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Prove that, for a positive integer \(n\) and any integer \(a, \operatorname{gcd}(a, a+n)\) divides \(n ;\) hence, \(\operatorname{gcd}(a, a+1)=1\)

Short Answer

Expert verified
\( \operatorname{gcd}(a, a+n) \) divides \( n \); therefore, \( \operatorname{gcd}(a, a+1) = 1 \).

Step by step solution

01

Define the GCD

To prove that \( \operatorname{gcd}(a, a+n) \) divides \( n \), we start by defining \( g = \operatorname{gcd}(a, a+n) \). This means \( g \) is the greatest positive integer that divides both \( a \) and \( a + n \).
02

Use the Properties of GCD

Since \( g \) divides both \( a \) and \( a + n \), it follows that \( g \) also divides the difference of these two expressions: \((a+n) - a = n\). Thus, if \( g \) divides \( a \) and \( a+n \), \( g \) must divide \( n \) as well.
03

Prove the Special Case

Now consider the special case where \( n = 1 \). We need to prove that \( \operatorname{gcd}(a, a+1) = 1 \). Since 1 is the difference between \( a+1 \) and \( a \), by Step 2, the greatest common divisor of any number and one greater than it is 1. Therefore, \( \operatorname{gcd}(a, a+1) = 1 \) for any integer \( a \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Positive Integers
Positive integers are numbers greater than zero, and they do not include any fractions, decimals, or negative numbers. These are the numbers we often start counting from, like 1, 2, 3, and so on. Positive integers are vital in many branches of mathematics, including number theory, where they form the basis of more complex problems.

Understanding the concept of positive integers is essential for problems like finding the greatest common divisor (GCD). The GCD deals with positive integers because it is a measure of the largest number that can exactly divide two given numbers without leaving a remainder. When working with problems that involve the GCD, you are usually given positive integers to work with, ensuring your solutions remain within a set of values that are easy to manage and understand.

For example, in proving that \( \operatorname{gcd}(a, a+n) \) divides \( n \), \( n \) is a positive integer, ensuring that the proof can be done within a range of suitable numbers. Using positive integers helps maintain the clarity and simplicity of mathematical expressions.
Integer Properties
Integers are whole numbers that can be positive, negative, or zero. Their properties are important when dealing with mathematical operations such as addition, subtraction, and finding the GCD. Here are some key integer properties:

  • Divisibility: An integer \( a \) is divisible by another integer \( b \) if there exists an integer \( k \) such that \( a = b \times k \).
  • Greatest Common Divisor (GCD): The GCD of two integers is the largest positive integer that divides both numbers without leaving a remainder.
  • Arithmetic Operations: Integers abide by standard arithmetic rules which are associative, commutative, and distributive in nature.

In the problem from the exercise, these properties help us conclude that \( g \), the GCD of \( a \) and \( a+n \), can also divide \( n \), due to the properties of divisibility and the commutative nature of addition and subtraction within integers. By understanding these integer properties, we can manipulate and transform expressions while remaining assured that the operations we perform are valid.
Difference Property of GCD
The difference property of the GCD is a fascinating aspect that underpins many proofs and problems. It states that for any integers \( a \) and \( b \), the GCD of \( a \) and \( b \) (\( \operatorname{gcd}(a,b) \)) will also divide any linear combination of \( a \) and \( b \), specifically the difference \( b-a \).

This property shows that if a number divides both \( a \) and \( a+n \), it must necessarily divide their difference, \( n \). This logical step is fundamental in the exercise because it helps generalize the idea that if \( g = \operatorname{gcd}(a, a+n) \), then \( g \) must also divide \( n \).

In applying this to \( n = 1 \), the difference \( (a+1) - a \) is 1, which means \( \operatorname{gcd}(a, a+1) \) is 1, reflecting the fact that consecutive integers have no common divisors apart from 1. This property simplifies many complex GCD problems into straightforward, logical steps, making them easier to understand and prove.

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Most popular questions from this chapter

Given integers \(a\) and \(b\), prove the following: (a) There exist integers \(x\) and \(y\) for which \(c=a x+b y\) if and only if \(\operatorname{gcd}(a, b) \mid c\). (b) If there exist integers \(x\) and \(y\) for which \(a x+b y=\operatorname{gcd}(a, b)\), then \(\operatorname{gcd}(x, y)=1\).

A farmer purchased 100 head of livestock for a total cost of \(\$ 4000\). Prices were as follow: calves, \(\$ 120\) each; lambs, \(\$ 50\) each; piglets, \(\$ 25\) each. If the farmer obtained at least one animal of each type, how many of each did he buy?

Verify that if an integer is simultaneously a square and a cube (as is the case with 64 \(=8^{2}=4^{3}\) ), then it must be either of the form \(7 k\) or \(7 k+1\).

Confirm the following properties of the greatest common divisor: (a) If \(\operatorname{gcd}(a, b)=1\), and \(\operatorname{gcd}(a, c)=1\), then \(\operatorname{gcd}(a, b c)=1\). [Hint: Because \(1=a x+b y=a u+c v\) for some \(x, y, u, v, 1=(a x+b y)(a u+c v)=\) \(a(a u x+c v x+b y u)+b c(y v) .]\) (b) If \(\operatorname{gcd}(a, b)=1\), and \(c \mid a\), then \(\operatorname{gcd}(b, c)=1\). (c) If \(\operatorname{gcd}(a, b)=1\), then \(\operatorname{gcd}(a c, b)=\operatorname{gcd}(c, b)\). (d) If \(\operatorname{gcd}(a, b)=1\), and \(c \mid a+b\), then \(\operatorname{gcd}(a, c)=\operatorname{gcd}(b, c)=1\). [Hint: Let \(d=\operatorname{gcd}(a, c)\). Then \(d|a, d| c\) implies that \(d \mid(a+b)-a\), or \(d \mid b .\) ] (e) If \(\operatorname{gcd}(a, b)=1, d \mid a c\), and \(d \mid b c\), then \(d \mid c\). (f) If \(\operatorname{gcd}(a, b)=1\), then \(\operatorname{gcd}\left(a^{2}, b^{2}\right)=1\).

(a) A man has \(\$ 4.55\) in change composed entirely of dimes and quarters. What are the maximum and minimum number of coins that he can have? Is it possible for the number of dimes to equal the number of quarters? (b) The neighborhood theater charges \(\$ 1.80\) for adult admissions and \(\$ .75\) for children. On a particular evening the total receipts were \(\$ 90\). Assuming that more adults than children were present, how many people attended? (c) A certain number of sixes and nines is added to give a sum of 126 ; if the number of sixes and nines is interchanged, the new sum is 114 . How many of each were there originally?

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