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(a) Prove: If \(T: R^{n} \rightarrow R^{m}\) is a matrix transformation, then \(T(0)=0 ;\) that is, \(T\) maps the zero vector in \(R^{n}\) into the zero vector in \(R^{m}\). (b) The converse of this is not true. Find an example of a function that satisfies \(T(0)=0\) but is not a matrix transformation.

Short Answer

Expert verified
(a) Matrix transformations map the zero vector in \(\mathbb{R}^{n}\) to the zero vector in \(\mathbb{R}^{m}\). (b) \(T(x) = x^2\) is a counterexample.

Step by step solution

01

Understanding the Matrix Transformation

A matrix transformation \(T: \mathbb{R}^{n} \rightarrow \mathbb{R}^{m}\) is a function that can be expressed in the form \(T(\mathbf{x}) = A\mathbf{x}\), where \(A\) is an \(m \times n\) matrix and \(\mathbf{x}\) is a vector in \(\mathbb{R}^{n}\). This type of transformation always has a linear structure.
02

Statement to Prove

We need to prove that if \(T\) is a matrix transformation, then it maps the zero vector in \(\mathbb{R}^{n}\) (denoted as \(\mathbf{0}_{n}\)) to the zero vector in \(\mathbb{R}^{m}\) (denoted as \(\mathbf{0}_{m}\)). In symbols, \(T(\mathbf{0}_{n}) = \mathbf{0}_{m}\).
03

Applying Matrix Transformation to Zero Vector

Consider the zero vector \(\mathbf{0}_{n}\) in \(\mathbb{R}^{n}\). The matrix transformation is given by \(T(\mathbf{x}) = A\mathbf{x}\). Thus, \(T(\mathbf{0}_{n}) = A\mathbf{0}_{n}\).
04

Result of Matrix Multiplication

Since \(\mathbf{0}_{n}\) is a zero vector, multiplying any matrix \(A\) by \(\mathbf{0}_{n}\) results in another zero vector of appropriate dimension. Mathematically, \(A\mathbf{0}_{n} = \mathbf{0}_{m}\). Therefore, we have \(T(\mathbf{0}_{n}) = \mathbf{0}_{m}\), proving the statement.
05

Analyzing the Converse

The converse would state that if a transformation maps the zero vector in \(\mathbb{R}^{n}\) to the zero vector in \(\mathbb{R}^{m}\), it must be a matrix transformation. However, this is not necessarily true.
06

Finding a Counterexample

Consider a piecewise function \(T: \mathbb{R} \to \mathbb{R}\) defined as \( T(x) = x^2 \). For \(x = 0\), \(T(0) = 0^2 = 0 \). However, \(T(x) = x^2 \) is not a linear transformation because it does not satisfy the properties of linearity (i.e., it does not satisfy \(T(x+y) = T(x) + T(y)\) for all \(x, y\)). Hence, \(T\) is not a matrix transformation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

linear transformation
Linear transformations are special kinds of functions between vector spaces. They preserve the operations of addition and scalar multiplication. In simpler terms, if you have a linear transformation, applying it to two vectors added together or multiplying a vector by a number (scalar) and then applying the transformation, gives you the same result as first transforming the vectors individually and then adding or scaling them. Formally, a function \( T: \mathbb{R}^n \rightarrow \mathbb{R}^m \) is linear if it satisfies two conditions: - **Additivity**: \( T(\mathbf{x} + \mathbf{y}) = T(\mathbf{x}) + T(\mathbf{y}) \) for any vectors \( \mathbf{x} \) and \( \mathbf{y} \).- **Homogeneity**: \( T(c \mathbf{x}) = c T(\mathbf{x}) \) for any vector \( \mathbf{x} \) and scalar \( c \). This means that a linear transformation can be represented by a matrix that operates on vectors, enabling us to simplify calculations using matrix multiplication.
zero vector
The zero vector is a special vector in any vector space that when added to any other vector, does not change that vector. For instance, the zero vector in \( \mathbb{R}^n \) can be represented as \([0, 0, ..., 0]\). It plays a crucial role in understanding transformations because of its unique properties: - It remains unchanged after any addition: \( \mathbf{v} + \mathbf{0} = \mathbf{v} \).- It is mapped to another zero vector by any linear or matrix transformation: \( T(\mathbf{0}) = \mathbf{0} \). When dealing with matrix transformations, this means that applying the matrix to a zero vector of appropriate dimension, the result is still a zero vector in the output space dimension. This property confirms the transformation's linearity.
non-linear function
Non-linear functions differ from linear transformations as they do not satisfy the rules of additivity and homogeneity. These functions produce outputs that cannot be predicted simply by examining only pairs of inputs. A common example of a non-linear function is the square function \( T(x) = x^2 \). Here’s why it’s non-linear: - It doesn’t satisfy additivity: \( T(x + y) = (x + y)^2 eq x^2 + y^2 = T(x) + T(y) \).- It also breaks homogeneity: \( T(c x) = (c x)^2 = c^2 x^2 eq c x^2 = c T(x) \). These kinds of functions can map a zero vector to zero, like \( x^2 \) does, but they repay attention as they won't conform to linear operations, resulting in them not being depicted by matrices in the standard way.
matrix multiplication
Matrix multiplication is an operation used extensively in linear algebra, which allows us to perform transformations on vectors through matrices. When we multiply a matrix \( A \) by a vector \( \mathbf{x} \), the result is another vector, often in a different dimension, which represents the transformation of \( \mathbf{x} \) under the matrix \( A \). - The key rule here is that the number of columns in the matrix must match the number of elements in the vector.- Each element of the result vector is calculated as the dot product of the vector and each row of the matrix. This operation follows specific properties, such as distributing over addition and associating with scalar multiplication, making it central to understanding linear transformations. Because multiplying any matrix by a zero vector results in a zero vector, it confirms the transformation's linearity, maintaining the structure of the input space in the transformation output.

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Most popular questions from this chapter

(a) If \(P\) is a regular \(n \times n\) stochastic matrix with steady-state vector \(\mathbf{q},\) and if \(\mathbf{e}_{1}, \mathbf{e}_{2}, \ldots, \mathbf{e}_{n}\) are the standard unit vectors in column form, what can you say about the behavior of the sequence $$P \mathbf{e}_{i}, \quad P^{2} \mathbf{e}_{i}, \quad P^{3} \mathbf{e}_{i}, \ldots, \quad P^{k} \mathbf{e}_{i}, \ldots$$ as \(k \rightarrow \infty\) for each \(i=1,2, \ldots, n ?\) (b) What does this tell you about the behavior of the column vectors of \(P^{k}\) as \(k \rightarrow \infty ?\)

Find the standard matrix for the given matrix operator. (a) \(T: R^{2} \rightarrow R^{2}\) projects a vector orthogonally onto the \(x\) -axis and then reflects that vector about the \(y\) -axis. (b) \(T: R^{2} \rightarrow R^{2}\) reflects a vector about the line \(y=x\) and then reflects that vector about the \(x\) -axis. (c) \(T: R^{2} \rightarrow R^{2}\) dilates a vector by a factor of \(3,\) then reflects that vector about the line \(y=x,\) and then projects that vector orthogonally onto the \(y\) -axis.

Let \(T_{A}: R^{3} \rightarrow R^{3}\) be multiplication by $$A=\left[\begin{array}{rrr} -1 & 3 & 0 \\\2 & 1 & 2 \\\4 & 5 & -3\end{array}\right]$$ and let \(\mathbf{e}_{1}, \mathbf{e}_{2},\) and \(\mathbf{e}_{3}\) be the standard basis vectors for \(R^{3}\). Find the following vectors by inspection. (a) \(T_{A}\left(\mathbf{e}_{1}\right), T_{A}\left(\mathbf{e}_{2}\right),\) and \(T_{A}\left(e_{3}\right)\) (b) \(T_{A}\left(e_{1}+e_{2}+e_{3}\right)\) (c) \(T_{A}\left(7 e_{3}\right)\)

Determine whether \(P\) is a regular stochastic matrix. (a)\(P=\left[\begin{array}{ll}\frac{1}{2} & 1 \\ \frac{1}{2} & 0\end{array}\right]\) (b)\(P=\left[\begin{array}{ll}1 & \frac{2}{3} \\ 0 & \frac{1}{3}\end{array}\right]\) (c)\(P=\left[\begin{array}{ll}\frac{3}{4} & \frac{1}{3} \\ \frac{1}{4} & \frac{2}{3}\end{array}\right]\)

Suppose that two competing television stations, station 1 and station \(2,\) each have \(50 \%\) of the viewer market at some initial point in time. Assume that over each one-year period station 1 captures \(5 \%\) of station 2 's market share and station 2 captures \(10 \%\) of station I's market share. (a) Make a table that shows the market share of each station over a five-year period. (b) Over the long term, how will the market share be distributed between the two stations?

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