Chapter 3: Problem 11
Find a point-normal form of the equation of the plane passing through \(P\) and having \(\mathbf{n}\) as a normal. $$P(2,0,0) ; \mathbf{n}=(0,0,2)$$
Short Answer
Expert verified
The equation of the plane is \(z = 0\).
Step by step solution
01
Understand the Point-Normal Form Equation
The point-normal form of the equation of a plane is given as \(oldsymbol{n} \cdot (\boldsymbol{r} - \boldsymbol{r_0}) = 0\), where \(\boldsymbol{n}\) is the normal vector, \(\boldsymbol{r}\) is a general point \((x, y, z)\) on the plane, and \(\boldsymbol{r_0}\) is a given point on the plane \((x_0, y_0, z_0)\).
02
Substitute the Normal Vector and Point
Given \(P(2, 0, 0)\) as the point \(\boldsymbol{r_0}\) and \(\boldsymbol{n} = (0, 0, 2)\), we substitute these into the equation. So, \(\boldsymbol{n} \cdot ((x, y, z) - (2, 0, 0)) = 0\).
03
Simplify the Equation Using the Dot Product
Calculate the dot product \(0(x-2) + 0(y-0) + 2(z-0) = 0\). This simplifies to \(2(z - 0) = 0\).
04
Final Equation of the Plane
The simplified equation from the dot product is \(2z = 0\). This indicates that \(z = 0\) is the equation of the plane.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of a Plane
The equation of a plane in three-dimensional space is a mathematical expression that describes all the points lying on that plane. There are several standardized forms to express this, but one common form is the **point-normal form**. This form is particularly handy when you know any point that lies on the plane, and a vector that is perpendicular, or normal, to the plane.
The point-normal form is given by the equation:
The point-normal form is given by the equation:
- \( \mathbf{n} \cdot (\mathbf{r} - \mathbf{r_0}) = 0 \)
- \( \mathbf{n} \) is the normal vector to the plane.
- \( \mathbf{r} = (x, y, z) \) is a generic point on the plane.
- \( \mathbf{r_0} = (x_0, y_0, z_0) \) is a specific given point on the plane.
Normal Vector
A normal vector is a crucial element in defining planes and surfaces in mathematics. It acts like an arrow sticking directly out or into the surface, pointing in a direction that is perpendicular to the plane.
In the context of the point-normal form of the equation of a plane, the normal vector \( \mathbf{n} \) is key to influencing the orientation of the plane.
In the context of the point-normal form of the equation of a plane, the normal vector \( \mathbf{n} \) is key to influencing the orientation of the plane.
- **Magnitude and Direction**: Although any multiple of a normal vector can also be a normal (because direction matters, not length), typically a single, simplest version is used for calculations.
- **Perpendicularly**: By definition, the normal vector is perpendicular to every vector that lies within the plane.
- **Components**: It is expressed in terms of its components, \( (a, b, c) \), in three-dimensional space, which influences how the plane tilts or aligns with the axes.
Dot Product
The dot product is a fundamental operation in vector mathematics. It takes two vectors and produces a scalar, reflecting the degree to which the two vectors align with each other.
In the context of plane equations, the dot product plays a pivotal role:
In the context of plane equations, the dot product plays a pivotal role:
- **Perpendicularity Determination**: For the point-normal form equation \( \mathbf{n} \cdot (\mathbf{r} - \mathbf{r_0}) = 0 \), the dot product equals zero when \( \mathbf{n} \) is perpendicular to \( (\mathbf{r} - \mathbf{r_0}) \).
- **Simplifying the Equation**: This means that for any point \( \mathbf{r} \) on the plane, the vector from \( \mathbf{r_0} \) to \( \mathbf{r} \) is orthogonal, assuring it lies on the plane.
- **Computational Steps**: Calculating \( \mathbf{n} \cdot \mathbf{v} \) translates to \( n_1v_1 + n_2v_2 + n_3v_3 \). Substituting values simplifies the plane's equation, as seen in the original solution steps.