Chapter 6: Problem 21
Let \(A\) be an \(n \times n\) matrix such that \(A^{2}=O .\) Prove that if \(B\) is similar to \(A,\) then \(B^{2}=O\).
Short Answer
Expert verified
\(\)Hence, if B is similar to A, and \(A^2 = O\), then \(B^2 = O\).
Step by step solution
01
Understand the Given Conditions
Here, A is an n×n matrix such that \(A^2 = O\). This means when the matrix A is multiplied by itself, the result is the null matrix. B is similar to A which means there exists an invertible matrix P such that \(B = P^{-1}AP\).
02
Substitute the Similarity Relation in B
What we need to prove is \(B^2 = O\). We first express B in terms of A and P, then we find \(B^2\). Let's substitute \(B = P^{-1}AP\) into the equation for \(B^2\). So, \(B^2 = (P^{-1}AP)^2\).
03
Solve the Equation
We can expand this as: \(B^2 = (P^{-1}AP)(P^{-1}AP)\). Using the associative property of matrix multiplication, we get: \(B^2 = P^{-1}A(PP^{-1})AP = P^{-1}AAP = P^{-1}A^2P\).
04
Substitute Given Condition
It is given that \(A^2 = O\). So substitute \(A^2 = O\) into the equation, we get \(B^2 = P^{-1}OP = O\).\n
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nilpotent Matrix
A **nilpotent matrix** is a type of square matrix that, when raised to a certain power, results in a matrix made entirely of zeros. This concept is integral in linear algebra as it provides insights into the structure and behavior of matrices. For a square matrix \( A \), if \( A^k = O \) where \( O \) is a zero matrix and \( k \) is a positive integer, then \( A \) is considered nilpotent. In the given exercise, we know that \( A^2 = O \), meaning \( A \) is nilpotent of index 2.
Important properties of nilpotent matrices include:
- **Trace**: The trace of any nilpotent matrix is always zero, as the sum of the eigenvalues of the matrix is zero.
- **Eigenvalues**: All eigenvalues of a nilpotent matrix are zero. This implies that the determinant of a nilpotent matrix is also zero.
Understanding the properties of nilpotent matrices helps us in various mathematical fields, including differential equations and dynamical systems, where such matrices often play a crucial role.
Important properties of nilpotent matrices include:
- **Trace**: The trace of any nilpotent matrix is always zero, as the sum of the eigenvalues of the matrix is zero.
- **Eigenvalues**: All eigenvalues of a nilpotent matrix are zero. This implies that the determinant of a nilpotent matrix is also zero.
Understanding the properties of nilpotent matrices helps us in various mathematical fields, including differential equations and dynamical systems, where such matrices often play a crucial role.
Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra, used to combine two matrices into one. It is defined for two matrices, say \( A \) and \( B \), when the number of columns in \( A \) matches the number of rows in \( B \). The result is a new matrix whose dimensions are determined by the number of rows in \( A \) and the number of columns in \( B \).
Some essential points to remember about matrix multiplication include:
Some essential points to remember about matrix multiplication include:
- Non-Commutativity: Matrix multiplication is generally not commutative, meaning \( AB eq BA \).
- Associative Property: It is associative, \((AB)C = A(BC)\).
- Distributive Property: It obeys the distributive law, \( A(B + C) = AB + AC \).
Invertible Matrix
An **invertible matrix** is a square matrix that possesses an inverse such that if \( A \) is invertible, there exists a matrix \( A^{-1} \) for which \( AA^{-1} = A^{-1}A = I \), where \( I \) is the identity matrix. The existence of an inverse is fundamental for solving systems of linear equations and understanding matrix similarity.
Key properties of invertible matrices include:
Key properties of invertible matrices include:
- Non-zero Determinant: A matrix is invertible if and only if its determinant is not zero.
- Unique Solution: When a matrix \( A \) is invertible, any equation of the form \( Ax = b \) has a unique solution \( x = A^{-1}b \).
- Consistency in System of Equations: Invertibility ensures the system is consistent and solvable for any vector \( b \).