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Use the fact that \(|c A|=c^{n}|A|\) to evaluate the determinant of the \(n \times n\) matrix. $$A=\left[\begin{array}{rrr}-3 & 6 & 9 \\\6 & 9 & 12 \\\9 & 12 & 15\end{array}\right]$$

Short Answer

Expert verified
The determinant of the given matrix is -54.

Step by step solution

01

Identify the scalar

Identify the scalar in the given matrix. Here the scalar is -3 and the matrix without this scalar looks like this: \[\begin{{bmatrix}}1 & 2 & 3\\2 & 3 & 4\\3 & 4 & 5\end{{bmatrix}}\]
02

Compute the determinant of the scaled-down matrix

Compute the determinant of the matrix obtained after scaling down by dividing each element by -3. Remember that the determinant is a special number of a square matrix. For a 3x3 matrix, it is computed as follows:\[\begin{{vmatrix}}a & b & c\\d & e & f\\g & h & i\end{{vmatrix}}\]equals to \(aei+bfg+cdh-ceg-bdi-afh\)which gives us \((1*3*5)+(2*4*3)+(3*2*1)-(3*3*1)-(2*2*5)-(1*4*3) = 2\)
03

Apply the formula for the determinant of a scaled matrix

Apply the formula for the determinant of a scaled matrix which is \(|cA|=c^{n}|A|\), where 'c' is the scalar, 'A' is the original matrix and 'n' is the order of the matrix. So here, -3 is the scalar 'c', 2 is the determinant of the matrix |A| and 3 is the order of the matrix 'n'. Substituting these values we get,\[|-3A| = (-3)^3 * 2 = -54\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Scalar Multiplication in Matrices
In linear algebra, scalar multiplication is a simple yet powerful process. It involves multiplying every element of a matrix by a constant, known as the scalar. This operation creates a new matrix where each element is the product of the original element and the scalar. For example, if we have a matrix \(A\) and a scalar \(c\), then the scalar multiplication \(cA\) results in a matrix where each element \(a_{ij}\) becomes \(ca_{ij}\).

Consider a practical example with the matrix:
  • \(A = \begin{bmatrix} -3 & 6 & 9 \ 6 & 9 & 12 \ 9 & 12 & 15 \end{bmatrix}\)
Identify the scalar factor; in this case, it's \(-3\). By dividing each element by this scalar, you simplify the matrix for further calculations.

Scalar multiplication doesn't change the matrix type (square, rectangular) but affects properties like determinants, discussed up next.
Matrix Determinant Formula
The determinant of a matrix is a unique number that provides key insights into the matrix properties, such as invertibility and volume scaling in transformations. For a 3x3 matrix, the determinant \(|A|\) is computed using the formula:
  • \( |A| = aei + bfg + cdh - ceg - bdi - afh \)
Each component consists of cross and dot products of matrix elements. Let's apply this to the simplified matrix:
  • \( B = \begin{bmatrix} 1 & 2 & 3 \ 2 & 3 & 4 \ 3 & 4 & 5 \end{bmatrix} \)
Calculating step by step using the formula gives us \((1*3*5) + (2*4*3) + (3*2*1) - (3*3*1) - (2*2*5) - (1*4*3) = 2\).

Thus, the determinant \(|B| = 2\). Understanding this process ensures efficient handling of more complex matrices in various mathematical applications.
Square Matrix Properties
Square matrices have an equal number of rows and columns, such as a 3x3 or 4x4 matrix, making them crucial in many mathematical areas. They possess unique properties, particularly when it comes to calculating determinants.

In our problem, we deal with a square matrix of size 3x3. Key characteristics include:
  • Determinants: Only square matrices have determinants.
  • Identity Element: The identity matrix retains its elements in operations.
  • Invertibility: Only square matrices with non-zero determinants are invertible.
When applying scalar multiplication to a square matrix, the determinant of the resulting matrix \(cA\) can be derived as \(|cA| = c^n|A|\), where \(n\) is the matrix order.

In our example, \(-3\) is the scalar, and the order \(n\) is 3, leading to \(|-3A| = (-3)^3 * 2 = -54\). Understanding these properties helps in optimizing calculations and making informed predictions in linear algebra and calculus.

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Most popular questions from this chapter

Use a software program or a graphing utility to find (a) \(|\boldsymbol{A}|\) (b) \(\left|\boldsymbol{A}^{T}\right|,(\mathbf{c})\left|\boldsymbol{A}^{2}\right|,(\mathbf{d})|\boldsymbol{2} \boldsymbol{A}|,\) and \((\mathbf{e})\left|\boldsymbol{A}^{-1}\right|\). $$A=\left[\begin{array}{rrr}3 & 1 & -2 \\\2 & -1 & 3 \\\\-3 & 1 & 2\end{array}\right]$$

Find the volume of the tetrahedron with the given vertices. $$(1,0,0),(0,1,0),(0,0,1),(1,1,1)$$

Let \(A\) and \(P\) be \(n \times n\) matrices, where \(P\) is invertible. Does \(P^{-1} A P=A ?\) IIlustrate your conclusion with appropriate examples. What can you say about the two determinants \(\left|P^{-1} A P\right|\) and \(|A| ?\)

Find the determinant of the elementary matrix. (Assume \(k \neq 0\).) $$\left[\begin{array}{lll}1 & 0 & 0 \\\0 & 1 & 0 \\\0 & k & 1\end{array}\right]$$

Guided Proof Prove Property 2 of Theorem 3.3 : When \(B\) is obtained from \(A\) by adding a multiple of a row of \(A\) to another row of \(A, \operatorname{det (B)=\operatorname{det}(A)\) Getting Started: To prove that the determinant of \(B\) is equal to the determinant of \(A,\) you need to show that their respective cofactor expansions are equal. (i) Begin by letting \(B\) be the matrix obtained by adding \(c\) times the \(j\) th row of \(A\) to the \(i\) th row of \(A\) (ii) Find the determinant of \(B\) by expanding in this ith row. (iii) Distribute and then group the terms containing a coefficient of \(c\) and those not containing a coefficient of \(c\) (iv) Show that the sum of the terms not containing a coefficient of \(c\) is the determinant of \(A,\) and the sum of the terms containing a coefficient of \(c\) is equal to \(0 .\)

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