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Prove that if \(A\) and \(B\) are idempotent and \(A B=B A,\) then \(A B\) is idempotent.

Short Answer

Expert verified
The product \(AB\) of the matrices \(A\) and \(B\) is idempotent. The key steps to this proof involved first understanding the given conditions, namely that \(A\) and \(B\) are idempotent and commuting matrices. After squaring the matrix product \(AB\) and applying the given conditions, the resulting expression was equal to \(AB\), proving idempotence.

Step by step solution

01

Understand what being idempotent and commute mean

By definition, a matrix \(M\) is idempotent if \(M^2 = M\). Commutation of \(A\) and \(B\) means \(AB = BA\). These are the given conditions in this exercise.
02

Compute the square of the product AB

We will square the matrix product \(AB\) to truly understand if it results in \(AB\). When we square the product \(AB\), we get \((AB)^2 = ABAB\). By utilizing the property of commutation, we rewrite this as \(A(AB)B = A(BA)B = A^2 B^2\).
03

Apply the idempotent property

Since \(A\) and \(B\) are both idempotent, squaring them doesn't change them. This means \(A^2 = A\) and \(B^2 = B\). Substituting this back in, we get that \(A^2 B^2 = AB\), which confirms the idempotent property of the original product \(AB\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Idempotent Matrix Proof
In linear algebra, a matrix is described as idempotent when it yields the same matrix as a result of its multiplication by itself. This is mathematically represented as \(M^2 = M\), where \(M\) is the matrix in question. The exercise provided requires proving that if matrices \(A\) and \(B\) are idempotent and commutative, meaning they fulfill the conditions \(A^2 = A\), \(B^2 = B\), and \(AB = BA\), then the product \(AB\) is also idempotent.

To understand this proof, it's crucial to first grasp the concept of matrix multiplication, where the elements of the resulting matrix are the sums of products of elements from the rows of the first matrix and the columns of the second. Now, since \(A\) and \(B\) are idempotent matrices, we can substitute \(A^2\) for \(A\) and \(B^2\) for \(B\) in the product without altering the matrices themselves. By multiplying \(A\) and \(B\) given they commute, we demonstrate that \(AB\) multiplied by itself indeed equals \(AB\), thus proving its idempotency. This is a foundational proof in linear algebra that underlines the importance of matrix properties and operations.
Matrix Commutation and Its Role in Proofs
The commutation of two matrices is a concept in linear algebra that refers to the ability for matrices to be multiplied in any order without affecting the result. This is to say, for matrices \(A\) and \(B\), if \(AB = BA\), then the matrices are said to commute. In the context of the given exercise, \(AB\) and \(BA\) are interchangeable due to the commutation property.

This property becomes especially useful when addressing more complex matrix operations and proofs, as it allows the rearrangement of terms which can simplify the calculations and lead to clearer demonstrations. For example, in proving an idempotent matrix, commutation ensures that squaring the product \(AB\) results in a sequence that can be rearranged as \(A^2 B^2\), which simplifies the proof significantly. Understanding matrix commutation is imperative for students as it frequently arises in theoretical and applied mathematics.
Essential Matrix Operations in Linear Algebra
Matrix operations form the backbone of linear algebra and are indispensable in solving a slew of problems across mathematics and applied sciences. Key operations include matrix addition, scalar multiplication, matrix multiplication, and the calculation of determinants and inverses, if they exist. Each of these operations follows a specific set of rules that govern the outcome of these operations.

For instance, matrix multiplication is not commutative in general, but in the case of the exercise above, the commutation of \(A\) and \(B\) provides an exception to the rule, playing a critical role in the proof. Matrix operations often involve properties such as distributivity, associativity, and in specific cases, commutativity. When dealing with idempotent matrices, knowing that \(A^2 = A\) simplifies many operations. Students are encouraged to familiarize themselves with these matrix operations, understand the rules that govern them, and practice applying these rules in various contexts to achieve mastery.

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Most popular questions from this chapter

Wildlife \(A\) wildlife management team studied the reproduction rates of deer in three tracts of a wildlife preserve. The team recorded the number of females \(x\) in each tract and the percent of females \(y\) in each tract that had offspring the following year. The table shows the results. $$ \begin{array}{l|ccc} \hline \text {Number, }, x & 100 & 120 & 140 \\ \text {Percent, } y & 75 & 68 & 55 \\ \hline \end{array} $$ (a) Find the least squares regression line for the data. (b) Use a graphing utility to graph the model and the data in the same viewing window. (c) Use the model to create a table of estimated values for y. Compare the estimated values with the actual data. (d) Use the model to estimate the percent of females that had offspring when there were 170 females. (e) Use the model to estimate the number of females when \(40 \%\) of the females had offspring.

Prove that if \(A\) is row-equivalent to \(B,\) then \(B\) is row-equivalent to \(A\).

Prove that if \(A\) is row-equivalent to \(B\) and \(B\) is row-equivalent to \(C,\) then \(A\) is row-equivalent to \(C\). Getting Started: To prove that \(A\) is row-equivalent to \(C\) you have to find elementary matrices \(E_{1}, E_{2}, \ldots, E_{k}\) such that \(A=E_{k} \cdot \cdot \cdot E_{2} E_{1} C\) (i) Begin by observing that \(A\) is row-equivalent to \(B\) and \(B\) is row- equivalent to \(C\). (ii) This means that there exist elementary matrices \(F_{1}, F_{2}, \ldots, F_{n}\) and \(G_{1}, G_{2}, \ldots, G_{m}\) such that \(\vec{A}=\vec{F}_{n} \cdot \cdot \cdot F_{2} F_{1} B\) and \(B=G_{m} \cdot \cdot \cdot G_{2} G_{1} C\)(iii) Combine the matrix equations from step (ii).

Perform the operations, given \(c=-2\) and \(A=\left[\begin{array}{rrr}1 & 2 & 3 \\\ 0 & 1 & -1\end{array}\right], B=\left[\begin{array}{rr}1 & 3 \\ -1 & 2\end{array}\right], C=\left[\begin{array}{rr}0 & 1 \\ -1 & 0\end{array}\right]\). $$c B(C+C)$$.

Verify that \((A B)^{T}=B^{T} A^{T}\). $$ A=\left[\begin{array}{rrr}2 & 1 & -1 \\\0 & 1 & 3 \\\4 & 0 & 2\end{array}\right] \text { and } B=\left[\begin{array}{rrr}1 & 0 & -1 \\ 2 & 1 & -2 \\\0 & 1 & 3\end{array}\right] $$

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