Chapter 1: Problem 28
Find a diagonal matrix \(A\) that satisfies the given condition. $$A^{-2}=\left[\begin{array}{lll} 9 & 0 & 0 \\ 0 & 4 & 0 \\ 0 & 0 & 1 \end{array}\right]$$
Short Answer
Expert verified
Matrix \( A \) is \( \begin{bmatrix} \frac{1}{3} & 0 & 0 \\ 0 & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{bmatrix} \).
Step by step solution
01
Understand the Problem
We need to find a diagonal matrix \( A \) such that \( A^{-2} \) equals a given matrix. A diagonal matrix \( A \) is one where non-diagonal elements are zero, and only diagonal elements are non-zero.
02
Find Square Roots of Diagonal Elements
Given \( A^{-2} \), the diagonal elements are 9, 4, and 1. Notice that if \( A^{-2} \cdot A^{-2} = A^{-4} \), the diagonal elements should be the square roots of the given elements such that when squared twice, they give the original elements. Thus, find \( \sqrt{9} = 3 \), \( \sqrt{4} = 2 \), \( \sqrt{1} = 1 \).
03
Construct Matrix \( A \)
Now construct the matrix \( A \) using the square roots found in the previous step. The diagonal entries of \( A \) should be 1/3, 1/2, and 1, since these are the inverses of the numbers obtained from finding the square root, and \( A^{-2} \) will multiply these values twice.
04
Verify the Solution
Check by squaring \( A \) and taking its inverse twice to confirm that it results in the given matrix. Calculate \( A = \begin{bmatrix} \frac{1}{3} & 0 & 0 \ 0 & \frac{1}{2} & 0 \ 0 & 0 & 1 \end{bmatrix} \). \( (A^{-1})^2 = \begin{bmatrix} 9 & 0 & 0 \ 0 & 4 & 0 \ 0 & 0 & 1 \end{bmatrix} \).
05
Conclusion
Thus, the matrix \( A \) is \( \begin{bmatrix} \frac{1}{3} & 0 & 0 \ 0 & \frac{1}{2} & 0 \ 0 & 0 & 1 \end{bmatrix} \). This matrix satisfies the condition \( A^{-2} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Matrix Inversion
Matrix inversion is an essential concept in linear algebra. It involves finding a matrix that, when multiplied by the original matrix, produces the identity matrix. The identity matrix has 1s on the diagonal and 0s elsewhere, similar to the number 1 in multiplication. If a matrix \( A \) has an inverse, it is denoted as \( A^{-1} \). However, not every matrix has an inverse. Only square matrices, where the number of rows and columns are equal, are considered for inversion, and even then, the matrix must be 'non-singular,' meaning it has a non-zero determinant for an inverse to exist.
The process of finding the inverse of a diagonal matrix, like the one mentioned in the exercise, is straightforward. For a diagonal matrix \( D \) with elements \( d_1, d_2, \ldots, d_n \) on the diagonal, the inverse is simply a diagonal matrix where each diagonal element is \( \frac{1}{d_i} \).
The process of finding the inverse of a diagonal matrix, like the one mentioned in the exercise, is straightforward. For a diagonal matrix \( D \) with elements \( d_1, d_2, \ldots, d_n \) on the diagonal, the inverse is simply a diagonal matrix where each diagonal element is \( \frac{1}{d_i} \).
- Find the diagonal elements of the matrix.
- Take reciprocal of each diagonal element for the inverse.
- Keep non-diagonal elements as zero.
Matrix Exponentiation
Matrix exponentiation is a fascinating operation with wide-ranging applications, especially in computation and theoretical mathematics. It involves raising a matrix to the power of any integer exponent. When we say \( A^2 \), we mean multiplying matrix \( A \) by itself, similar to how numbers are squared. For diagonal matrices, this process is particularly efficient.
Imagine you have a diagonal matrix \( D \) and you'd like to find \( D^2 \). You simply square each of the diagonal elements of \( D \). For example, if \( D \) has diagonal elements \( 3, 2, 1 \), \( D^2 \) will have diagonal elements \( 9, 4, 1 \), because \( 3^2 = 9, 2^2 = 4, \) and \( 1^2 = 1 \).
Imagine you have a diagonal matrix \( D \) and you'd like to find \( D^2 \). You simply square each of the diagonal elements of \( D \). For example, if \( D \) has diagonal elements \( 3, 2, 1 \), \( D^2 \) will have diagonal elements \( 9, 4, 1 \), because \( 3^2 = 9, 2^2 = 4, \) and \( 1^2 = 1 \).
- Exponentiation of diagonal matrices involves simple element-wise operations.
- No need to perform matrix multiplication on the non-diagonal elements, as they remain zero.
Matrix Multiplication
Matrix multiplication is another key concept in linear algebra, which involves multiplying two matrices to produce a new matrix. The process is not as intuitive as multiplying numbers, as it involves the dot product of rows and columns.
Take two matrices, say \( A \) and \( B \). For multiplication to occur, the number of columns in \( A \) must match the number of rows in \( B \). Each element of the resulting product matrix is obtained by multiplying the elements of the rows from \( A \) by the corresponding elements of columns in \( B \) and summing up these products.
Take two matrices, say \( A \) and \( B \). For multiplication to occur, the number of columns in \( A \) must match the number of rows in \( B \). Each element of the resulting product matrix is obtained by multiplying the elements of the rows from \( A \) by the corresponding elements of columns in \( B \) and summing up these products.
- Ensure matrix dimensions are compatible for multiplication.
- Each element in the resulting matrix is a dot product of a row from the first matrix and a column from the second matrix.