Chapter 4: Problem 28
Prove: An \(n \times n\) matrix \(A\) is invertible if and only if the linear system \(A \mathbf{x}=\mathbf{w}\) has exactly one solution for every vector \(\mathbf{w}\) in \(R^{n}\) for which the system is consistent.
Short Answer
Expert verified
An \( n \times n \) matrix \( A \) is invertible if it has a unique solution for every consistent \( A \mathbf{x} = \mathbf{w} \).
Step by step solution
01
Understanding the Problem
We need to prove the equivalence of two statements about an \( n \times n \) matrix \( A \):1. \( A \) is invertible.2. For every vector \( \mathbf{w} \) in \( \mathbb{R}^n \), the system \( A \mathbf{x} = \mathbf{w} \) has exactly one solution whenever it is consistent.
02
Definition of an Invertible Matrix
Recall that an \( n \times n \) matrix \( A \) is invertible if there exists a matrix \( B \) such that \( AB = BA = I_n \), where \( I_n \) is the identity matrix of size \( n \). This means \( A \) has full rank \( n \).
03
The Forward Direction: Invertible Implies Unique Solution
If \( A \) is invertible, for any vector \( \mathbf{w} \), the matrix equation \( A \mathbf{x} = \mathbf{w} \) can be solved uniquely by multiplying both sides by \( A^{-1} \). Thus, \( \mathbf{x} = A^{-1} \mathbf{w} \) is the unique solution because \( A^{-1} \) exists and the entire space \( \mathbb{R}^n \) can be mapped bijectively.
04
The Reverse Direction: Unique Solution Implies Invertibility
Assume that the system \( A \mathbf{x} = \mathbf{w} \) has exactly one solution for every vector \( \mathbf{w} \). This implies that for \( \mathbf{w} = \mathbf{0} \), the only solution is \( \mathbf{x} = \mathbf{0} \). Therefore, the null space of \( A \) contains only the zero vector, indicating \( A \) has full rank and is invertible.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Linear Systems
A linear system is a collection of linear equations that need to be solved simultaneously. Consider a scenario where you have multiple equations, each representing a straight line in space. The solution to this system is the point or set of points where these lines intersect. In mathematical terms, a linear system expressed in matrix form looks like this:
- Suppose you have equations in the form: \[ a_{1,1}x_1 + a_{1,2}x_2 + \ ... + a_{1,n}x_n = b_1 \]i.e., the coefficients of the variables in a structured format.
- Your goal is to find the values of \( x_1, x_2, \ ... , x_n \) that satisfy all these equations.
- If all lines intersect at a single point, there is exactly one solution.
- If they are parallel and never meet, there is no solution.
- If they overlap entirely, there are infinitely many solutions.
Matrix Equation
Matrix equations involve operations on matrices, similar to regular algebraic equations. Here’s how a matrix equation is set up:
- Consider the matrix equation \( A \mathbf{x} = \mathbf{w} \).
- Here, \( A \) is a matrix of coefficients with dimensions \( n \times n \), \( \mathbf{x} \) is a column matrix of variables, and \( \mathbf{w} \) is the resultant vector.
- Simplifying expressions and solving for components of \( \mathbf{x} \) to satisfy \( \mathbf{x} = A^{-1} \mathbf{w} \), whenever \( A^{-1} \) exists.
Rank of a Matrix
The rank of a matrix is a crucial concept in linear algebra that helps determine solutions to matrix equations. The rank tells us the maximum number of linearly independent row vectors or column vectors in a matrix. Here's what you need to know:
- A matrix is full rank if its rank equals the smallest dimension of the matrix, often seen in square matrices \( n \times n \) where rank \( n \) implies full rank.
- Full rank indicates that the matrix does not have any linear dependence among its rows or columns.
- If a matrix \( A \) is full rank, it means that every variable in the linear system can be determined uniquely, which also implies the matrix is invertible.
- If the rank of \( A \) is not full, there is a linear dependence that prevents finding a unique solution for the matrix equation \( A \mathbf{x} = \mathbf{w} \).