Chapter 6: Problem 28
Let \(T: R^{3} \rightarrow R^{3}\) be a linear transformation such that \(T(1,1,1)=(2,0,-1), T(0,-1,2)=(-3,2,-1),\) and \(T(1,0,1)=(1,1,0) .\) Find $$T(0,2,-1)$$
Short Answer
Expert verified
The transformation \(T(0,2,-1)=(-2, -1, -2)\)
Step by step solution
01
Create a basis for \(R^{3}\)
Firstly, change the given vectors into a basis for \(R^{3}\) using the given transformations. Let's say \(x=(1,1,1)\), \(y=(0,-1,2)\), and \(z=(1,0,1)\) are the basis vectors. Hence, we have, \(T(x)=(2,0,-1)\), \(T(y)=(-3,2,-1)\), and \(T(z)=(1,1,0)\).
02
Express the desired vector as a linear combination of basis vectors
We have the vector \(v=(0,2,-1)\) to find a transformation, let's write it as a linear combination of basis vectors \(x\), \(y\), and \(z\), i.e, \(v=a.x+b.y+c.z\). Solving, we get \(a=1\), \(b=-1\), and \(c=-1\).
03
Apply linear transformations
A linear transformation on a combination of vectors is equivalent to a combination of their transformed counterparts. In other words, Turing to the definition of linear transformations, \(T(a.x +b.y +c.z) = a.T(x) + b.T(y) + c.T(z)\). Equating the earlier obtained values \(a=1\), \(b=-1\), and \(c=-1\), we get \(T(v)= T(x) - T(y) - T(z)\).
04
Compute the result
Finally substituting \(T(x)=(2,0,-1)\), \(T(y)=(-3,2,-1)\), and \(T(z)=(1,1,0)\) in \(T(v)= T(x) - T(y) - T(z)\), we get \(T(v)= (-2, -1, -2)\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Basis Vectors
To understand the process of finding the transformation of a vector in a different space, we first need to talk about basis vectors. Imagine a coordinate system as a unique type of map. In three-dimensional space, any point can be described using three specific directions. These directions are known as basis vectors. For example, the vectors \((1,1,1)\), \((0,-1,2)\), and \((1,0,1)\) can serve as a set of basis vectors for \(\mathbb{R}^3\).
- Each basis vector is independent of the others.
- Together, they can represent any vector in the space by taking combinations of these directions.
Linear Combination
Once we have our basis vectors, we can express any vector as a linear combination of these basis vectors. Simply put, a linear combination involves adding together multiple vectors, each multiplied by a scalar (a constant number). For example, suppose you have a vector \((0,2,-1)\) that you want to express using the basis vectors \((1,1,1), (0,-1,2), (1,0,1)\). You could find scalars \(a\), \(b\), and \(c\) such that:
\[(0, 2, -1) = a \times (1, 1, 1) + b \times (0, -1, 2) + c \times (1, 0, 1)\]
\[(0, 2, -1) = a \times (1, 1, 1) + b \times (0, -1, 2) + c \times (1, 0, 1)\]
- This means identifying how much of each basis vector contributes to the vector \((0,2,-1)\).
- In our solution, these turned out to be \(a=1\), \(b=-1\), and \(c=-1\).
Vector Transformation
Now, let's delve into how vector transformation works with linear transformations. A linear transformation is a function that maps vectors to other vectors in a consistent manner, meaning the transformation respects vector addition and scalar multiplication. For our exercise, the transformation is represented by \(T((x,y,z))\), where we aim to find the image of a given vector under this transformation.
The rule of thumb with transformations is that transforming a combination of vectors yields a combination of their transformed images. If you have equations for \(T(x)\), \(T(y)\), and \(T(z)\), you can then find \(T(v)\), where \(v\) is a vector expressed as a linear combination of the basis vectors:
\[T(v) = a \times T(x) + b \times T(y) + c \times T(z)\]
The rule of thumb with transformations is that transforming a combination of vectors yields a combination of their transformed images. If you have equations for \(T(x)\), \(T(y)\), and \(T(z)\), you can then find \(T(v)\), where \(v\) is a vector expressed as a linear combination of the basis vectors:
\[T(v) = a \times T(x) + b \times T(y) + c \times T(z)\]
- Each transformation \(T(x)\), \(T(y)\), and \(T(z)\) reflects how each basis vector is transformed.
- In our case, this culminates in determining \(T(0,2,-1)\) by substituting our values of \(a\), \(b\), and \(c\).