Chapter 8: Problem 17
For which values of \(b\) is the exponential congruence \(9^{x} \equiv b(\bmod 13)\) solvable?
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Chapter 8: Problem 17
For which values of \(b\) is the exponential congruence \(9^{x} \equiv b(\bmod 13)\) solvable?
These are the key concepts you need to understand to accurately answer the question.
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Let \(r\) be a primitive root of the odd prime \(p\), and let \(d=\operatorname{gcd}(k, p-1)\). Prove that the values of \(a\) for which the congruence \(x^{k} \equiv a(\bmod p)\) is solvable are \(r^{d}, r^{2 d}, \ldots, r^{[(p-1) / d] d}\).
Find the order of the integers 2,3 , and 5 : (a) modulo 17. (b) modulo 19 . (c) modulo 23 .
Given that \(a\) has order 3 modulo \(p\), where \(p\) is an odd prime, show that \(a+1\) must have order 6 modulo \(p\). [Hint: From \(a^{2}+a+1 \equiv 0(\bmod p)\), it follows that \((a+1)^{2} \equiv a(\bmod p)\) and \(\left.(a+1)^{3} \equiv-1(\bmod p) .\right]\)
If \(r\) is a primitive root of the odd prime \(p\), verify that $$ \text { ind }_{r}(-1)=\text { ind }_{r}(p-1)=\frac{1}{2}(p-1) $$
Assuming that \(r\) is a primitive root of the odd prime \(p\), establish the following facts: (a) The congruence \(r^{(p-1) / 2} \equiv-1(\bmod p)\) holds. (b) If \(r^{\prime}\) is any other primitive root of \(p\), then \(r r^{\prime}\) is not a primitive root of \(p .\) [Hint: By part (a), \(\left.\left(r r^{\prime}\right)^{(p-1) / 2} \equiv 1(\bmod p) .\right]\) (c) If the integer \(r^{\prime}\) is such that \(r r^{\prime} \equiv 1(\bmod p)\), then \(r^{\prime}\) is a primitive root of \(p\).
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