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Finding the Standard Matrix and the Image In Exercises \(11-22,\) (a) find the standard matrix \(A\) for the linear transformation \(T,\) (b) use \(A\) to find the image of the vector \(\mathbf{v},\) and (c) sketch the graph of \(\mathbf{v}\) and its image. \(T\) is the counterclockwise rotation of \(45^{\circ}\) in \(R^{2}\) \(\mathbf{v}=(2,2)\)

Short Answer

Expert verified
The standard matrix A for the counterclockwise rotation of \( 45^{\circ} \) in \(R^{2}\) is \( \left(\begin{array}{cc} \frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} \end{array}\right) \). The image of the vector v=(2,2) is (0, \(2\sqrt{2}\)) after a counterclockwise rotation by \(45掳\).

Step by step solution

01

Finding Standard Matrix A

For a linear transformation rotating counterclockwise by 胃 degrees in 鈩澛, the standard matrix A is structured as follows - \[ A= \left(\begin{array}{cc} \cos(胃) & -\sin(胃) \\ \sin(胃) & \cos(胃) \end{array}\right) \] Plug in the value of \(胃=45掳=\frac{蟺}{4} rad\) to the above matrix. We have, \[ A= \left(\begin{array}{cc} \cos(\frac{蟺}{4}) & -\sin(\frac{蟺}{4}) \\ \sin(\frac{蟺}{4}) & \cos(\frac{蟺}{4}) \end{array}\right) \] Simplifying the trigonometric values we get, \[ A= \left(\begin{array}{cc} \frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} \end{array}\right) \] So, the standard matrix \(A\) for the counterclockwise rotation of \( 45^{\circ} \) in \(R^{2}\) is \( \left(\begin{array}{cc} \frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} \end{array}\right) \)
02

Find the image of the vector using A

The image of the vector \(\mathbf{v}\) under the transformation \(T\) is given by multiplying the standard matrix \(A\) with the vector \(\mathbf{v}\). The multiplication is as follows: \[ \begin{array}{cc} \frac{\sqrt{2}}{2} & -\frac{\sqrt{2}}{2} \\ \frac{\sqrt{2}}{2} & \frac{\sqrt{2}}{2} \end{array}\right) \times \left(\begin{array}{c} 2 \\ 2 \end{array}\right)=\left(\begin{array}{c} 0 \\ 2\sqrt{2} \end{array}\right) \] So, the image of the vector \(\mathbf{v}\)=(2,2) after rotation by \(45掳\) counterclockwise is (0, \(2\sqrt{2}\)).
03

Sketching the vectors and their transformation

To sketch the vectors, put the tip of vector \(\mathbf{v}\) at point (2,2) and vector T(\(\mathbf{v}\)) or the image of \(\mathbf{v}\) under transformation T at point (0, \(2\sqrt{2}\)). Both the vectors will originate from the same point and the image vector will be rotated \(45掳\) counterclockwise from the original vector \(\mathbf{v}\).

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