Chapter 3: Problem 24
Compute the scalar triple product \(\mathbf{u} \cdot(\mathbf{v} \times \mathbf{w})\). $$\mathbf{u}=(3,-1,6), \quad \mathbf{v}=(2,4,3), \quad \mathbf{w}=(5,-1,2)$$
Short Answer
Expert verified
The scalar triple product is -110.
Step by step solution
01
Understand the Definitions
The scalar triple product \( \mathbf{u} \cdot(\mathbf{v} \times \mathbf{w}) \) is a scalar value calculated using the dot product and the cross product. \( \mathbf{v} \times \mathbf{w} \) is the cross product of vectors \( \mathbf{v} \) and \( \mathbf{w} \), and the result is a vector. The dot product \( \mathbf{u} \cdot(\mathbf{v} \times \mathbf{w}) \) will finally produce a scalar value.
02
Compute \( \mathbf{v} \times \mathbf{w} \)
To find the cross product \( \mathbf{v} \times \mathbf{w} \), use the determinant of a 3x3 matrix. The formula for the cross product is:\[\mathbf{v} \times \mathbf{w} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 2 & 4 & 3 \ 5 & -1 & 2 \end{vmatrix}\]This can be expanded to:\[= \hat{i}(4 \cdot 2 - 3 \cdot (-1)) - \hat{j}(2 \cdot 2 - 3 \cdot 5) + \hat{k}(2 \cdot (-1) - 4 \cdot 5)\]\[= \hat{i}(8 + 3) - \hat{j}(4 - 15) + \hat{k}(-2 - 20)\]\[= 11\hat{i} + 11\hat{j} - 22\hat{k}\]Thus, \( \mathbf{v} \times \mathbf{w} = (11, 11, -22) \).
03
Compute \( \mathbf{u} \cdot (\mathbf{v} \times \mathbf{w}) \)
Now, compute the dot product of \( \mathbf{u} \) and the result from the previous step, \( (11, 11, -22) \):\[\mathbf{u} \cdot (\mathbf{v} \times \mathbf{w}) = (3, -1, 6) \cdot (11, 11, -22)\]Using the dot product formula \((a_1, a_2, a_3) \cdot (b_1, b_2, b_3) = a_1 b_1 + a_2 b_2 + a_3 b_3\), we calculate:\[= 3 \cdot 11 + (-1) \cdot 11 + 6 \cdot (-22)\]\[= 33 - 11 - 132\]\[= -110\]So, the scalar triple product is \(-110\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product is a fundamental vector operation used to find a vector perpendicular to two given vectors in three-dimensional space. It is denoted by the mathematical symbol **\( \times \)**. The operation involves two vectors, let's say \( \mathbf{v} \) and \( \mathbf{w} \), and results in a new vector, represented as \( \mathbf{v} \times \mathbf{w} \). This new vector is orthogonal (at a right angle) to both original vectors.
- To compute the cross product, consider a 3x3 matrix where the first row consists of the unit vectors \( \hat{i}, \hat{j}, \hat{k} \), and the second and third rows are the components of \( \mathbf{v} \) and \( \mathbf{w} \) respectively.
- The result of the cross product is obtained by calculating the determinant of this matrix.
Dot Product
The dot product is a scalar result obtained from two vectors. While the cross product results in a vector, the dot product results in a single number. If you have two vectors, say \( \mathbf{u} = (u_1, u_2, u_3) \) and \( \mathbf{v} = (v_1, v_2, v_3) \), the dot product is calculated using the formula:
- \( \mathbf{u} \cdot \mathbf{v} = u_1 v_1 + u_2 v_2 + u_3 v_3 \)
Vector Operations
Vector operations like the cross and dot products are essential tools in understanding and manipulating vectors in 3D space.
- Vector operations allow us to compute areas, volumes, and project vectors onto other vectors.
- These operations are integral in fields ranging from engineering to computer graphics and physics.
3D Vectors
3D vectors are objects defined in three-dimensional space using three components, which can represent various physical quantities like velocity, force, or position. In mathematics and physics, these vectors are typically expressed as \( \mathbf{a} = (a_1, a_2, a_3) \), where each component reflects a magnitude along the x, y, and z axes respectively.These vectors are essential for:
- Describing points in space and computing distances between them.
- Calculating direction and magnitude, making them vital in navigation and pathfinding algorithms.
- Applying transformations and rotations in 3D modeling and computer graphics.