/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 Let \(B=\left\\{1, x, x^{2}\righ... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(B=\left\\{1, x, x^{2}\right\\}\) be a basis for \(P_{2}\) with the inner product \(\langle p, q\rangle=\int_{-1}^{1} p(x) q(x) d x\). Complete Example 9 by verifying the indicated inner products. $$\left\langle x^{2}, 1\right\rangle=\frac{2}{3}$$

Short Answer

Expert verified
The calculated value for the inner product \(\langle x^{2}, 1\rangle\) is indeed \(\frac{2}{3}\), which confirms the assertion in the problem statement.

Step by step solution

01

Understanding the definition of inner product

The inner product between two functions is defined as \(\langle p, q\rangle=\int_{-1}^{1} p(x) q(x) d x\). For this exercise, \(p(x) = x^{2}\) and \(q(x) = 1\). So we need to compute the integral of \(x^{2} * 1\) from \(-1\) to \(1\)
02

Calculate the integral

The integral to compute is \(\int_{-1}^{1} x^{2} * 1 dx = \int_{-1}^{1} x^{2} dx\). The antiderivative of \(x^2\) is \(\frac{x^3}{3}\). After applying the fundamental theorem of calculus we get \(\frac{x^{3}}{3}|_{-1}^{1}\)
03

Evaluate at the limits

After applying the limits we get \(\frac{(1)^3}{3} - \frac{(-1)^3}{3} = \frac{1}{3} - \left(- \frac{1}{3} \right) = \frac{2}{3}\)
04

Compare with the given value

The calculated inner product is indeed equal to the provided value: \(\langle x^{2}, 1\rangle = \frac{2}{3}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Basis
When we talk about the polynomial basis in the context of the vector space of polynomials, we refer to a set of polynomials that can express any polynomial in that space as a linear combination of these basis elements. In the case of the exercise, the basis is given as \( B = \{1, x, x^2\} \).

This basis is particularly relevant for polynomials of degree at most 2, known as the \( P_2 \) polynomial space.

  • The basis polynomial \( 1 \) represents the constant term of any polynomial.
  • The basis polynomial \( x \) accounts for the linear component.
  • The polynomial \( x^2 \) contributes to the quadratic (or degree 2) aspect.
These basis functions are orthogonal with respect to certain inner products, making them valuable for many computations, as shown in our exercise. Knowing the basis helps us determine exactly how any polynomial in \( P_2 \) is constructed.
Integration in Linear Algebra
In linear algebra, the concept of an inner product not only applies to vectors but also to function spaces, like the space of polynomials. Here, integration plays a key role in defining the inner product for continuous functions over a specified interval.

For our exercise, the inner product is defined as:\[\langle p, q \rangle = \int_{-1}^{1} p(x) q(x) \, dx\]This means to compute the inner product between two functions, we calculate the integral of their product over the interval [−1, 1].

Integration transforms the multiplication of functions into a scalar number, representing their "overlap" in the context of the space. This particular inner product comes from the area concept in calculus, thus integrating interpretations from both linear algebra and calculus to give us meaningful results like the exercise’s \( \left\langle x^2 , 1 \right\rangle = \frac{2}{3} \).
P2 Polynomial Space
The \( P_2 \) polynomial space consists of all polynomials of degree at most 2. In other words, any polynomial that lives in \( P_2 \) can be expressed in the form \( a_0 + a_1x + a_2x^2 \) where \( a_0, a_1, \text{and } a_2 \) are constants.

In context of the exercise, the polynomial basis \( \{1, x, x^2\} \) corresponds perfectly with this space.

Key aspects of the \( P_2 \) space include:
  • It has precisely three dimensions corresponding to the three coefficients \( a_0, a_1, \text{and } a_2 \).
  • Any polynomial in \( P_2 \) is uniquely determined by these three coefficients when expressed in the basis \( \{1, x, x^2\} \).
  • This space serves as a fundamental building block for more complex polynomial spaces.
Understanding \( P_2 \) is essential for tasks like polynomial interpolation, curve fitting, and solving differential equations, as it provides a foundation for approximating functions with relatively simple expressions.

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Most popular questions from this chapter

Determine whether each statement is true or false. If a statement is true, give a reason or cite an appropriate statement from the text. If a statement is false, provide an example that shows the statement is not true in all cases or cite an appropriate statement from the text. (a) If \(S_{1}\) and \(S_{2}\) are orthogonal subspaces of \(R^{n},\) then their intersection is an empty set. (b) If each vector \(\mathbf{v} \in R^{n}\) can be uniquely written as a sum of a vector \(\mathbf{s}_{1}\) from \(S_{1}\) and a vector \(\mathbf{s}_{2}\) from \(S_{2},\) then \(R^{n}\) is called the direct sum of \(S_{1}\) and \(S_{2}\) (c) The solution of the least squares problem consists essentially of solving the normal equations - that is, solving the \(n \times n\) linear system of equations \(A^{T} A \mathbf{x}=A^{T} \mathbf{b}\).

(a) find the linear least squares approximating function \(g\) for the function \(f\) and \((b)\) use a graphing utility to graph \(f\) and \(g\). $$f(x)=e^{2 x}, \quad 0 \leq x \leq 1$$

The table shows the annual sales (in millions of dollars) for Advanced Auto Parts and Auto Zone for 2000 through 2007 Find an appropriate regression line, quadratic regression polynomial, or cubic regression polynomial for each company. Then use the model to predict sales for the year 2010 . Let \(t\) represent the year, with \(t=0\) corresponding to 2000 . (Source: Advanced Auto Parts and Auto Zone)$$\begin{array}{l|cccc} \hline & & & & \\ \text {Year} & 2000 & 2001 & 2002 & 2003 \\ \hline \text {Advanced} & 2288 & 2518 & 3288 & 3494 \\ \text {Auto Parts Sales, } y & & & & \\ \text {Auto Zone Sales, } y & 4483 & 4818 & 5326 & 5457 \\ \hline \end{array}$$ $$\begin{array}{l|llll} \hline \text {Year} & 2004 & 2005 & 2006 & 2007 \\ \hline \text {Advanced} & 3770 & 4265 & 4625 & 5050 \\ \text {Auto Parts Sales, } y & & & & \\ \text {Auto Zone Sales, } y & 5637 & 5711 & 5948 & 6230 \\ \hline \end{array}$$

Find the Fourier approximation of the specified order for the function on the interval \([0,2 \pi]\). \(f(x)=1+x, \quad\) fourth order

(a) find the linear least squares approximating function \(g\) for the function \(f\) and \((b)\) use a graphing utility to graph \(f\) and \(g\). $$f(x)=x^{2}, \quad 0 \leq x \leq 1$$

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