=1\), show that \(133 \mid a^{18}-b^{18}\).
Short Answer
Step by step solution
Given Conditions for (a)
Apply Fermat's Little Theorem mod 7
Apply Fermat's Little Theorem mod 5
Combine Results for mod 35
Given Conditions for (b)
Use Fermat's Theorem mod 3, 7 and 8
Conclude divisibility by 168
Given Conditions for (c)
Demonstrate divisibility by 7 and 19
Final Conclusion Using CRT
Short Answer:
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chinese Remainder Theorem
- \( x \equiv a \, (\text{mod} \, n_1) \)
- \( x \equiv b \, (\text{mod} \, n_2) \)