Chapter 4: Problem 2
Find the coordinate vector for \(\mathbf{v}\) relative to the basis \(S=\left\\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}\right\\}\) for \(R^{3}\). (a) \(v=(2,-1,3) ; v_{1}=(1,0,0), v_{2}=(2,2,0), v_{3}=(3,3,3)\) (b) \(\mathrm{v}=(5,-12,3) ; \mathrm{v}_{1}=(1,2,3), \mathrm{v}_{2}=(-4,5,6), \mathrm{v}_{3}=(7,-8,9)\)
Short Answer
Step by step solution
Write the vector equation
Express the combination as a system of equations for (a)
Solve the system of equations for (a)
Express the combination as a system of equations for (b)
Solve the system of equations for (b)
Write the coordinate vectors
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Basis in Linear Algebra
For example, in the three-dimensional space \( \mathbb{R}^3 \), a common standard basis consists of the vectors \( \mathbf{i} = (1, 0, 0) \), \( \mathbf{j} = (0, 1, 0) \), and \( \mathbf{k} = (0, 0, 1) \). Any vector in \( \mathbb{R}^3 \) can be formed by combining these vectors with appropriate coefficients.
- Linearly independent: No vector in the basis can be written as a linear combination of the others. This property ensures that the vectors are uniquely defined.
- Spanning set: The set of all possible linear combinations of the basis vectors fills the entire vector space.
Linear Combination
The task is to find scalars \( c_1, c_2, \) and \( c_3 \) such that the vector \( \mathbf{v} \) is represented as \( \mathbf{v} = c_1 \mathbf{v}_1 + c_2 \mathbf{v}_2 + c_3 \mathbf{v}_3 \). This representation is unique if the basis vectors are linearly independent.
- To form a linear combination, each component of the vector \( \mathbf{v} \) is expressed in terms of the components of the basis vectors multiplied by the respective coefficients.
- This leads to a system of linear equations which we can solve to find the scalar coefficients \( c_1, c_2, \) and \( c_3 \).
System of Equations
For instance, if \( \mathbf{v} = (2, -1, 3) \) in terms of basis vectors \( \mathbf{v}_1, \mathbf{v}_2, \mathbf{v}_3 \), the expression becomes a system:
- \( c_1 + 2c_2 + 3c_3 = 2 \)
- \( 2c_2 + 3c_3 = -1 \)
- \( 3c_3 = 3 \)
- For specific values of \( c_3 \), you substitute back to find \( c_2 \), then \( c_1 \).
- A consistent system yields values that will form the coordinate vector of \( \mathbf{v} \), giving its position in the vector space relative to the chosen basis.