/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 For any integer \(a\), show that... [FREE SOLUTION] | 91Ó°ÊÓ

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For any integer \(a\), show that \(a\) and \(a^{4 n+1}\) have the same last digit.

Short Answer

Expert verified
Integers \(a\) and \(a^{4n+1}\) always have the same last digit when both are considered modulo 10.

Step by step solution

01

Understand the Problem

We need to show that the last digit of an integer \( a \) is the same as the last digit of \( a^{4n+1} \), for any integer \( n \). The last digit of a number is determined by its remainder when divided by 10.
02

Simplify the Expression modulo 10

Since we are interested in the last digit, we consider the expression modulo 10: \( a^k \equiv a^{4n+1} \pmod{10} \). It suffices to show that \( a \equiv a^{4n+1} \pmod{10} \).
03

Analyze Powers Within the Modulus

Note that raising any integer \( a \) to a power results in cycling through certain residues when considered modulo 10. Specifically, for any positive integer \( n \), \( (a^{4}) \equiv 1 \pmod{10} \) due to Euler's theorem or relate it to patterns observed in the cycle of powers.
04

Conclude Using Power Cycles

Given \( a^4 \equiv 1 \pmod{10} \), we write \( a^{4n} \equiv 1^n \equiv 1 \pmod{10} \). Thus, \( a^{4n+1} \equiv a^1 \equiv a \pmod{10} \). This implies \( a \equiv a^{4n+1} \pmod{10} \).
05

Verify with Example

For example, let \( a = 3 \) and \( n = 1 \). Then \( a^{4n+1} = 3^5 = 243 \). The last digit of 3 and 243 are both 3. Therefore, \( 3 \equiv 3^5 \pmod{10} \), as expected.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Euler's Theorem
Euler's Theorem is a fundamental theorem in number theory that helps us solve problems related to powers of integers under modulo operations. It states that for any two numbers that are coprime (i.e., their greatest common divisor is 1), like \( a \) and \( n \), the following holds: \[ a^{\phi(n)} \equiv 1 \pmod{n},\]where \( \phi(n) \) is Euler's totient function, representing the count of numbers less than \( n \) that are coprime to \( n \). Understanding this theorem is key in modular arithmetic applications, allowing us to simplify computations of large powers under a modulus. In our exercise, even though Euler’s Theorem isn't directly required, it helps explain why there are consistent patterns (or cycles) observed in powers, like seeing \( a^4 \equiv 1 \pmod{10} \) often. This pattern is pivotal in comprehension and comes in handy when determining repetitiveness in modular operations.
Last Digit
Finding the last digit of a number is a common task which is simplified using modular arithmetic. The last digit of any given number is equivalent to finding the number modulo 10. For example, with a number like 27, calculating \( 27 \mod 10 \) gives 7, which is the last digit. This technique is important in problems where the values can become large, and we need simpler expressions to manage. In our exercise, figuring out \( a^{4n+1} \) and ensuring it shares the same last digit as \( a \), involves utilizing the modulo 10 operation. Observing the effect of raising numbers to a power and considering modulo 10 allows us to generalize the rule for finding last digits and show their persistence even for results of intricate powers.
Power Cycles
Power cycles refer to the repeating patterns observed when exponentiating a number under a specific modulus. Essentially, as you raise a base to higher powers, you'll notice that the results (under a modulo operation) eventually start repeating. This cycle happens because there are only a finite number of residues possible when working with modular values. In our exercise, we find that when numbers are powered up, ultimately, their residues modulo 10 start to loop back. This is described by seeing for any integer \( a \), \( a^4 \equiv 1 \pmod{10} \). Because of this cycle, when \( a \) is raised to \( 4n+1 \), the last digit resets to that of \( a \). Hence, understanding and identifying these cycles help simplify calculations and predict outcomes efficiently for large power values.

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Most popular questions from this chapter

(a) A linear cipher is defined by the congruence \(C=a P+b\) (mod 26), where \(a\) and \(b\) are integers with ged \((a, 26)=1\). Show that the corresponding decrypting congruence is \(P=a^{\prime}(C-b)(\bmod 26)\), where the integer \(a^{\prime}\) satisfies \(a a^{\prime}=1(\bmod 26)\). (b) Using the linear cipher \(C=5 P+11\) (mod 26), encrypt the message NUMBER THEORY IS EASY. (c) Decrypt the message RZQTGU HOZTKGH DJ KTKMMTG, which was produced using the linear cipher \(C \equiv 3 P+7\) (mod 26).

For a positive integer \(n\), prove that \(\sum_{d \mid n} \mu^{2}(d) / \phi(d)=n / \phi(n) .\) |Hint: Both sides of the equation are multiplicative functions.]

(a) Prove that the equation \(\phi(n)=2 p\), where \(p\) is a prime number and \(2 p+1\) is composite, is not solvable. (b) Prove that there is no solution to the equation \(\phi(n)=14\), and that 14 is the smallest (positive) even integer with this property.

In a lengthy ciphertext message, sent using a linear cipher \(C=a P+b(\bmod 26)\), the most frequently occurring letter is \(\mathrm{Q}\) and the second most frequent is \(\mathrm{J} .\) (a) Break the cipher by determining the values of \(a\) and \(b\). [Hint: The most often used letter in English text is \(\mathrm{E}\), followed by \(\mathrm{T}\).] (b) Write out the plaintext for the intercepted message WCPQ JZQO MX.

Given \(n \geq 1\), a set of \(\phi(n)\) integers that are relatively prime to \(n\) and that are incongruent modulo \(n\) is called a reduced set of residues modulo \(n\) (that is, a reduced set of residues are those members of a complete set of residues modulo \(n\) that are relatively prime to \(n\) ). Verify the following: (a) The integers \(-31,-16,-8,13,25,80\) form a reduced set of residues modulo \(9 .\) (b) The integers 3, \(3^{2}, 3^{3}, 3^{4}, 3^{5}, 3^{6}\) form a reduced set of residues modulo 14 . (c) The integers \(2,2^{2}, 2^{3}, \ldots, 2^{18}\) form a reduced set of residues modulo 27 .

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