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Show that the number of subgroups of finite index \(n\) in the group \(Z^{2}\) is equal to \(\sigma(n)\). (Hint: you may assume that these subgroups correspond to integer matrices \(A=\left(\begin{array}{l}a b \\ 0 & d\end{array}\right)\) where \(a, d>0, a d=n\) and \(0 \leq b

Short Answer

Expert verified
The number of subgroups of index \( n \) in \( \mathbb{Z}^2 \) is \( \sigma(n) \). For \( \mathbb{Z}^k \), it's \( \sigma(n)^k \).

Step by step solution

01

Understanding the Problem

We need to determine the number of subgroups of finite index \( n \) in the group \( \mathbb{Z}^2 \). The hint suggests that these subgroups correspond to integer matrices \( A = \begin{pmatrix} a & b \ 0 & d \end{pmatrix} \), where \( a, d > 0 \), \( ad = n \), and \( 0 \leq b < d \).
02

Identifying the Diagonal Form

The matrix \( A \) represents a subgroup of \( \mathbb{Z}^2 \). Since \( a, d > 0 \) and \( ad = n \), we are looking to express \( n \) as the product of two positive integers \( a \) and \( d \).
03

Counting Choices for \(a\) and \(d\)

For each positive divisor \( a \) of \( n \), there is a corresponding \( d = \frac{n}{a} \). Thus, the choices for \( (a, d) \) correspond to the set of divisor pairs of \( n \).
04

Determining \(b",

Given \( a \) and \( d \), the possible values of \( b \) range from 0 to \( d-1 \), inclusive. This provides \( d \) choices for \( b \) for each pair \( (a, d) \).
05

Counting Total Subgroups

For each divisor \( a \) of \( n \), there are \( \frac{n}{a} \) choices for \( b \). The total number of subgroups is therefore the sum over all divisors \( a \, | \, n \) of \( \frac{n}{a} \).
06

Relating to the Divisor Sum Function

The expression \( \sum_{a \, | \, n} \frac{n}{a} \) is equivalent to \( \sigma(n) \), the sum of the divisors of \( n \). Thus, the number of subgroups in \( \mathbb{Z}^2 \) of index \( n \) is \( \sigma(n) \).
07

Generalizing to \(\mathbb{Z}^k\)

For the group \( \mathbb{Z}^k \), the number of subgroups of index \( n \) is analogously given by the product \( \sigma(n)^k \) based on similar combinatorial arguments across \( k \) dimensions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

integer matrix
An integer matrix is a matrix where all the elements are integers. In this problem, we consider a specific kind of integer matrix which represents a subgroup of the group \( \mathbb{Z}^2 \).

The matrix given is \( A = \begin{pmatrix} a & b \ 0 & d \end{pmatrix} \), where \( a \) and \( d \) are positive integers. These integers satisfy the condition \( ad = n \), meaning the product of \( a \) and \( d \) equals \( n \), the index of the subgroup.
  • The integer \( a \) corresponds to one dimension of the subgroup structure.
  • The integer \( d \) corresponds to the second dimension.
  • \( b \) can take any integer value such that \( 0 \leq b < d \).
This specific form helps in counting the number of distinct finite index subgroups in \( \mathbb{Z}^2 \). Understanding how integer matrices represent these subgroups is crucial for solving the given problem.
divisor pairs
Divisor pairs are a key element to solving the subgroup problem in \( \mathbb{Z}^2 \). Given an integer \( n \), its divisors are integers that divide \( n \) without leaving a remainder.

For any divisor \( a \) of \( n \), you can find a corresponding divisor \( d \) such that \( ad = n \). This pairing, \( (a, d) \), provides the foundational structure for the matrix \( A \) in the problem.
  • Each divisor \( a \) implies the existence of \( d = \frac{n}{a} \).
  • The divisor pairs \( (a, d) \) are used to build the integer matrices that represent subgroups of \( \mathbb{Z}^2 \).
By calculating all such pairs, we know how \( n \) can decompose into two numbers, guiding us to the number of possible subgroups of the finite index \( n \).
divisor sum function
The divisor sum function, denoted as \( \sigma(n) \), is a function that returns the sum of all positive divisors of \( n \).

In the context of the problem, \( \sigma(n) \) is directly related to the number of subgroups of a given index in \( \mathbb{Z}^2 \). This relationship arises because:
  • For each divisor \( a \) of \( n \), there are \( \frac{n}{a} \) valid choices for \( b \) in the matrix \( A \).
  • The total number of subgroups is thus the sum over all divisors \( a \), of the expression \( \frac{n}{a} \).
The mathematical expression \( \sum_{a \mid n} \frac{n}{a} \) matches exactly with \( \sigma(n) \), thereby proving that there are \( \sigma(n) \) such subgroups.
The divisor sum function is a powerful tool used in number theory, often simplifying complex counting into more manageable forms.
combinatorial arguments
Combinatorial arguments provide a method of counting discrete structures, which in this case, are the subgroups of a given index in \( \mathbb{Z}^2 \).

The process involves a few key steps:
  • Identify divisor pairs \( (a, d) \), ensuring \( ad = n \).
  • For each pair, determine potential values for \( b \), constrained by the range \( 0 \leq b < d \).
These steps ensure you account for all possible matrices \( A \) that form subgroups of \( \mathbb{Z}^2 \) with index \( n \). The product of choices for \( a, d, \) and \( b \) leads to the realization that the count is \( \sigma(n) \).
In more general terms, similar arguments can extend to higher dimensions, such as \( \mathbb{Z}^k \), resulting in \( \sigma(n)^k \), where each additional dimension complicates the counting procedure. Combinatorial reasoning simplifies these calculations into understandable and logical steps.

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