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Let \(\mathbf{p}_{0}=\left(x_{0}, y_{0}, z_{0}\right)\) and \(\mathbf{p}=(x, y, z) .\) Describe the set of all points \((x, y, z)\) for which \(\left\|\mathbf{p}-\mathbf{p}_{0}\right\|=1\).

Short Answer

Expert verified
The set of points is a sphere centered at \(\mathbf{p}_{0}\) with radius 1.

Step by step solution

01

Define the distance formula

The distance between two points \(\mathbf{p}_{0}=(x_{0}, y_{0}, z_{0})\) and \(\mathbf{p}=(x, y, z)\) in 3-dimensional space is given by the formula \(\|\mathbf{p}-\mathbf{p}_{0}\| = \sqrt{(x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2}\). We need to set this distance equal to 1.
02

Set the equation equal to 1

Since \(\|\mathbf{p}-\mathbf{p}_{0}\| = 1\), we equate the formula to 1. This gives us the equation: \(\sqrt{(x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2} = 1\).
03

Square both sides

To eliminate the square root, square both sides of the equation: \((x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2 = 1^2\). This simplifies to \((x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2 = 1\).
04

Identify the geometric shape

The resulting equation \((x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2 = 1\) represents the equation of a sphere in 3-dimensional space. The center of this sphere is \(\mathbf{p}_{0}=(x_{0}, y_{0}, z_{0})\) and the radius of the sphere is 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Distance Formula
The distance formula is a crucial tool in geometry, especially when working in 3-dimensional space. It helps us calculate the distance between two points. Imagine you have two points, say \(\mathbf{p}_{0}=(x_{0}, y_{0}, z_{0})\) and \(\mathbf{p}=(x, y, z)\). The distance between these points is given by \[ \|\mathbf{p}-\mathbf{p}_{0}\| = \sqrt{(x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2} \] This formula might look complex, but it's just an extension of the Pythagorean theorem.
Think of it as finding a straight line that connects two points in 3D. You square the difference of each coordinate, add these results together, and then take the square root of the sum.
  • The difference \(x-x_0\) represents the horizontal distance.
  • The difference \(y-y_0\) represents the vertical distance.
  • The difference \(z-z_0\) represents the depth distance.
Exploring 3-Dimensional Space
3-dimensional space, often referred to as 3D space, is the environment around us that we perceive as having length, width, and height. It is a mathematical conception used to define the position of points.
In mathematics and physics, a 3D space is a situation where you describe an object's position using three numbers, typically in the form of coordinates: \(x\), \(y\), and \(z\).
  • \(x\)-axis usually refers to left-right positioning.
  • \(y\)-axis usually refers to up-down positioning.
  • \(z\)-axis usually refers to forward-backward positioning.
Understanding 3D space allows you to visualize and analyze objects in a way similar to how we see and interact with the real world.
When thinking about equations and shapes like spheres, 3D space helps us understand their positions and interactions within a larger context.
Equation of a Sphere
A sphere is a perfectly round three-dimensional shape, and its equation helps to describe its size and position in 3D space.
The exercise we tackled derives an equation for a sphere by using the distance formula. This equation is:\[ (x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2 = r^2 \]where \((x_0, y_0, z_0)\) is the center of the sphere, and \(r\) is its radius.
In our specific case, \(r = 1\), hence the equation becomes:\[ (x-x_{0})^2 + (y-y_{0})^2 + (z-z_{0})^2 = 1 \]This equation tells us that any point \((x, y, z)\) lying on the sphere’s surface is exactly one unit away from the sphere's center \((x_0, y_0, z_0)\).
  • The center of the sphere gives its position in space.
  • The radius tells us the size of the sphere.
This simple yet powerful equation provides a systematic way to describe spherical objects and their properties in mathematical terms.

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